# HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

## BSEB Class 9 Maths Chapter 1 संख्या पद्धति Ex 1.6 Textbook Solutions PDF: Download Bihar Board STD 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 Book Answers

 BSEB Class 9 Maths Chapter 1 संख्या पद्धति Ex 1.6 Textbook Solutions PDF: Download Bihar Board STD 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 Book Answers

BSEB Class 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 Textbooks Solutions and answers for students are now available in pdf format. Bihar Board Class 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 Book answers and solutions are one of the most important study materials for any student. The Bihar Board Class 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 books are published by the Bihar Board Publishers. These Bihar Board Class 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 textbooks are prepared by a group of expert faculty members. Students can download these BSEB STD 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 book solutions pdf online from this page.

## Bihar Board Class 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 Books Solutions

 Board BSEB Materials Textbook Solutions/Guide Format DOC/PDF Class 9th Subject Maths Chapter 1 संख्या पद्धति Ex 1.6 Chapters All Provider Hsslive

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## BSEB Class 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 Textbooks Solutions with Answer PDF Download

Find below the list of all BSEB Class 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

## BSEB Bihar Board Class 9 Maths Solutions Chapter 1 संख्या पद्धति Ex 1.6

प्रश्न 1.
ज्ञात कीजिए
(i) 6412
(ii) 3215
(iii) 12513
हाल:
(i) (64)12 = (8 × 8)12
= (8²)12 [∵ (xa)b = xab]
= 8

(ii) 3215 = (2 × 2 × 2 × 2 × 2)15
= (25)15
= 25×15 [∵ (xa)b = xab]
= 2

(iii) 12513 = (5 × 5 × 5)13
= (53)13
= 53×13 [∵ (xa)b = xab]
= 5

प्रश्न 2.
ज्ञात कीजिए
(i) 932
(ii) 3225
(iii) 1634
(iv) 125−13
हल:
(i) 932 = (3 × 3)32
= (32)32
= 32×32 [∵ (xa)b = xab]
= 3³
= 27

(ii) 3225 = (2 × 2 × 2 × 2 × 2)25
= (25)25
= 25×25 [∵ (xa)b = xab]
= 2²
= 4

(iii) 1634 = (2 × 2 × 2 × 2)34
= (24)34
= 24×34 [∵ (xa)b = xab]
= 2³
= 8

(iv) 125−13 = (5 × 5 × 5)-13
= (53)-13
= 53×-13 [∵ (xa)b = xab]
= 5-1
= 15 [∵ (x-a) = 1𝑥𝑎]

प्रश्न 3.
सरल कीजिए
(i) 223. 215
(ii) (13³)7
(iii) 11121114
(iv) 71/2.81/2
हल:
(i) 223. 215 = 2(23+15) [∵ xaxb = xa+b]
= 210+35
= 213/15

(ii) (13³)7 = 133×7 [∵ (xa)b = xab]
= 1321
= 3-21

(iii) 11121114 = 1112 – 14 [∵ 𝑥𝑎𝑥𝑏=𝑥𝑎−𝑏]

= 112−14
= 1114

(iv) 71/2.81/2 = (7.8)12 [∵ xaya = (xy)a]
= (56)1/2

## Bihar Board Class 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 Textbooks for Exam Preparations

Bihar Board Class 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 Textbook Solutions can be of great help in your Bihar Board Class 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 exam preparation. The BSEB STD 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 Books State Board syllabus with maximum efficiency.

## FAQs Regarding Bihar Board Class 9th Maths Chapter 1 संख्या पद्धति Ex 1.6 Textbook Solutions

#### Can we get a Bihar Board Book PDF for all Classes?

Yes you can get Bihar Board Text Book PDF for all classes using the links provided in the above article.

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