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## AP Board Class 7 Maths Chapter 6 Ratio Applications Ex 5 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 6 Ratio Applications Ex 5 Book Answers

 AP Board Class 7 Maths Chapter 6 Ratio Applications Ex 5 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 6 Ratio Applications Ex 5 Book Answers

## Andhra Pradesh State Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Books Solutions

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## AP Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Question 1.
A shopkeeper bought a suit case for ₹ 480 and sold it for ₹ 540. Find his gain percent?
Solution:
C.P of the suitcase = ₹ 480
SP of the suitcase = ₹ 540
∴ gain=S,P-C.P = 540 – 480 = ₹ 60
∴ gain percent = 60450 × 100% = 12.5%

Question 2.
Ajay bought a TV for ₹ 15000 and sold it for ₹141 00. Find the loss percent?
Solution:
C.P of the TV = ₹ 15,000
S.P of the TV = ₹ 14100
As S.P < C.P
Loss = C.P – S.P= 15,000 – 14,100 = ₹ 900
∴ Loss percent = 90015000 × 100 = 6%

Question 3.
Ramu sold a plot of land for ₹ 2,40,000 gaining 20%. For how much did he purchase the plot?
Solution:
Let the cost price of the land = ₹ x
gain percent = 20% of the C.P
∴ S.P of the land = 120% of C.P
By problem, 120% of x = 2,40,000
120.𝑥100 = 2,40,000
x = 2.40000 × 100120
= ₹ 2,00,000

(OR)

Let the C.P of the land = ₹ x
gain percent = 20% of C.P = 20% of x = 20x100
∴ S.P of the land = C.P + gain
= x + 20x100
= 100𝑥+20𝑥100=120𝑥100

By problem, 20x100 = 2,40.000
∴ x = 24000 x 100120
= ₹ 2,00,000

Question 4.
On selling a mobile for ₹ 750, a shop keeper looses 10%. For what amount should he sell it to gain 5%?
Solution:
Let the C.P of the mobile be x
Losspercent = 10% of C.P = 10% of x = 10x100
∴ Loss = 10𝑥100
∴ S.P = C.P – Loss
= 𝑥–10𝑥100=100𝑥−10𝑥100=90𝑥100

By problem, 90x100 = 750
x = 750 × 10090 = ₹ 25003
Now to gain by 5% the S.P = C.P + 5% of C.P

Question 5.
A farmer sold 2 bullocks for ₹ 24000 each. On one bullock he gained 25% and on the other he lost 20%. Find his total profit or loss percent?
Solution:
Let the C.P of first bullock be x
gain = 25% of x = 25 × 𝑥100=25𝑥100
S.P = C.P + gain = x + 25𝑥100=100𝑥+25𝑥100=125𝑥100
Selling price of first bullock 24,000 (given)
125𝑥100 = 24000
x = 24000125 × 100
∴ C.P of first bullock = ₹ 19.200
Let the C.P of second bullock be y
Loss percent = 20%

∴Loss = 20×y100=20y100

S.P = C.P – loss
= 𝑦−20𝑦100=100𝑦−20𝑦100=80𝑦100

But S.P = ₹ 24,000 (given)
80y100 = 24,000
∴ y = 24000 x 10080 = 30,000

∴ C.P of second bullock = ₹ 30,000
C.P of 2 bullocks = ₹19,200 + ₹30,000
= ₹ 49,200
S.P of 2 bullocks ₹24,000 × 2 = ₹48,000
Loss = C.P – S.P = 49,200 – 48,000 = ₹1200
Loss % =  loss  CP  × 100
= 120049200 × 100 = 2.4
∴ Loss% = 2.4%

Question 6.
Sravya bought a watch for ₹480. She sold it to Ridhi at a gain of 614 %. Ridhi sold it to Divya at a gain of 10%. How much did Divya pay for it?
Solution:
CF of the watch = ₹ 480
Gain% = 614%=254%
Gain = 480 × 254 x 1100 = 30
C.P of the watch for Ridhi = 480 + 30 = ₹ 510
Gain% = 10%
∴ Gain= 51% × 10100 = 51
S.P of the watch for Ridhi = 510 + 51 = ₹561
∴ Amount paid for Divya for the watch = ₹561

Question 7.
The marked price of a book is ₹225.Thc publisher allows a discount of ₹10% on it. Find the selling price of it?
Solution:
The marked price of the book = ₹ 225
Discount 10%
∴ Discount = 225 × 10100= ₹ 22.5
S.P = M.P – discount
= 225 – 22.5 = ₹202.5
∴ Selling price of the book = ₹ 202.5

Question 8.
A carpenter allows 15% discount on his goods. Find the marked price of a chair which is sold by him for ₹680?
Solution:
Let the marked price of chair be ₹x
Discount = 15% = x × 15100=15𝑥100
S.P = M.P – discount
𝑥−15𝑥100=100𝑥−15𝑥100=85𝑥100
S.P = ₹ 680 (given)
∴ 85x100 = 680
x = 680×10085 = 800
Marked price of the chair = ₹ 800

Question 9.
A dealer allows a discount of ₹ 10% and still gains by 10%. What should be the marked price if the cost price is ₹900?
Solution:
Given that C.P = 900
There is a gain of 10% on C.P
∴ Gain = 10% of ₹ 900
= 10×900100 = ₹ 90
∴ S.P = C.P . gain
= 900 + 90
S.P = ₹990 …………….. (1)
Let the marked price = ₹ x
Discount on it = 10% on M.P = 10x100
∴ Selling Price = MP – Discount
= x – 10x100
= 100𝑥−10𝑥100
∴ S.P = 90x100 …………….(2)
From (1) & (2) 90x100 = 990
∴ x = 990 x 10090
∴ M.P = x = ₹1100

## Andhra Pradesh Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Textbooks for Exam Preparations

Andhra Pradesh Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 exam preparation. The AP Board STD 7th Maths Chapter 6 Ratio Applications Ex 5 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 7th Maths Chapter 6 Ratio Applications Ex 5 Books State Board syllabus with maximum efficiency.

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