AP Board Class 7 Maths Chapter 3 Simple Equations Ex 3 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 3 Simple Equations Ex 3 Book Answers ~ HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

Wednesday, October 19, 2022

AP Board Class 7 Maths Chapter 3 Simple Equations Ex 3 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 3 Simple Equations Ex 3 Book Answers

October 19, 2022 AP Board 7 Maths Solutions No comments

AP Board Class 7 Maths Chapter 3 Simple Equations Ex 3 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 3 Simple Equations Ex 3 Book Answers

AP Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbooks Solutions and answers for students are now available in pdf format. Andhra Pradesh Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Book answers and solutions are one of the most important study materials for any student. The Andhra Pradesh State Board Class 7th Maths Chapter 3 Simple Equations Ex 3 books are published by the Andhra Pradesh Board Publishers. These Andhra Pradesh Board Class 7th Maths Chapter 3 Simple Equations Ex 3 textbooks are prepared by a group of expert faculty members. Students can download these AP Board STD 7th Maths Chapter 3 Simple Equations Ex 3 book solutions pdf online from this page.

Andhra Pradesh Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbooks Solutions PDF

Andhra Pradesh State Board STD 7th Maths Chapter 3 Simple Equations Ex 3 Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 7th Maths Chapter 3 Simple Equations Ex 3 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 7th Maths Chapter 3 Simple Equations Ex 3 Textbooks. These Andhra Pradesh State Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.

Andhra Pradesh State Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Books Solutions

Board	AP Board
Materials	Textbook Solutions/Guide
Format	DOC/PDF
Class	7th
Subject	Maths
Chapters	Maths Chapter 3 Simple Equations Ex 3
Provider	Hsslive

How to download Andhra Pradesh Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbook Solutions Answers PDF Online?

Visit our website - Hsslive
Click on the Andhra Pradesh Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Answers.
Look for your Andhra Pradesh Board STD 7th Maths Chapter 3 Simple Equations Ex 3 Textbooks PDF.
Now download or read the Andhra Pradesh Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbook Solutions for PDF Free.

AP Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Question 1.
Write the information given in the picture in the form of an equation. Also, find ‘x’ in the following figure.

Solution:
From the figure x + 11 = 15
∴ x = 15 – 11 (transposing +11)
∴ x = 4cm

Question 2.
Write the information given in the picture in the form of an equation. Also, find ‘y in the following figure.

Solution:
From the figure y + 8 = 13
y = 13 – 8 (transposing 8)
∴ y = 5cm

Question 3.
If we add 7 to twice a number, we get 49. Find the number.
Solution:
Let the number be x
Then twice the number = 2x
Onaddingi = 2x + 7
By problem, 2x + 7 = 49
2x = 49 – 7 (transposing + 7)
2x = 42
x = 422 (transposing x 2)
x = 21

Question 4.
If we subtract 22 from three times a number, we get 68. Find the number.
Solution:
Let the number be x
Then three times the number = 3x
On subtracting 22 ⇒ 3x – 22
By problem, 3x – 22 = 68
3x = 68 + 22 (transposing -22)
3x = 90
x = 903(transposingx3)
x = 30
∴ The required number 30

Question 5.
Find a number which when multiplied by 7 and then reduced by 3 is equal to 53.
Solution:
Let the number be x
Multiplied by 7 ⇒ 7x
Then reduced by 3 ⇒ 7x – 3
By problem, 7x – 3 = 53
7x = 53 + 3 (transposing – 3)
7x = 56
x = 567 (transposing x 7)
x = 8 .
∴ The required number = 8

Question 6.
Sum of two numbers is 95. 1f one exceeds the other by 3, find the numbers.
Solution:
Let one number be = x.
Then the other number x – 3
Sumofthenumbers x + x – 3 = 2x – 3
By problem, 2x – 3 = 95
2x = 95 + 3 (transposing – 3)
2x = 98
x = 982 (transposing x 2)
x = 49
∴if one number x 49 then the other number x – 3 = 49 – 3 = 46

Question 7.
Sum of three consecutive integers is 24. Find the integers.
Solution:
Let the three integers be = x, x + 1, x 2
Sumoftheintegers = x + x + 1 + x + 2 = 3x + 3
By problem, 3x + 3 = 24’
3x = 24 – 3 (Transposing + 3)
3x = 21
x = 213 (transposing x 3)
x = 7
∴ The integers x = 7
x + 1 = 7 + 1 = 8
x + 2 = 7 + 2 = 9

Question 8.
Find the length and breadth of the rectangle given below if its perimeter is 72m.

Solution:
Length of the rectangle = 5x + 4
Breadth of the rectangLe = x – 4
Perimeter of the rectangle = 2 x (length + breadth)
= 2x[(5x + 4)+(x – 4)]
= 2[5x + 4 + x – 4]
= 2(6x)
= 12x
Byproblem, 12x = 72
x = 7212 (transposing x 12)
x = 6
∴ Length of the rectangle = 5x + 4 = 5 x 6.4 = 34cm
Breadth of the rectangÌe = x – 4 = 6 – 4 = 2cm

Question 9.
Length of a rectangle exceeds its breadth by 4 m. 1f the perimeter of the rectangle is 84 m, find its length and breadth.
Solution:
Let the breadth be x
Then its length = x + 4
Perimeter of the rectangle = 2 x (length + breadth)
=2[x + 4 + x]
= 2 (2x + 4)
= 4x + 8
By problem, 4x + 8 = 84
4x = 84 – 8 (transposing + 8)
4x = 76
x = 764 (transposing x 4)
x = 19
∴ Length of the rectangle =x+4= 19+4 = 23m
Breadth of the rectangle = 19m

Question 10.
After 15 years, Hema’s age will become four times that of her present age. Find her present age.
Solution:
Let the preser age of Hema be x years
After 15 years Hema Age = 4x
By problem, x + 15 = 4x
x + 15 – 4x = 4x – 4x (Subtracting 4x from both sides)
– 3x + 15 = 0
– 3x = – 15
x = −15−3 transposing x ( – 3)]
x = 5
∴ Her present age is 5 years.
∴ Her present age is 5 years.

