# HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

## Andhra Pradesh State Board Class 9th Maths Chapter 8 Quadrilaterals Ex 8.2 Books Solutions

 Board AP Board Materials Textbook Solutions/Guide Format DOC/PDF Class 9th Subject Maths Chapters Maths Chapter 8 Quadrilaterals Ex 8.2 Provider Hsslive

3. Look for your Andhra Pradesh Board STD 9th Maths Chapter 8 Quadrilaterals Ex 8.2 Textbooks PDF.

Find below the list of all AP Board Class 9th Maths Chapter 8 Quadrilaterals Ex 8.2 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

## AP State Syllabus 9th Class Maths Solutions 8th Lesson Quadrilaterals Exercise 8.2

Question 1.
In the given figure ABCD is a parallelogram. ABEF is a rectangle. Show that ΔAFD ≅ ΔBEC

Solution:
Given that □ABCD is a parallelogram.
□ABEF is a rectangle.
In ΔAFD and ΔBEC
AF = BE ( ∵ opp. sides of rectangle □ABEF)
AD = BC (∵ opp. sides of //gm □ABCD)
DF = CE (∵ AB = DC = DE + EC , AB = EF = DE + DF)
∴ ΔAFD ≅ ΔBEC (SSS congruence)

Question 2.
Show that the diagonals of a rhombus divide it into four congruent triangles.
Solution:

□ABCD is a rhombus.
Let AC and BD meet at O’.
In ΔAOB and ΔCOD
∠OAB = ∠OCD (alt.int. angles)
AB = CD (def. of rhombus)
∠OBA = ∠ODC ………………….(1) (alt. int. angles)
∴ ΔAOB ≅ ΔCOD (ASA congruence)
Thus AO = OC (CPCT)
Also ΔAOD ≅ ΔCOD …………..(2)
[ ∵ AO = OC; AD = CD; OD = OD SSS congruence]
Similarly we can prove
ΔAOD ≅ ΔCOB ……………. (3)
From (1), (2) and (3) we have
ΔAOB ≅ ΔBOC ≅ ΔCOD ≅ ΔAOD
∴ Diagonals of a rhombus divide it into four congruent triangles.

Question 3.
In a quadrilateral ABCD, the bisector of ∠C and ∠D intersect at O. Prove that ∠COD = 12 (∠A + ∠B) .
(OR)
In a quadrilateral ABCD, the bisectors of ∠A and ∠B are intersects at ‘O’ then prove that ∠AOB = 12 (∠C + ∠D)
Solution:

∠A + ∠B + ∠C + ∠D = 360°
(angle sum property)
∠C + ∠D = 360° – (∠A + ∠B)
12 (∠C + ∠D) = 180 – 12 (∠A + ∠B) ………….. (1)
(∵ dividing both sides by 2) .
But in ΔCOD
12∠C + 12∠D + ∠COD = 180°
12∠C + 12∠D = 180° – ∠COD
∴12(∠C +∠D) = 180° -∠COD………….(2)
From (1) and (2);
180° – ∠COD = 180° – 12 (∠A + ∠B)
∴ ∠COD = 12 (∠A + ∠B)
Hence proved.

## Andhra Pradesh Board Class 9th Maths Chapter 8 Quadrilaterals Ex 8.2 Textbooks for Exam Preparations

Andhra Pradesh Board Class 9th Maths Chapter 8 Quadrilaterals Ex 8.2 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 9th Maths Chapter 8 Quadrilaterals Ex 8.2 exam preparation. The AP Board STD 9th Maths Chapter 8 Quadrilaterals Ex 8.2 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 9th Maths Chapter 8 Quadrilaterals Ex 8.2 Books State Board syllabus with maximum efficiency.

## FAQs Regarding Andhra Pradesh Board Class 9th Maths Chapter 8 Quadrilaterals Ex 8.2 Textbook Solutions

#### Can we get a Andhra Pradesh State Board Book PDF for all Classes?

Yes you can get Andhra Pradesh Board Text Book PDF for all classes using the links provided in the above article.