HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

BSEB Class 7 Maths Chapter 9 बीजीय व्यंजक Textbook Solutions PDF: Download Bihar Board STD 7th Maths Chapter 9 बीजीय व्यंजक Book Answers

 BSEB Class 7 Maths Chapter 9 बीजीय व्यंजक Textbook Solutions PDF: Download Bihar Board STD 7th Maths Chapter 9 बीजीय व्यंजक Book Answers

BSEB Class 7th Maths Chapter 9 बीजीय व्यंजक Textbooks Solutions and answers for students are now available in pdf format. Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक Book answers and solutions are one of the most important study materials for any student. The Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक books are published by the Bihar Board Publishers. These Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक textbooks are prepared by a group of expert faculty members. Students can download these BSEB STD 7th Maths Chapter 9 बीजीय व्यंजक book solutions pdf online from this page.

Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक Books Solutions

 Board BSEB Materials Textbook Solutions/Guide Format DOC/PDF Class 7th Subject Maths Chapter 9 बीजीय व्यंजक Chapters All Provider Hsslive

How to download Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक Textbook Solutions Answers PDF Online?

2. Click on the Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक Answers.
3. Look for your Bihar Board STD 7th Maths Chapter 9 बीजीय व्यंजक Textbooks PDF.
4. Now download or read the Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक Textbook Solutions for PDF Free.

Find below the list of all BSEB Class 7th Maths Chapter 9 बीजीय व्यंजक Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Bihar Board Class 7 Maths बीजीय व्यंजक Ex 9.1

Class 7 Maths Chapter 9 Ex 9.2 Bihar Board प्रश्न 1.
निम्नलिखीत व्यंजकों में से चर एवं अचर राशियाँ ज्ञात करें-
(a) 5x + 2
(b) 2ab + 1
(c) 2x2y – 1 + 2x
(d) m3 – n2 – 1
(e) 9x2y2
हल :
(a) 5x + 2
चर = x
अचर = 5, 2

(b) 2ab + 1
चर = a, b
अचर = 2, 1

(c) 2x2y2 – 1 + 2x
चर = x2, y, x
अचर = 2, -1, 2

(d) m3 – n2 – 1
चर = m, n
अचर = -1

(e) 9x2y2
चर = x, y, z
अचर = 9

Class 7 Maths Chapter 9 Exercise 9.1 Solution Bihar Board प्रश्न 2.
निम्नलिखित व्यंजकों के पदों को पहचानिए-
(a) x2 + 2x + 1
(b) 8a2 + 11ab = 2b2
(c) 9p2 – 4q
(d) a2b2 – 9
(e) 8ab – 3b
हल :
(a) x2 + 2x + 1
x2 = x × x
2x = 2 × x
1 = 1
पेड़ की आरेख विधि से

(b) 8a2 + 11ab = 2b2
8a = 8 × a × a
11ab = 11 × a × b
2b2 = b × b × 2

(c) 9p2 – 4q
9p2 = 9 × p × p
4q = 4 × q

(d) a2b2 – 9
a2b2 = a × a × b × b

(e) 8ab – 3b
8ab = 8 × a × b
3b = 3 × b

Exercise 9.1 Class 7 Bihar Board प्रश्न 3.
12x2y में x2y, x तथा y का गुणांक बताइए-
हल :
12x2y में
x2y का गुणांक = 12
xy का गुणांक = 12xy
y का गुणांक = 12x2

Class 7 Maths Exercise 9.1 Bihar Board प्रश्न 4.
निम्नलिखित पद युग्मों में से समान पदों के समूह लिखिए-
9x2y, 8xy2, 3ab, -7ba, 7ab2, -4b2, 7a, 7, 11a, -11a2, 2xy, -2xy, 8ab, -2a, -2, 1, -x, 3x, 8x, 8
हल :
समान पद-
3ab, 8ab, -7ab
3x, 8x, -x
7, -2, 1, 8
11a, -2a
7a, 11a, -2a

Chapter 9 Class 7 Maths Bihar Board प्रश्न 5.
(a) 2x – y (द्विपदी)
(b) a2 – 3 – 3a (त्रिपदी)
(c) 3mn (एकपदी)
(d) a2b – 7a + 6 (त्रिपदी)
(e) 3a2 – 2a (द्विपदी)

Bihar Board Class 7 Maths बीजीय व्यंजक Ex 9.2

Class 7 Maths Chapter 9 Exercise 9.2 Solution Bihar Board प्रश्न 1.
निम्नलिखित व्यंजको को जोड़े-
(a) 6ab + 7ab
हल :
6ab + 7ab = 13ab

(b) 8x2y + (-4x2y)
हल :
8x2y + (-4x2y) = 4x2y

(c) x एवं y – 4
हल :
x + y – 4

(d) x – y, y – z, z – z
हल :
x – y + y – z + z – x = 0

(e) 3ab – b + 3b – ab
= 3ab – ab + 3b – b
= 2ab + 2b

(f) x2 – y2, y2 – x2
हल :
x2 – y2 + y2 – x2 = 0

(g) a2 + 2ab + b2, a2 – 2ab + b2
हल :
a2 + 2ab + b2 + a2 – 2ab + b2
= 2a2 + 2b2
= 2(a2 + b2)

