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AP Board Class 7 Maths Chapter 6 Ratio Applications Ex 5 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 6 Ratio Applications Ex 5 Book Answers

AP Board Class 7 Maths Chapter 6 Ratio Applications Ex 5 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 6 Ratio Applications Ex 5 Book Answers
AP Board Class 7 Maths Chapter 6 Ratio Applications Ex 5 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 6 Ratio Applications Ex 5 Book Answers


AP Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Textbooks Solutions and answers for students are now available in pdf format. Andhra Pradesh Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Book answers and solutions are one of the most important study materials for any student. The Andhra Pradesh State Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 books are published by the Andhra Pradesh Board Publishers. These Andhra Pradesh Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 textbooks are prepared by a group of expert faculty members. Students can download these AP Board STD 7th Maths Chapter 6 Ratio Applications Ex 5 book solutions pdf online from this page.

Andhra Pradesh Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Textbooks Solutions PDF

Andhra Pradesh State Board STD 7th Maths Chapter 6 Ratio Applications Ex 5 Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 7th Maths Chapter 6 Ratio Applications Ex 5 Textbooks. These Andhra Pradesh State Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.

Andhra Pradesh State Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Books Solutions

Board AP Board
Materials Textbook Solutions/Guide
Format DOC/PDF
Class 7th
Subject Maths
Chapters Maths Chapter 6 Ratio Applications Ex 5
Provider Hsslive


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AP Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Question 1.
A shopkeeper bought a suit case for ₹ 480 and sold it for ₹ 540. Find his gain percent?
Solution:
C.P of the suitcase = ₹ 480
SP of the suitcase = ₹ 540
∴ gain=S,P-C.P = 540 – 480 = ₹ 60
∴ gain percent = 60450 × 100% = 12.5%

Question 2.
Ajay bought a TV for ₹ 15000 and sold it for ₹141 00. Find the loss percent?
Solution:
C.P of the TV = ₹ 15,000
S.P of the TV = ₹ 14100
As S.P < C.P
Loss = C.P – S.P= 15,000 – 14,100 = ₹ 900
∴ Loss percent = 90015000 × 100 = 6%

Question 3.
Ramu sold a plot of land for ₹ 2,40,000 gaining 20%. For how much did he purchase the plot?
Solution:
Let the cost price of the land = ₹ x
gain percent = 20% of the C.P
∴ S.P of the land = 120% of C.P
By problem, 120% of x = 2,40,000
120.𝑥100 = 2,40,000
x = 2.40000 × 100120
= ₹ 2,00,000

(OR)

Let the C.P of the land = ₹ x
gain percent = 20% of C.P = 20% of x = 20x100
∴ S.P of the land = C.P + gain
= x + 20x100
= 100𝑥+20𝑥100=120𝑥100

By problem, 20x100 = 2,40.000
∴ x = 24000 x 100120
= ₹ 2,00,000

Question 4.
On selling a mobile for ₹ 750, a shop keeper looses 10%. For what amount should he sell it to gain 5%?
Solution:
Let the C.P of the mobile be x
Losspercent = 10% of C.P = 10% of x = 10x100
∴ Loss = 10𝑥100
∴ S.P = C.P – Loss
= 𝑥–10𝑥100=100𝑥−10𝑥100=90𝑥100

By problem, 90x100 = 750
x = 750 × 10090 = ₹ 25003
Now to gain by 5% the S.P = C.P + 5% of C.P

Question 5.
A farmer sold 2 bullocks for ₹ 24000 each. On one bullock he gained 25% and on the other he lost 20%. Find his total profit or loss percent?
Solution:
Let the C.P of first bullock be x
gain = 25% of x = 25 × 𝑥100=25𝑥100
S.P = C.P + gain = x + 25𝑥100=100𝑥+25𝑥100=125𝑥100
Selling price of first bullock 24,000 (given)
125𝑥100 = 24000
x = 24000125 × 100
∴ C.P of first bullock = ₹ 19.200
Let the C.P of second bullock be y
Loss percent = 20%

∴Loss = 20×y100=20y100

S.P = C.P – loss
= 𝑦−20𝑦100=100𝑦−20𝑦100=80𝑦100

But S.P = ₹ 24,000 (given)
80y100 = 24,000
∴ y = 24000 x 10080 = 30,000

∴ C.P of second bullock = ₹ 30,000
C.P of 2 bullocks = ₹19,200 + ₹30,000
= ₹ 49,200
S.P of 2 bullocks ₹24,000 × 2 = ₹48,000
Loss = C.P – S.P = 49,200 – 48,000 = ₹1200
Loss % =  loss  CP  × 100
= 120049200 × 100 = 2.4
∴ Loss% = 2.4%

Question 6.
Sravya bought a watch for ₹480. She sold it to Ridhi at a gain of 614 %. Ridhi sold it to Divya at a gain of 10%. How much did Divya pay for it?
Solution:
CF of the watch = ₹ 480
Gain% = 614%=254%
Gain = 480 × 254 x 1100 = 30
C.P of the watch for Ridhi = 480 + 30 = ₹ 510
Gain% = 10%
∴ Gain= 51% × 10100 = 51
S.P of the watch for Ridhi = 510 + 51 = ₹561
∴ Amount paid for Divya for the watch = ₹561

Question 7.
The marked price of a book is ₹225.Thc publisher allows a discount of ₹10% on it. Find the selling price of it?
Solution:
The marked price of the book = ₹ 225
Discount 10%
∴ Discount = 225 × 10100= ₹ 22.5
S.P = M.P – discount
= 225 – 22.5 = ₹202.5
∴ Selling price of the book = ₹ 202.5

Question 8.
A carpenter allows 15% discount on his goods. Find the marked price of a chair which is sold by him for ₹680?
Solution:
Let the marked price of chair be ₹x
Discount = 15% = x × 15100=15𝑥100
S.P = M.P – discount
𝑥−15𝑥100=100𝑥−15𝑥100=85𝑥100
S.P = ₹ 680 (given)
∴ 85x100 = 680
x = 680×10085 = 800
Marked price of the chair = ₹ 800

Question 9.
A dealer allows a discount of ₹ 10% and still gains by 10%. What should be the marked price if the cost price is ₹900?
Solution:
Given that C.P = 900
There is a gain of 10% on C.P
∴ Gain = 10% of ₹ 900
= 10×900100 = ₹ 90
∴ S.P = C.P . gain
= 900 + 90
S.P = ₹990 …………….. (1)
Let the marked price = ₹ x
Discount on it = 10% on M.P = 10x100
∴ Selling Price = MP – Discount
= x – 10x100
= 100𝑥−10𝑥100
∴ S.P = 90x100 …………….(2)
From (1) & (2) 90x100 = 990
∴ x = 990 x 10090
∴ M.P = x = ₹1100


AP Board Textbook Solutions PDF for Class 7th Maths


Andhra Pradesh Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Textbooks for Exam Preparations

Andhra Pradesh Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 exam preparation. The AP Board STD 7th Maths Chapter 6 Ratio Applications Ex 5 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 7th Maths Chapter 6 Ratio Applications Ex 5 Books State Board syllabus with maximum efficiency.

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How to get AP Board Class 7th Maths Chapter 6 Ratio Applications Ex 5 Textbook Answers??

Students can download the Andhra Pradesh Board Class 7 Maths Chapter 6 Ratio Applications Ex 5 Answers PDF from the links provided above.

Can we get a Andhra Pradesh State Board Book PDF for all Classes?

Yes you can get Andhra Pradesh Board Text Book PDF for all classes using the links provided in the above article.

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