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BSEB Class 9 Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Textbook Solutions PDF: Download Bihar Board STD 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Book Answers

 BSEB Class 9 Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Textbook Solutions PDF: Download Bihar Board STD 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Book Answers

BSEB Class 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Textbooks Solutions and answers for students are now available in pdf format. Bihar Board Class 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Book answers and solutions are one of the most important study materials for any student. The Bihar Board Class 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 books are published by the Bihar Board Publishers. These Bihar Board Class 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 textbooks are prepared by a group of expert faculty members. Students can download these BSEB STD 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 book solutions pdf online from this page.

Bihar Board Class 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Books Solutions

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BSEB Class 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Textbooks Solutions with Answer PDF Download

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BSEB Bihar Board Class 9th Maths Solutions Chapter 4 Linear Equations in Two Variables Ex 4.1

Question 1.
The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.
Solution:
Let the cost of a notebook be Rs x and that of a pen be Rs y. Since the cost of a notebook is twice the cost of pen. So, the required linear equation in two variables to represent the above statement is given by x = 2y.

Question 2.
Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case :
(i) 2x + 3y = 9.35¯
(ii) x – 𝑦5 – 10 = 0
(iii) – 2x + 3y = 6
(iv) x = 3y
(v) 2x = – 5y
(vi) 3x + 2 = 0
(vii) y – 2 = 0
(viii) 5 = 2x
Solution:
(i) 2x + 3y = 9 can be written as 2x + 3y – 9 = 0.
On comparing it with ax + by + c = 0, we have
a = 2, b = 3 and c = – 9,

(ii) On.comparing x – 𝑦5 – 10 = 6 with ax + 6y f c = 0, we have
a = 1, b = –15 and c = – 10.

(iii) – 2x i+ 3y = 6 can be written as – 2x + 3y – 6 = 0.
On comparing it With ax + by + c = 0, we have
a = – 2, b = 3 and c = – 6.

(iv) x- 3y can be written as x – 3y = 0.
On comparing it with ax + by + c – 0, we have a = 1, b = – 3 and c = 0.

(v) 2x = – 5y can be written as 2x + 5y = 0
On comparing it with ax + by + c = 0, we have
a = 2, b = 5 and c = 0.

(vi) On comparing 3x + 2 = 0 with ax + by + c = 0, we
a = 3, b = 0 and c = 2.

(vii) On comparing y – 2 = 0 with ax + by + c = 0, we
a = 0, b = 1 and c = – 2.

(viii) 5 = 2x can be written as 2x – 5 = 0.
On comparing with ax + by + c = 0, We have
a = 2, 6 = 0 and c = – 5

Bihar Board Class 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Textbooks for Exam Preparations

Bihar Board Class 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Textbook Solutions can be of great help in your Bihar Board Class 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 exam preparation. The BSEB STD 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 9th Maths Chapter 4 Linear Equations in Two Variables Ex 4.1 Books State Board syllabus with maximum efficiency.

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