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AP Board Class 8 Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Book Answers

AP Board Class 8 Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Book Answers
AP Board Class 8 Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Book Answers


AP Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbooks Solutions and answers for students are now available in pdf format. Andhra Pradesh Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Book answers and solutions are one of the most important study materials for any student. The Andhra Pradesh State Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 books are published by the Andhra Pradesh Board Publishers. These Andhra Pradesh Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 textbooks are prepared by a group of expert faculty members. Students can download these AP Board STD 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 book solutions pdf online from this page.

Andhra Pradesh Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbooks Solutions PDF

Andhra Pradesh State Board STD 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbooks. These Andhra Pradesh State Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.

Andhra Pradesh State Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Books Solutions

Board AP Board
Materials Textbook Solutions/Guide
Format DOC/PDF
Class 8th
Subject Maths
Chapters Maths Chapter 6 Square Roots and Cube Roots Ex 6.2
Provider Hsslive


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AP Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Question 1.
Find the square roots of the following numbers by Prime factorization method.
(1) 441
(ii) 784
(iii) 4096
(iv) 7056
Solution:

Question 2.
Find the smallest number by which 3645 must be multiplied to get a perfect square.
Solution:
The prime factorization of 3645
= (3 × 3) × (3 × 3) (3 × 3) × 5
∴ Deficiency of one ‘5’ is appeared in the above product.
∴ 3645 is multiplied with 5 then we will get a perfect square.

Question 3.
Find the smallest number by which 2400 is to be multiplied to get a perfect square and also find the square root of the resulting number.
Solution:
The prime factorization of 2400
=(2 × 2) × (2 × 2) × 2 × (5 × 5) × 3
∴ 2,3 are needed to form a pair
∴ 2 × 3 = 6
∴ 6 should be multiplied with 2400 then we will get a perfect square number.
∴ 2400 × 6 = 14400
∴ 14400‾‾‾‾‾‾√ = 120

Question 4.
Find the smallest number by which 7776 is to be divided to get a perfect square.
Solution:

The prime factorization of 7776
=(2 × 2) × (2 × 2) × 2 × (3 × 3) × (3 × 3) × 3
∴ 2, 3 are needed to form a pair
∴ 2 × 3 = 6
∴ 7776 should be divided by 6 then we will get a perfect square number.

Question 5.
1521 trees are planted in a garden in such a way that there are as many trees in each row as there are rows in the garden. Find the number of rows and number of trees in each row.
Solution:
Let the no. of trees planted in a garden for each row = x say.
No. of rows in the garden = x
∴ Total no. of trees in the garden = x × x = x2
According to the sum x2 = 1521
x = 1521‾‾‾‾‾√=39×39‾‾‾‾‾‾‾√ = 39
∴ No. of trees for each row = 39
No. of rows in the garden = 39

Question 6.
A school collected ₹ 2601 as fees from its students. If fee paid by each student and number students in the school were equal, how many students were there in the school?
Solution:
Let the no. of students in a school = x say
The (amount) fee paid by each student = ₹ x
Amount collected by all the students
= x × x = x2
According to the sum
∴ x2 = 2601
x = 2601‾‾‾‾‾√=51×51‾‾‾‾‾‾‾√ = 51
∴ x = 51
∴ No. of students in the school = 51

Question 7.
The product of two numbers is 1296. If one number is 16 times the other, find the two numbers?
Solution:
Given that the product of two numbers = 1296.
Let the second number = x say
Then first number = 16 × x = 16x
∴ The product of two numbers
= x × 16x= 16x2
According to the sum
16x2 = 1296
⇒ x2 = 129616 = 81
⇒ x2 = 81
⇒ x = 8‾√1⎯⎯⎯=9×9‾‾‾‾‾√ = 9
⇒ x = 9
∴ The first number = 16x
= 16 × 9
=144
The second number = x = 9

Question 8.
7921 soldiers sat in an auditorium in such a way that there are as many soldiers in a row as there are rows in the auditorium. How many rows are there in the auditorium’?
Solution:
Let the number of soldiers sat in an auditorium for each row = x say
∴ No. of rows in an auditorium = x
∴ Total no. of soldiers = x × x = x2
According to the sum,
x2 = 7921
x = 7921‾‾‾‾‾√=89×89‾‾‾‾‾‾‾√ = 89
∴ No. of rowS in an auditorium = 89

Question 9.
The area of a square field is 5184 m2. Find the area of a rectangular field, whose perimeter is equal to the perimeter of the square field and whose length is twice of its breadth.
Solution:
Area of a square field = 5184 m2
A = s2 = 5184
:. s = 5184‾‾‾‾‾√=72×72‾‾‾‾‾‾‾√ = 72
∴ s = 72
∴ Perimeter of the square field = 4 × s
= 4 × 72
= 288 m
According to the sum,
Perimeter of a rectangular field
= Perimeter of a square field = 288 m
Let the breadth of a rectangular field
= x m say
∴ Length = 2 × x = 2 × m
∴ Perimeter of the rectangular field
= 2 (1 + b)
= 2 (2x + x)
= 2 × 3x
= 6x
∴ 6x = 288 .
x = 2886
x = 48
∴ Breadth of the rectangular field
= x = 48 m
Length of the rectangular field = 2x
= 2 × 48
=96m
∴ Area of the rectangular field
= l × b
= 96 × 48
= 4608 m2


AP Board Textbook Solutions PDF for Class 8th Maths


Andhra Pradesh Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbooks for Exam Preparations

Andhra Pradesh Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 exam preparation. The AP Board STD 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Books State Board syllabus with maximum efficiency.

FAQs Regarding Andhra Pradesh Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbook Solutions


How to get AP Board Class 8th Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Textbook Answers??

Students can download the Andhra Pradesh Board Class 8 Maths Chapter 6 Square Roots and Cube Roots Ex 6.2 Answers PDF from the links provided above.

Can we get a Andhra Pradesh State Board Book PDF for all Classes?

Yes you can get Andhra Pradesh Board Text Book PDF for all classes using the links provided in the above article.

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