(h) 3x + 11 + 8z, 5x – 7
हल :
3x + 11 + 8z + 5x – 7
= 3x + 5x + 8z + 11 – 7
= 8x + 8z + 4

(i) x2 – y2 – 1, y2 – 1 – x2, 1 – x2 – y2
हल :
x2 – y2 – 1 + y2 – 1 – x2 + 1 – x2 – y2 = y2 – x2 – 1

Class 7 Math Exercise 9.2 Bihar Board प्रश्न 2.
घंटाइए-
(a) 3a2 में से (-7a2)
(b) a2 + b2 में से (a2 – b2)
(c) a2 + 2ab + b2 में से (a2 – 2ab + b2)
(d) b(8 – a) में से -{a(b – 3)}
(e) 3xy – 2x2 – 2y2 में से (5x2 – 7xy + 5y2)
हल :
(a) 3a2 – (-7a2) = 3a2 + 7a2 = 10a2
(b) a2 + b2 – (a2 – b2) = a2 + b2 – a2 + b2 = 2b2
(c) a2 + 2ab + b2 – (a2 – 2ab + b2)
= a2 + 2ab + b2 – a2 + 2ab – b2
= 4ab
(d) b(8 – a) – {a(b – 3)}
= 8b – ab – {ab – 3a}
= 8b – ab – ab + 3a
= 8b – 2ab + 3a
(e) 3xy – 2x2 – 2y2 – (5x2 – 7xy + 5y2)
= 3xy – 2x2 – 2y2 – 5x2 + 7xy – 5y2
= 10xy – 7x2 – 7y2

Class 7 Maths Exercise 9.2 Solution Bihar Board प्रश्न 3.
सरल करें-
(a) 4xy – 7x2y – 6xy + 2yz2 + 4y2z – 3yz2
(b) a2 + ab + b2 + a2 + b2 – ab + 3
हल :
(a) 4xy – 7x2y – 6xy + 2yz2 + 4y2z – 3yz2
= 4xy – 6xy – 7x2y + 2yz2 – 3yz2 + 4yz2
= -2xy – 7x2y – yz2 +4y2z

(b) a2 + ab + b2 + a2 + b2 – ab + 3
= 2a2 + 2b2 + 3

प्रश्न 4.
x2 + y2 प्राप्त करने के लिए 2x2 + y2 – 3 में क्या जोड़े
हल :
2x2 + y2 – 3 – (x2 + y2)
= 2x2 + y2 – 3 – x2 – y2
= -3

प्रश्न 5.
a + b + c प्राप्त करने के लिए 7a – 8b में क्या घटाना चाहिए-
हल :
7a – 8b – (a + b + c)
= 7a – 8b – a – b – c
= 6a – 7b – c

प्रश्न 6.
यदि सुनील ने a रु. की दर से 5 कलम b रु. की दर से 7 पेन्सिलें एवं पुनः a रु. की दर से 10 कलमें एवं b रु. की दर से 3 पेन्सिलें खरीदीं तो उसने कुल कलम एवं पेंसिल खरीदने में कितने रुपये खर्च किये?
हल :
a रु. की दर से 5 कलम = 5a
b रु. की दर से 7 पेंसिलें = 7b
a रु. की दर से 10 कलम = 10a
b रु. की दर से 3 पेंसिलें = 3b
कुल = 5a + 7b + 10a + 3b = 15a + 10b

Bihar Board Class 7 Maths बीजीय व्यंजक Ex 9.3

प्रश्न 1.
नीचे दिए गए बीजीय व्यंजकों का गुणा कीजिए-
(a) (7a + 2b) (a + 4b)
(b) (x – 6) (4x + 9)
(c) (5x – 1) (3y – 8)
(d) (a3 – b3) (a – b)
(e) (0.7x – 0.2y) (1.5x – 3y)
(f) (3a2 + 5a – 9) (3a – 9)
(g) (-x – y) (-x – y)
(h) (x2 – 5x + 8) (x2 + 3)
(i) (12𝑥−12𝑦)(𝑥′−𝑦)
(j) (3pq – 3q) (3q – 7pq)
हल :
(a) (7a + 2b) (a + 4b)
= (7a × a) + (7a × 4b) + (2b × a) + (2b × 4b)
= 7a2 + 28ab + 2ab + 8b2
= 7a2 + 30ab + 8b2

(b) (x – 6) (4x + 9)
= (x × 4x) + (x × 9) + (-6 × 4x) + (-6 × 9)
= 4x2 + 9x – 24x – 54
= 4x2 – 15x – 54

(c) (5x – 1) (3y – 8)
= (5x × 3y) + (5x × -8) + (-1 × 3y) + (-1 × -8)
= 15xy – 40x – 3y + 8

