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## AP Board Class 9 Maths Chapter 9 Statistics Ex 9.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 9th Maths Chapter 9 Statistics Ex 9.2 Book Answers

 AP Board Class 9 Maths Chapter 9 Statistics Ex 9.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 9th Maths Chapter 9 Statistics Ex 9.2 Book Answers

## Andhra Pradesh State Board Class 9th Maths Chapter 9 Statistics Ex 9.2 Books Solutions

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## AP Board Class 9th Maths Chapter 9 Statistics Ex 9.2 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 9th Maths Chapter 9 Statistics Ex 9.2 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

## AP State Syllabus 9th Class Maths Solutions 9th Lesson Statistics Exercise 9.2

Question 1.
Weights of parcels in a transport office are given below.

Find the mean weight of the parcels.
Solution:

 Weight in kg xi No. of parcels fi x1fi 50 25 1250 65 34 2210 75 38 2850 90 40 3600 110 47 5170 120 16 1920

Σfi = 200
Σfixi = 17000
x⎯⎯⎯=ΣfixiΣfi=17000200=1702x⎯⎯⎯=85
Mean = 85

Question 2.
Number of familles In a village in correspondence with the number of children are given below.

Find the mean number of children per family.
Solution:

 No. of childrens xi No. of families fi x1fi 0 11 0 1 25 25 2 32 64 3 10 30 4 5 20 6 1 5

Σfi = 84
Σfixi = 144
x⎯⎯⎯=ΣfixiΣfi=14484
Mean = 1.714285

Question 3.
If the mean of the following frequency distribution is 7.2, find value of ‘k’.

Solution:

Σfi = 40 + k;
Σfixi = 260 + 10k
Given that x⎯⎯⎯ = 7.2
But x⎯⎯⎯=Σf1xiΣfi
7.2 = 260+10𝑘40+𝑘
288.0 + 7.2k = 260 + 10k
10k – 7.2k = 288 – 260
2.8k = 28
k = 282.8 = 10

Question 4.
Number of villages with respect to their population as per India census 2011 are given below.

Find the average population in each village.
Solution:

 Population (in thousands xi) Villages fi x1fi 12 20 240 5 15 75 30 32 960 20 35 700 15 36 540 8 7 56

Σfi = 145 Σfixi = 2571 thousands
x⎯⎯⎯=ΣfixiΣfi
Mean = 2571145 = 17.731 thousands

Question 5.
A FLATOUN social and financial educational programme initiated savings programme among the high school children in Hyderabad district. Mandal wise savings in a month are given in the following table.

 Mandal No. of schools Total amount saved (in rupees Amberpet 6 2154 Thirumalgiri 6 2478 Saidabad 5 975 Khairathabad 4 912 Secunderabad 3 600 Bahadurpura 9 7533

Find arithmetic mean of school wise savings in each mandal. Also find the arithmetic mean of saving of all schools.
Solution:

Σfi = 33
Σfixi = 14652
Mean = ΣfixiΣfi
𝑥¯=1465233 = ₹ 444 (Mean savings per school)

Question 6.
The heights of boys and girls of IX class of a school are given below.

Compare the heights of the boys and girls.
[Hint: Fliid median heights of boys and girls]
Solution:

Boys median class=37+12=382= 19th observation
∴ Median height of boys = 147 cm
Girls median class= 29+12=302 = 15th observation
∴ Median height of girls = 152 cm

Question 7.
Centuries scored and number of cricketers in the world are given below.

Find the mean, median and mode of the given data.
Solution:

Question 8.
On the occasion of New year’s day a sweet stall prepared sweet packets. Number of sweet packets and cost of each packet is given as follows

Find the mean, median and mode of the given data.
Solution:

N = Σfi = 150
Σfixi = 12000
Mean = x⎯⎯⎯=ΣfixiΣfi=12000150=80
Median = average of (𝑁2+1 and 𝑁2 terms = average of 75 and 76 observation = 75
Mode = 50

Question 9.
The mean (average) weight of three students is 40 kg. One of the students Ranga weighs 46 kg. The other two students, Rahim and Reshma have the same weight.
Find Rahim’s weight. cgigB)
Solution:
Weight of Ranga = 46 kg
Weight of Reshma = Weight of Rahim = x kg say
Average =  Sum of the weights  Number  = 40kg
∴ 40 = 46+𝑥+𝑥3
3 x 40 = 46 + 2x
2x = 120 – 46 = 74
∴ x = 742 = 37 .
∴ Rahim’s weight = 37 kg.

Question 10.
The donations given to an orphanage home by the students of different classes of a secondary school are given below.

 Class Donation by each student in (Rs) No. of students donated VI 5 15 VII 7 15 VIII 10 20 IX 15 16 X 20 14

Find the mean, median and mode of the data.
Solution:

Σfi = 80
Σfixi = 900
Mean x⎯⎯⎯=ΣfixiΣfi=90080=11.25
Median = Average of (N2) and (N2+1) terms of 802,(802+1) terms
= average of 40 and 41 terms = ₹10
Mode = ₹ 10

Question 11.
There are four unknown numbers. The mean of the first two numbers is 4 and the mean of the first three is 9. The mean of all four numbers is 15; if one of the four numbers is 2 find the other numbers.
Solution:
We know that mean =  sum  number
Given that, Mean of 4 numbers = 15
⇒ Sum of the 4 numbers = 4 x 15 = 60
Mean of the first 3 numbers = 9
⇒ Sum of the first 3 numbers = 3 x 9 = 27
Mean of the first 2 numbers = 4
⇒ Sum of the first 2 numbers = 2 x 4 = 8
Fourth number = sum of 4 numbers – sum of 3 numbers = 60 – 27 = 33
Third number = sum of 3 numbers – sum of 2 numbers = 27 – 8 = 19
Second number = Sum of 2 numbers – given number = 8-2 = 6
∴ The other three numbers are 6, 19, 33.

## Andhra Pradesh Board Class 9th Maths Chapter 9 Statistics Ex 9.2 Textbooks for Exam Preparations

Andhra Pradesh Board Class 9th Maths Chapter 9 Statistics Ex 9.2 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 9th Maths Chapter 9 Statistics Ex 9.2 exam preparation. The AP Board STD 9th Maths Chapter 9 Statistics Ex 9.2 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 9th Maths Chapter 9 Statistics Ex 9.2 Books State Board syllabus with maximum efficiency.

## FAQs Regarding Andhra Pradesh Board Class 9th Maths Chapter 9 Statistics Ex 9.2 Textbook Solutions

#### Can we get a Andhra Pradesh State Board Book PDF for all Classes?

Yes you can get Andhra Pradesh Board Text Book PDF for all classes using the links provided in the above article.

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