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AP Board Class 9 Maths Chapter 9 Statistics Ex 9.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 9th Maths Chapter 9 Statistics Ex 9.2 Book Answers |
Andhra Pradesh Board Class 9th Maths Chapter 9 Statistics Ex 9.2 Textbooks Solutions PDF
Andhra Pradesh State Board STD 9th Maths Chapter 9 Statistics Ex 9.2 Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 9th Maths Chapter 9 Statistics Ex 9.2 Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 9th Maths Chapter 9 Statistics Ex 9.2 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 9th Maths Chapter 9 Statistics Ex 9.2 Textbooks. These Andhra Pradesh State Board Class 9th Maths Chapter 9 Statistics Ex 9.2 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.Andhra Pradesh State Board Class 9th Maths Chapter 9 Statistics Ex 9.2 Books Solutions
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Materials | Textbook Solutions/Guide |
Format | DOC/PDF |
Class | 9th |
Subject | Maths |
Chapters | Maths Chapter 9 Statistics Ex 9.2 |
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AP Board Class 9th Maths Chapter 9 Statistics Ex 9.2 Textbooks Solutions with Answer PDF Download
Find below the list of all AP Board Class 9th Maths Chapter 9 Statistics Ex 9.2 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:AP State Syllabus 9th Class Maths Solutions 9th Lesson Statistics Exercise 9.2
Question 1.
Weights of parcels in a transport office are given below.
Find the mean weight of the parcels.
Solution:
Weight in kg xi | No. of parcels fi | x1fi |
50 | 25 | 1250 |
65 | 34 | 2210 |
75 | 38 | 2850 |
90 | 40 | 3600 |
110 | 47 | 5170 |
120 | 16 | 1920 |
Σfi = 200
Σfixi = 17000
x⎯⎯⎯=ΣfixiΣfi=17000200=1702x⎯⎯⎯=85
Mean = 85
Question 2.
Number of familles In a village in correspondence with the number of children are given below.
Find the mean number of children per family.
Solution:
No. of childrens xi | No. of families fi | x1fi |
0 | 11 | 0 |
1 | 25 | 25 |
2 | 32 | 64 |
3 | 10 | 30 |
4 | 5 | 20 |
6 | 1 | 5 |
Σfi = 84
Σfixi = 144
x⎯⎯⎯=ΣfixiΣfi=14484
Mean = 1.714285
Question 3.
If the mean of the following frequency distribution is 7.2, find value of ‘k’.
Solution:
Σfi = 40 + k;
Σfixi = 260 + 10k
Given that x⎯⎯⎯ = 7.2
But x⎯⎯⎯=Σf1xiΣfi
7.2 = 260+10𝑘40+𝑘
288.0 + 7.2k = 260 + 10k
10k – 7.2k = 288 – 260
2.8k = 28
k = 282.8 = 10
Question 4.
Number of villages with respect to their population as per India census 2011 are given below.
Find the average population in each village.
Solution:
Population (in thousands xi) | Villages fi | x1fi |
12 | 20 | 240 |
5 | 15 | 75 |
30 | 32 | 960 |
20 | 35 | 700 |
15 | 36 | 540 |
8 | 7 | 56 |
Σfi = 145 Σfixi = 2571 thousands
x⎯⎯⎯=ΣfixiΣfi
Mean = 2571145 = 17.731 thousands
Question 5.
A FLATOUN social and financial educational programme initiated savings programme among the high school children in Hyderabad district. Mandal wise savings in a month are given in the following table.
Mandal | No. of schools | Total amount saved (in rupees |
Amberpet | 6 | 2154 |
Thirumalgiri | 6 | 2478 |
Saidabad | 5 | 975 |
Khairathabad | 4 | 912 |
Secunderabad | 3 | 600 |
Bahadurpura | 9 | 7533 |
Find arithmetic mean of school wise savings in each mandal. Also find the arithmetic mean of saving of all schools.
Solution:
Σfi = 33
Σfixi = 14652
Mean = ΣfixiΣfi
𝑥¯=1465233 = ₹ 444 (Mean savings per school)
Question 6.
The heights of boys and girls of IX class of a school are given below.
Compare the heights of the boys and girls.
[Hint: Fliid median heights of boys and girls]
Solution:
Boys median class=37+12=382= 19th observation
∴ Median height of boys = 147 cm
Girls median class= 29+12=302 = 15th observation
∴ Median height of girls = 152 cm
Question 7.
Centuries scored and number of cricketers in the world are given below.
Find the mean, median and mode of the given data.
Solution:
Question 8.
On the occasion of New year’s day a sweet stall prepared sweet packets. Number of sweet packets and cost of each packet is given as follows
Find the mean, median and mode of the given data.
Solution:
N = Σfi = 150
Σfixi = 12000
Mean = x⎯⎯⎯=ΣfixiΣfi=12000150=80
Median = average of (𝑁2+1 and 𝑁2 terms = average of 75 and 76 observation = 75
Mode = 50
Question 9.
The mean (average) weight of three students is 40 kg. One of the students Ranga weighs 46 kg. The other two students, Rahim and Reshma have the same weight.
Find Rahim’s weight. cgigB)
Solution:
Weight of Ranga = 46 kg
Weight of Reshma = Weight of Rahim = x kg say
Average = Sum of the weights Number = 40kg
∴ 40 = 46+𝑥+𝑥3
3 x 40 = 46 + 2x
2x = 120 – 46 = 74
∴ x = 742 = 37 .
∴ Rahim’s weight = 37 kg.
Question 10.
The donations given to an orphanage home by the students of different classes of a secondary school are given below.
Class | Donation by each student in (Rs) | No. of students donated |
VI | 5 | 15 |
VII | 7 | 15 |
VIII | 10 | 20 |
IX | 15 | 16 |
X | 20 | 14 |
Find the mean, median and mode of the data.
Solution:
Σfi = 80
Σfixi = 900
Mean x⎯⎯⎯=ΣfixiΣfi=90080=11.25
Median = Average of (N2) and (N2+1) terms of 802,(802+1) terms
= average of 40 and 41 terms = ₹10
Mode = ₹ 10
Question 11.
There are four unknown numbers. The mean of the first two numbers is 4 and the mean of the first three is 9. The mean of all four numbers is 15; if one of the four numbers is 2 find the other numbers.
Solution:
We know that mean = sum number
Given that, Mean of 4 numbers = 15
⇒ Sum of the 4 numbers = 4 x 15 = 60
Mean of the first 3 numbers = 9
⇒ Sum of the first 3 numbers = 3 x 9 = 27
Mean of the first 2 numbers = 4
⇒ Sum of the first 2 numbers = 2 x 4 = 8
Fourth number = sum of 4 numbers – sum of 3 numbers = 60 – 27 = 33
Third number = sum of 3 numbers – sum of 2 numbers = 27 – 8 = 19
Second number = Sum of 2 numbers – given number = 8-2 = 6
∴ The other three numbers are 6, 19, 33.
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