BSEB Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.3 Textbook Solutions PDF: Download Bihar Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Book Answers ~ HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

BSEB Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.3 Textbook Solutions PDF: Download Bihar Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Book Answers

BSEB Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Textbooks Solutions and answers for students are now available in pdf format. Bihar Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Book answers and solutions are one of the most important study materials for any student. The Bihar Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 books are published by the Bihar Board Publishers. These Bihar Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 textbooks are prepared by a group of expert faculty members. Students can download these BSEB STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 book solutions pdf online from this page.

Bihar Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Textbooks Solutions PDF

Bihar Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Books Solutions with Answers are prepared and published by the Bihar Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of BSEB Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Books Answers Solutions, then you are in the right place. Here is a complete hub of Bihar Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Bihar Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Textbooks. These Bihar Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Bihar Board.

Bihar Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Books Solutions

Board	BSEB
Materials	Textbook Solutions/Guide
Format	DOC/PDF
Class	10th
Subject	Maths Chapter 7 Coordinate Geometry Ex 7.3
Chapters	All
Provider	Hsslive

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BSEB Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Textbooks Solutions with Answer PDF Download

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BSEB Bihar Board Class 10th Maths Solutions Chapter 7 Coordinate Geometry Ex 7.3

Question 1.
Find the area of the triangle whose vertices are :
(i) (2, 3), (- 1, 0), (2, – 4)
(ii) (- 5, – 1), (3, – 5), (5, 2)
Solution:
(i) Let A = (x₁, y₁) = (2, 3), B = (x₂, y₂) = (- 1, 0) and C = (x₃, y₃) = (2, – 4).

(ii) Let A = (x₁, y₁) = (- 5, – 1), B = (x₂, y₂) = (3, – 5) and C = (x₃, y₃) = (5, 2).

Question 2.
In each of the following, find the value of ‘k\ for which the points are collinear :
(i) (7, – 2), (5, 1), (3, k)
(ii) (8, 1), (k, – 4), (2, – 5)
Solution:
(i) Let the given points be A = (x₁, y₁) = (7, – 2), B = (x₂, y₂) = (5, 1) and C = (x₃, y₃) = (3, k). These points lie on a line if
Area (∆ ABC) = O
i.e., x₁(y₂ – y₃) + x₂(y₃ – y₁) + x₃(y₁ – y₂) = 0
or 7(1 – k) + 5(k + 2) + 3(- 2 – 1) = 0
or 7 – 7k + 5k + 10 – 9 = 0
or 8 – 2k = 0
2k = 8 i.e., k = 4
Hence, the given points are collinear for k = 4

(ii) Let the given points be A = (x₁, y₁) = (8, 1), B = (x₂, y₂) = (k, – 4) and C = (x₃, y₃) = (2, – 5).
If the given points are collinear, then
x₁(y₂ – y₃) + x₂(y₃ – y₁) + x₃(y₁ – y₂) = 0= 0
So, 8(- 4 + 5) + k(- 5 – 1) + 2(1 + 4) = 0
or 8 – 6k + 10 = 0
or – 6k = – 18
i.e., k – 3
Hence, the given points are collinear for k = 3.

Question 3.
Find the area of the triangle formed by joining the mid-points of the sides of the triangle whose vertices are (0, – 1), (2, 1) and (0, 3). Find the ratio of this area to the area of the given triangle.
Solution:
Let A = (x₁, y₁) = (0, – 1), B = (x₂, y₂) = (2, 1) and C = (x₃, y₃) = (0, 3) be the vertices of ∆ ABC.

Let P (0+22,3+12) i.e., (1, 2),
Q (2+02,1−12) i.e., (1, 0) and ,
R (0+02,3−12) i.e. (0, 1) be the
vertices of A PQR formed by joining the mid-points of the sides of A ABC.
Now,

Ratio of the area (∆ PQR) to the area (∆ ABC) = 1 : 4.

Question 4.
Find the area of the quadrilateral whose vertices, taken in order, are (- 4, – 2), (- 3, – 5), (3, – 2) and (2, 3).
Solution:
Let A(- 4, – 2), B(- 3, – 5), C(3, – 2) and D(2, 3) be the vertices of the quadrilateral ABCD.
Area of quadrilateral ABCD = Area of ∆ ABC + Area of ∆ ACD
= 12[- 4(- 5 + 2) – 3(- 2 + 2) + 3(- 2 + 5)] + 12[- 4(- 2 – 3) + 3(3 + 2) + 2(- 2 + 2)]
= 12(12-0 + 9) + 12(20 + 15 + 0)
= 12(21 + 35) sq. units = 12 x 56 sq.units = 28 sq. units

Question 5.
You have studied in class IX (Chapter 9, Example 3) that a median of a triangle divides it into two triangles of equal areas. Verify this result for ∆ ABC whose vertices are A(4, – 6), B(3, – 2) and C(5, 2).
Solution:

Since AD is the median of A ABC, therefore D is the mid-point of BC. Coordinates of D are (3+52,−2+22), i.e., (4, 0)
Area of ∆ ADC = 12 [4(0 – 2) + 4(2 + 6) + 5(- 6 – 0)]
= 12(- 8 + 32 – 30) = 12 x (- 6) = – 3
= 3 sq. units (numerically)
Area of ∆ ABD = 12 [4(- 2 – 0) + 3(0 + 6) + 4(- 6 + 2)]
= 12(- 8 + 18 – 16)
= 12(- 6)
= – 3
= 3 sq. units (numerically)
Clearly, area (∆ ADC) = area (∆ ABD).
Hence, the median of the triangle divides it into two triangles of equal areas.

BSEB Textbook Solutions PDF for Class 10th

Bihar Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Textbooks for Exam Preparations

Bihar Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Textbook Solutions can be of great help in your Bihar Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 exam preparation. The BSEB STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.3 Books State Board syllabus with maximum efficiency.

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