BSEB Class 9 Maths Chapter 6 Lines and Angles Ex 6.1 Textbook Solutions PDF: Download Bihar Board STD 9th Maths Chapter 6 Lines and Angles Ex 6.1 Book Answers ~ HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

BSEB Class 9 Maths Chapter 6 Lines and Angles Ex 6.1 Textbook Solutions PDF: Download Bihar Board STD 9th Maths Chapter 6 Lines and Angles Ex 6.1 Book Answers

BSEB Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 Textbooks Solutions and answers for students are now available in pdf format. Bihar Board Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 Book answers and solutions are one of the most important study materials for any student. The Bihar Board Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 books are published by the Bihar Board Publishers. These Bihar Board Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 textbooks are prepared by a group of expert faculty members. Students can download these BSEB STD 9th Maths Chapter 6 Lines and Angles Ex 6.1 book solutions pdf online from this page.

Bihar Board Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 Textbooks Solutions PDF

Bihar Board STD 9th Maths Chapter 6 Lines and Angles Ex 6.1 Books Solutions with Answers are prepared and published by the Bihar Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of BSEB Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 Books Answers Solutions, then you are in the right place. Here is a complete hub of Bihar Board Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Bihar Board STD 9th Maths Chapter 6 Lines and Angles Ex 6.1 Textbooks. These Bihar Board Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Bihar Board.

Bihar Board Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 Books Solutions

Board	BSEB
Materials	Textbook Solutions/Guide
Format	DOC/PDF
Class	9th
Subject	Maths Chapter 6 Lines and Angles Ex 6.1
Chapters	All
Provider	Hsslive

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BSEB Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 Textbooks Solutions with Answer PDF Download

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BSEB Bihar Board Class 9th Maths Solutions Chapter 6 Lines and Angles Ex 6.1

Question 1.
In figure, lines AB and CD intersect at O. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.

Solution:
Since OA and OB are opposite rays. Therefore, AB is a line.
Since ray OC stands on AB. Therefore,
∠AOC + ∠COB = 180° [Linear Pairs]
⇒ ∠AOC + ∠COE + ∠BOE = 180° [∵∠COB = ∠COE + ∠BOE]
⇒ (∠AOC + ∠BOE) + ∠COE = 180°
⇒ 70° + ∠COE = 180° [∵ ∠AOC + ∠BOE = 70° (Given)]
⇒ ∠COE = 180° – 70° = 110°
∴ Reflex ∠COE = 360° – 110° = 250°
Since OC and OD are opposite rays. Therefore, CD is a line.
Since ray OE stands on CD. Therefore,
∠COE + ∠EOD = 180° [Linear Pairs]
⇒ ∠COE) + ∠BOE + ∠BOD = 180°
⇒ 110° + ∠BOE + 40° = 180°
[∵ ∠COE = 110° (probed above), ∠BOD = 40° (Given)]
⇒ ∠BOE = 180° – 110° – 40° = 30°
Hence, ∠BOE = 30° and reflex ∠COE = 250°.

Question 2.
In figure, lines XY and MN intersect at O. If ∠POY = 90° and a : 6 = 2 : 3, find c.

Solution:
Since a : b = 2 : 3 and a + b = ∠POX = ∠POY = 90° and sum- of ratios = 2 + 3 = 5
∴ a = 25 x 90° = 2 x 18° = 36°
and b = 35 x 90° = 3 x 18° = 54°
Since OM and ON are opposite rays. Therefore, MN is a line.
Since ray OX stands on MN. Therefore,
∠MOX + ∠XON = 180°’ [Linear Pairs]
⇒ c + b = 180° ⇒ c + 54° = 180°
⇒ c = 180° – 54° = 126°
Hence, c = 126°.

Question 3.
In figure, ∠PQR = ∠PRQ, then prove that ∠PQS = ∠PRT.

Solution:
Since QS and QR are opposite rays. Therefore, SR is a line.
Since QP stands on the line SR.
∴ ∠PQS + ∠PQR = 180° [Linear Pair] … (1)
Again, RQ and RT are opposite rays. Therefore, QT is a line.
Since ER stands on the line QT.
∴ ∠PRQ + ∠PRT = 180° [Linear Pair] …(2)
From (1) and (2), we have
∠PQS + ∠PQR = ∠PRQ + ∠PRT [∵ Each side = 180°] … (3)
Also ∠PQR = ∠PRQ [Given] … (4)
Subtracting (4) from (3), we have ∠PQS = ∠PRT.

Question 4.
In figure, if x + y = w + z, then prove that AOB is a line.

Solution:
Since the sum all angles round a point is equal to 360°

Thus, ∠BOC and ∠COA, ∠BOD and ∠AOD form linear pairs. Consequently OA and OB are two opposite rays. Therefore, AOB is a straight line.

Question 5.
In figure, POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR. Prove that ∠ROS = 12(∠QOS – ∠POS).

Solution:
Since OR is perpendicular to the line PQ.
∴∠POR = ∠ROQ [∵ Each = 90°]
⇒ ∠POS + ∠ROS = ∠QOS – ∠ROS
⇒ 2∠ROS =∠QOS – ∠POS
⇒ ∠ROS = 12(∠QOS – ∠POS)

Question 6.
It is given that ∠XYZ = 64° and XY is produced to point P. Draw a figure from the given information. If ray YQ bisects ∠ZYP, find ∠XYQ and reflex ∠QYP.

Solution:
Since XY is produced to point P. Therefore, XP is a straight line.
Since YZ stands on XP.
∴ ∠XYZ + ∠ZYP = 180° [Linear Pair]
⇒ 64° + ∠ZYP = 180° [∵ ∠XYZ = 64°]
⇒ ∠ZYP = 180° – 64° = 116°
Since ray YQ bisects ∠ZYP.
Therefore,∠QYP = ∠ZYQ = 1112 = 58°
Now, ∠XYQ = ∠XYZ + ∠ZYQ
⇒ ∠XYQ = 64° + 58° = 122°
and reflex ∠QYP = 360° – ∠QYP = 360° – 58° = 302°

BSEB Textbook Solutions PDF for Class 9th

Bihar Board Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 Textbooks for Exam Preparations

Bihar Board Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 Textbook Solutions can be of great help in your Bihar Board Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 exam preparation. The BSEB STD 9th Maths Chapter 6 Lines and Angles Ex 6.1 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 9th Maths Chapter 6 Lines and Angles Ex 6.1 Books State Board syllabus with maximum efficiency.

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