AP Board Class 7 Maths Chapter 5 Triangle and Its Properties Ex 4 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Book Answers ~ HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

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AP Board Class 7 Maths Chapter 5 Triangle and Its Properties Ex 4 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Book Answers

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AP Board Class 7 Maths Chapter 5 Triangle and Its Properties Ex 4 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Book Answers

AP Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Textbooks Solutions and answers for students are now available in pdf format. Andhra Pradesh Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Book answers and solutions are one of the most important study materials for any student. The Andhra Pradesh State Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 books are published by the Andhra Pradesh Board Publishers. These Andhra Pradesh Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 textbooks are prepared by a group of expert faculty members. Students can download these AP Board STD 7th Maths Chapter 5 Triangle and Its Properties Ex 4 book solutions pdf online from this page.

Andhra Pradesh Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Textbooks Solutions PDF

Andhra Pradesh State Board STD 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Textbooks. These Andhra Pradesh State Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.

Andhra Pradesh State Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Books Solutions

Board	AP Board
Materials	Textbook Solutions/Guide
Format	DOC/PDF
Class	7th
Subject	Maths
Chapters	Maths Chapter 5 Triangle and Its Properties Ex 4
Provider	Hsslive

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AP Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Question 1.
In ΔABC, name all the interior and exterior angles of the triangle.

Solution:
Interior angles
∠ABC, ∠BAC, ∠CAB
Exterior angles
∠ACZ, ∠BAY and ∠CBX

Question 2.
For ΔABC, find the measure of ∠ACD.

Solution:
In ΔABC,
∠ACD = ∠BAC + ∠ABC (exterior angle property)
=66° + 45° = 111°.

Question 3.
Find the measure of angles x and y.

Solution:
In the figure,
x° + 65° = 180° (lInear pair of an1es)
∴ x°= 180°- 65°= 115°
Also y° + 30° = 65° (exterior angle property)
y° = 65° – 30° = 35°

Question 4.
In the following figures, fmd the values of x and y.

Solution:
In ΔABC,
107° = x° + 57° (exterIor angle property)
∴ x° = 107° – 57° =50°
In ΔADC,
∠CAD + ∠ADC + ∠ACD = 180° (angle – sum property)
40° + 107°+ x°= 180°
∴ x° = 180° – 147° = 33°
Also in ΔABC,
∠A +∠B +∠C = 180°
40° + ∠B + (33° + 65°) = 180°
∠B + 138° = 180°
B = 180° – 138° = 42°
Now y° = ∠A + ∠B for ΔABC (exterior angle property)
=40° + 42° = 82°

Question 5.
In the figure ∠BAD = 3 ∠DBA, find ∠CDB. ∠DBC and ∠ABC.

Solution:
In ΔBCD,
∠DBC + ∠BCD = ∠BDA (exterior angle property)
∠DBC + 65° -104°
∴ ∠DBC = 104° – 65° = 39°
Also ∠BDA + ∠BDC = 180° (linear pair of angles)
104° + ∠BDC = 180°
∠CDB or ∠BDC = 180° – 104° = 76°
Now in ΔABD,
∠BAD + ∠ADB + ∠DHA = 180°
3∠DBA + ∠DBA + 104° = 180° (given)
4∠DBA + 104° – 180°
∴ 4∠DBA = 180° – 104°= 76°
∴∠DBA = 76∘4 = 19°
Now ∠ABC = ∠DBA + ∠DBC = 19° + 39° = 58°

Question 6.
Find the values of x and y in the following figures.

Solution:
i) In the figure the angles are
70°, x°, x° (angles in an Isosceles triangle)
Also 70° + x° + x° = 180° (angle – sum property)
2x° + 70°= 180°
2x° = 180° – 70° [∵ y° = x°]
2x° = 110°
x°= 110∘2 = 55°

ii) From the figure,
the Interior opposite angles of x are 50°, 500 (angles in an isosceles triangle )
50° + 50° = x° (exterior angle is equal to sum of the Interior opposite angles)
∴ x = 100°

iii) From the figure,
y° = 30° (vertically opposite angles)
ALso y = x° – 30° (equal angles of an Isosceles triangles)
∴ x° = 30° and y = 30°

iv) From the figure,
a + 110° = 180° (linear pair of angles)
∴ a = 180° – 110°= 70
Also y° = a° = 70° (equal angles of an isosceles triangle)
x + y + a = 180 (sum of interior angles)
x + 70 + 70 = 180
x + 140 = 180
x = 180 – 40 = 40°, ∴ x = 40°

v) From the figure,
30° + y° – 180°
y° = 180° – 30° = 150°
Also x° + a° = y° (exterior angle property)
x° + 90° = 150°
x° = 150° – 90° = 60°

vi) From the figure,
b = 80° (vertically opposite angles)
Also x° = a° (equal angles of an isosceles triangle.)
° 80° + x° + a° = 180
80 + x° + x° = 180
2x° = 180° – 80° =100°
2x° = 100°
∴ x° = 1002 = 50°
Now y = x° b° (exterior angle property)
50° + 80° = 130°

Question 7.
One of the exterior angles of a triangle is 125° and the interior opposite angles are in the
ratio 2 :3. Find the angles of the triangle.
Solution:
Ratio of the interior opposite angles = 2 : 3
Sum of the terms of the ratio = 2 + 3 = 5
Sum of the interior angles exterior angle = 125°
∴ First angle = 25 x 125° = 500
Second angle = 35 x 125° = 75°

Question 8.
The exterior ∠PRS of ∆PQR is 105°. If Q = 70°. find ∠P. Is ∠PRS > ∠P?
Solution:

∠P+ ∠Q = ∠PRS (exterior angle is equal to sum of the interior opposite angles)
∠P + 70° = 105°
∠P = 105° – 70° = 35°
Now ∠PRS > ∠P.

Question 9.
If an exterior angle of a triangle is 130° and one of the interior opposite angle is 6. Find
the other interior opposite angle.
Solution:
Let the other interi6r opposite angle be = x°
Give interior opposite angle be = 60°
Now sum of the interior opposite angle = exterior angLe
x° + 60° = 130°
x° = 130° – 60° = 70°
∴ The other interior opposite angle = 70°

Question 10.
One of the exterior angle ofa triangle is 105° and the interior opposite angles are in the ratio 2 : 5. Find the angles of the triangle.
Solution:
Ratio of interior opposite angles = 2 : 5
Sum of the terms of the ratio = 2 + 5 = 7
Sum of the angles = 105°
∴ 1st angle = 27 x 105° = 30°
2nd angIe = 57 x 105° = 75°
3rd angle = 180° – (30° + 75°) [∵ angle – sum property]
= 180° – (105°) = 75°

Question 11.
In the figure find the values of x andy.
Solution:

From the figure,
∠y = 50° + 30° = 80° (exterior angle property)
∠x = y° + 55° (exterior angle property)
= 80° + 55°
= 135°

AP Board Textbook Solutions PDF for Class 7th Maths

Andhra Pradesh Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Textbooks for Exam Preparations

Andhra Pradesh Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 exam preparation. The AP Board STD 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 7th Maths Chapter 5 Triangle and Its Properties Ex 4 Books State Board syllabus with maximum efficiency.

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Wednesday, October 19, 2022