(d) (a3 – b3) (a – b)
= (a3 × a) – (a3 × b) + (-b3 × a) + (-b3 × -b)
= a4 – a3b – b3a + b4

(e) (0.7x – 0.2y) (1.5x – 3y)
= (0.7x × 1.5x) + (0.7x × -3y) + (-0.2y × 1.5x) + (0.2y × -3y)
= 0.45x2 – 2.1xy – 3xy + 0.6y2

(f) (3a2 + 5a – 9) (3a – 9)
= (3a2 × 3a) + (3a2 × -9) + (5a × 3a) + (5a × -9) + (-9 × 3a) + (-9 × -9)
= 9a3 – 27a2 + 15a2 – 45a – 27a + 81
= 9a3 – 12a2 – 72a + 81

(g) (-x – y) (-x – y)
= (-x × -x) + (-x × -y) + (-y × -x) + (-y × -y)
= x2 + xy + xy + y2
= x2 + 2xy + y2

(h) (x2 – 5x + 8) (x2 + 3)
= (x2 × x2) + (x2 × 3) + (-5x × x2) + (-5x × 3) + (8 × x2) + (8 × 3)
= x4 + 3x2 – 5x3 – 15x + 8x2 + 24
= x4 + 11x2 – 5x3 – 15x + 24

(j) (3pq – 3q) (3q – 7pq)
= (3pq × 3q) + (3pq × -7pq) + (-3q × 3q) + (-3q × -7pq)
= 9pq2 – 21p2q2 – 9q2 + 21pq2
= 30pq2 – 21p2q2 – 9q2
= 3(10pq2 – 7p2q2 – 3q2)

प्रश्न 2.
सरल करें-
(a) (a + b) (a – b) + (a – b) (a2 + ab + b2)
(b) a3 – b3 + (a + b) (a2 – ab + b2)
(c) m2 – n2 – (m – n) (m + n)
(d) (2a + 5b) (3b + 4a) – (7a + 3b) (2a + b)
हल :
(a) (a + b) (a – b) + (a – b) (a2 + ab + b2)
= (a × a) + (a × -b) + (b × a) + (b × -b)} + {(a × a2)+ (a × ab) + (a × b2) + (-b × a2) + (-b × ab) + (-b × b2)
= {a2 – ab + ab – b2} + {a3 + a2b + ab2 – ba2 – ab2 – b3}
= (a2 – b2) + (a3 – b3)

(b) a3 – b3 + (a + b) (a2 – ab + b2)
= a3 – b3 + (a × a2 + a × -ab + a × b2 + b × a2 + b × -ab + b × b2)
= a3 – b3 + a3 – a2b + ab2 + ba2 – ab2 + b3
= a3 – b3 + a3 + b3
= 2a3

(c) m2 – n2 – (m – n) (m + n)
= m2 – n2 – {m × m + m × n – n × m – n × n)
= m2 – n2 – {m2 + mn – mn – n2}
= m2 – n2 – m2 + n2
= 0

(d) (2a + 5b) (3b + 4a) – (7a + 3b) (2a + b)
= {2a × 3b + 2a × 4a + 5b × 3b + 5b × 4a} – {7a × 2a + 7a × b + 3b × 2a + 3b × b}
= {6ab + 8a2 + 15b2 + 20ab} – {14a2 + 7ab + 6ab + 3b2}
= 6ab + 8a2 + 15b2 + 20ab – 14a2 – 7ab – 6ab – 3b2
= 8a2 – 14a2 + 15b2 – 3b2 + 20ab – 7ab
= -6a2 + 12b2 + 13ab

Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक Textbooks for Exam Preparations

Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक Textbook Solutions can be of great help in your Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक exam preparation. The BSEB STD 7th Maths Chapter 9 बीजीय व्यंजक Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 7th Maths Chapter 9 बीजीय व्यंजक Books State Board syllabus with maximum efficiency.

FAQs Regarding Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक Textbook Solutions

Can we get a Bihar Board Book PDF for all Classes?

Yes you can get Bihar Board Text Book PDF for all classes using the links provided in the above article.

Important Terms

Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक, BSEB Class 7th Maths Chapter 9 बीजीय व्यंजक Textbooks, Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक, Bihar Board Class 7th Maths Chapter 9 बीजीय व्यंजक Textbook solutions, BSEB Class 7th Maths Chapter 9 बीजीय व्यंजक Textbooks Solutions, Bihar Board STD 7th Maths Chapter 9 बीजीय व्यंजक, BSEB STD 7th Maths Chapter 9 बीजीय व्यंजक Textbooks, Bihar Board STD 7th Maths Chapter 9 बीजीय व्यंजक, Bihar Board STD 7th Maths Chapter 9 बीजीय व्यंजक Textbook solutions, BSEB STD 7th Maths Chapter 9 बीजीय व्यंजक Textbooks Solutions,
Share: