BSEB Class 10 Maths Chapter 1 Real Numbers Ex 1.3 Textbook Solutions PDF: Download Bihar Board STD 10th Maths Chapter 1 Real Numbers Ex 1.3 Book Answers |
Bihar Board Class 10th Maths Chapter 1 Real Numbers Ex 1.3 Textbooks Solutions PDF
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Board | BSEB |
Materials | Textbook Solutions/Guide |
Format | DOC/PDF |
Class | 10th |
Subject | Maths Chapter 1 Real Numbers Ex 1.3 |
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BSEB Class 10th Maths Chapter 1 Real Numbers Ex 1.3 Textbooks Solutions with Answer PDF Download
Find below the list of all BSEB Class 10th Maths Chapter 1 Real Numbers Ex 1.3 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:BSEB Bihar Board Class 10th Maths Solutions Chapter 1 Real Numbers Ex 1.3
Question 1.
Prove that 5‾√ is irrational. [CBSE, Delhi 2009]
Solution:
Let us assume, to the contrary, that 5‾√ is rational.
Squaring on both sides, we get
5 = 𝑎2𝑏2 or 5b2 = a2 ………………. (1)
This shows that a2 is divisible by 5.
It follows that a is divisible by 5. …………………. (2)
So, a = 5m for some integer m.
Substituting a = 5m in (1), we get
5b2 = (5m)2 = 25m2
or b2 = 5m2 or b2 is divisible by 5
and hence b is divisible by 5.
From (2) and (3), we can conclude that 5 is a common factor of both a and b.
But this contradicts our supposition that a and b are coprime.
Hence, 5‾√ is irrational.
Question 2.
Prove that 3 + 25‾√ is irrational.
Solution:
Let us assume, to the contrary, that 3 + 25‾√ is a rational number.
Now, let 3 + 25‾√ = 𝑎𝑏, where a and b are coprime and b ≠ 0.
So, 25‾√ = 𝑎𝑏 – 3 or 5‾√ = 𝑎2𝑏 – 32
Since a and b are integers, therefore
𝑎2𝑏 – 32 is a rational number.
∴ 5‾√ is an irrational number.
But 5‾√ is an irrational number.
This shows that our assumption is incorrect.
So, 3 + 25‾√ is an irrational number.
Question 3.
Prove that the following are irrationals:
- 12√
- 75‾√
- 6 + 2‾√
Solution:
1. Let us assume, to the contrary, that 12√ is rational.
That is, we can find co-prime integers p and q (≠ 0) such that
Since p and q are integers, 2𝑝𝑞 is rational, and so 2‾√ is rational.
But this contradicts the fact that 2‾√ is irrational.
So, we conclude that 12√ is irrational.
2. Let us assume, to the contrary, that 75‾√ is rational.
That is, we can find co-prime integers p and q (≠ 0) such that 75‾√ = 𝑝𝑞.
So, 5‾√ = 𝑝7𝑞.
Since p and q are integers, 𝑝7𝑞 is rational and so is 5‾√.
But this contradicts the fact that 5‾√ is irrational.
So, we conclude that 75‾√ is irrational.
3. Let us assume, to the contrary, that 6 + 2‾√ is rational.
That is, we can find integers p and q (≠ 0) such that
6 + 2‾√ = 𝑝𝑞 or 6 – 𝑝𝑞 = 2‾√
or 2‾√ = 6 – 𝑝𝑞
Since p and q are integers, we get 6 – 𝑝𝑞 is rational, and so 2‾√ is rational.
But this contradicts the fact that 2‾√ is irrational.
So, we conclude that 6 + 2‾√ is irrational.
BSEB Textbook Solutions PDF for Class 10th
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