Question 11.
A sum of ₹.3000 is to be given in the form of 63 prizes. Ifthe prize money is either ₹. 100 or.25. Find the number of prizes of each type.
Solution:
Let the number of ₹ 100 prizes be x
Then the number of ₹ 25 prizes be = 63 – x
Value of the prizes = 100x + (63 – x) x 25
= 100x+ 1575 – 25x
= 75x + 1575
By problem, 75x + 1575 = 3000
75x = 3000 – 1575
75x = 1425
x = 142575
x = 19
∴ ₹ 100 prizes = 19
₹25 prizes= 63 – x =63 – 19 = 44

Question 12.
A number is divided into two parts such that one part is 10 more than the other. Ifthe two parts are in the ratio 5:3, find the number and the two parts.
Solution:
Let one part be x
Then the other part = x + 10
Ratio of these two parts = x + 10 : x
Byproblem, x + 10 : x=5:3
∴ 𝑥+10𝑥=53
3(x+ 10)=5x
3x + 30 = 5x
30 = 5x – 3x
2x = 30
x = 302
x = 15
If one part is 15 then the other part must be x + 10 = 15 + 10 = 25
∴ The number is 15 + 25 40

Question 13.
Suhana said, “multiplying my number by 5 and adding 8 to it gives the same answer as subtracting my number from 20”. Find Suhana’s numbers.
Solution:
Let Suhana’s number be x
Muhtplying by S and adding 8 to that number 5x + 8
Subtracting that number from 20 = 20 – x
By problem above two are equal.
i.e. 5x + 8 = 20 – x
5x + x = 20 – 8
6x = 12
x = 126 = 2
x = 2
∴ Suhanas number is 2

Question 14.
The teacher tells the class that the highest marks obtained by a student in her class is twice the lowest marks plus 7. The highest mark is 87. What is the lowest mark?
Solution:
Let the Lowest mark of the class=x
Twice the least mark = 2x
On adding 7 = 2x + 7
By problem; 2x + 7 = 87
2x = 87 – 7
2x = 80
x = 802 = 40
x = 40
∴ The lowest mark = 40

Question 15.
In adjacent figure find the magnitude of each of the three angles formed?
(Hint: Sum of all angles at a point on a line is 180°)
Solution:
(Hint : Sum of all angles at a point on a line is 180°)

We know sum of angles at a point = 180°
∴ x° + 2x° + 3x° = 180
6x° = 180°
x = 1806 = 30
∴ The angles are x = 30°
2x = 2 x 30 = 60°
3x° = 3 x 30° = 90°

Question 16.
Solve the following riddle:
I am a number
Tell my identity
Take me two times over
And add a thirty six.
To reach a century
Solution:
Let the number be x
Two times the number = 2x
On adding 36 = 2x 36
By problem, 2x + 36 = 100 – 4
2x 36 = 96
2x = 96 – 36
2x = 602
x = 30

AP Board Textbook Solutions PDF for Class 7th Maths

Andhra Pradesh Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbooks for Exam Preparations

Andhra Pradesh Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 7th Maths Chapter 3 Simple Equations Ex 3 exam preparation. The AP Board STD 7th Maths Chapter 3 Simple Equations Ex 3 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 7th Maths Chapter 3 Simple Equations Ex 3 Books State Board syllabus with maximum efficiency.

FAQs Regarding Andhra Pradesh Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbook Solutions

How to get AP Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbook Answers??

Students can download the Andhra Pradesh Board Class 7 Maths Chapter 3 Simple Equations Ex 3 Answers PDF from the links provided above.

Can we get a Andhra Pradesh State Board Book PDF for all Classes?

Yes you can get Andhra Pradesh Board Text Book PDF for all classes using the links provided in the above article.

Important Terms

Andhra Pradesh Board Class 7th Maths Chapter 3 Simple Equations Ex 3, AP Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbooks, Andhra Pradesh State Board Class 7th Maths Chapter 3 Simple Equations Ex 3, Andhra Pradesh State Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbook solutions, AP Board Class 7th Maths Chapter 3 Simple Equations Ex 3 Textbooks Solutions, Andhra Pradesh Board STD 7th Maths Chapter 3 Simple Equations Ex 3, AP Board STD 7th Maths Chapter 3 Simple Equations Ex 3 Textbooks, Andhra Pradesh State Board STD 7th Maths Chapter 3 Simple Equations Ex 3, Andhra Pradesh State Board STD 7th Maths Chapter 3 Simple Equations Ex 3 Textbook solutions, AP Board STD 7th Maths Chapter 3 Simple Equations Ex 3 Textbooks Solutions,

HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

Hsslive.co.in: Kerala Higher Secondary News, Plus Two Notes, Plus One Notes, Plus two study material, Higher Secondary Question Paper.

Wednesday, October 19, 2022