# HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

## AP Board Class 9 Maths Chapter 7 Triangles Ex 7.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 9th Maths Chapter 7 Triangles Ex 7.2 Book Answers

 AP Board Class 9 Maths Chapter 7 Triangles Ex 7.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 9th Maths Chapter 7 Triangles Ex 7.2 Book Answers

## Andhra Pradesh State Board Class 9th Maths Chapter 7 Triangles Ex 7.2 Books Solutions

 Board AP Board Materials Textbook Solutions/Guide Format DOC/PDF Class 9th Subject Maths Chapters Maths Chapter 7 Triangles Ex 7.2 Provider Hsslive

2. Click on the Andhra Pradesh Board Class 9th Maths Chapter 7 Triangles Ex 7.2 Answers.
3. Look for your Andhra Pradesh Board STD 9th Maths Chapter 7 Triangles Ex 7.2 Textbooks PDF.

## AP Board Class 9th Maths Chapter 7 Triangles Ex 7.2 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 9th Maths Chapter 7 Triangles Ex 7.2 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

## AP State Syllabus 9th Class Maths Solutions 7th Lesson Triangles Exercise 7.2

Question 1.
In an isosceles triangle ABC, with AB = AC, the bisectors of ∠B and ∠C intersect each other at ‘O’. Join A to O. Show that (i) OB = OC (ii) AO bisects ∠A.

Solution:
Given that in ΔABC
AB = AC
Bisectors of ∠B and ∠C meet at ‘O’.
To prove
i) OB = OC
∠B = ∠C (Angles opposite to equal, sides)
12∠B=12∠C (Dividing both sides by 2)
∠OBC = ∠OCB
⇒ OB = OC (∵ Sides opposite to equal angles in ΔOBC)

ii) AO bisects ∠A.
In ΔAOB and ΔAOC
AB = AC (given)
∠ABO = ∠ACO (∵ ∠B =∠C)
∴ ΔAOB ≅ ΔAOC
⇒ ∠BAO = ∠CAO [ ∵ CPCT of ΔAOB and ΔAOC]
∴ AO is bisector of ∠A.

Question 2.
In ΔABC, AD is the perpendicular bisector of BC (see given figure). Show that ΔABC is an isosceles triangle in which AB = AC

Solution:
In ΔABD and ΔACD
BD = DC (given)
∴ ΔABD ≅ ΔACD (∵ SAS congruence)
⇒ AB = AC (CPCT of ΔABD and ΔACD)

Question 3.
ABC is an isosceles triangle in which altitudes BD and CE are drawn to equal sides AC and AB respectively (see figure). Show that these altitudes are equal.

Solution:
Given that AC = AB; BD ⊥ AC; CE ⊥ AB
In ΔBCD and ΔCBE
∠BDC = ∠CEB (90° each)
∠BCD = ∠CBE (∵ angles opp. to equal sides of a triangle)
BC = BC
∴ ΔBCD ≅ ΔCBE (∵ AAScongruence)
⇒ BD = CE (CPCT)

Question 4.
ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal (see figure). Show that
i) ΔABD ≅ ΔACE
ii) AB = AC i.e., ABC is an isosceles triangle.

Solution:
Given that BD ⊥ AC; CE ⊥ AC
BD = CE
Now in ΔABD and ΔACE
∠ADB = ∠AEC (∵ given 90°)
∠A = ∠A (commori angle)
BD = CE
∴ ΔABD = ΔACE (∵ AAS congruence)
⇒ AB = AC (∵ C.P.C.T)

Question 5.
ΔABC and ΔDBC are two isosceles triangles on the same base BC (see figure). Show that ∠ABD = ∠ACD.

Solution:

Given that ΔABC and ΔDBC are isosceles.
To prove ∠ABD = ∠ACD
Join A and D.
Now in ΔABD and ACD
AB = AC (∵ equal sides of isosceles triangles)
BD = CD (∵ equal sides of isosceles triangles)
∴ ΔABD ≅ ΔACD (∵ SSS congruence)
⇒ ∠ABD = ∠ACD (CPCT)

## Andhra Pradesh Board Class 9th Maths Chapter 7 Triangles Ex 7.2 Textbooks for Exam Preparations

Andhra Pradesh Board Class 9th Maths Chapter 7 Triangles Ex 7.2 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 9th Maths Chapter 7 Triangles Ex 7.2 exam preparation. The AP Board STD 9th Maths Chapter 7 Triangles Ex 7.2 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 9th Maths Chapter 7 Triangles Ex 7.2 Books State Board syllabus with maximum efficiency.

## FAQs Regarding Andhra Pradesh Board Class 9th Maths Chapter 7 Triangles Ex 7.2 Textbook Solutions

#### Can we get a Andhra Pradesh State Board Book PDF for all Classes?

Yes you can get Andhra Pradesh Board Text Book PDF for all classes using the links provided in the above article.

## Important Terms

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