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AP Board Class 6 Maths Chapter 10 Practical Geometry Ex 10.4 Textbook Solutions PDF: Download Andhra Pradesh Board STD 6th Maths Chapter 10 Practical Geometry Ex 10.4 Book Answers

 AP Board Class 6 Maths Chapter 10 Practical Geometry Ex 10.4 Textbook Solutions PDF: Download Andhra Pradesh Board STD 6th Maths Chapter 10 Practical Geometry Ex 10.4 Book Answers

Andhra Pradesh State Board Class 6th Maths Chapter 10 Practical Geometry Ex 10.4 Books Solutions

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AP Board Class 6th Maths Chapter 10 Practical Geometry Ex 10.4 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 6th Maths Chapter 10 Practical Geometry Ex 10.4 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Question 1.
Construct ∠ABC = 60° without using protractor.
Solution:
Steps of construction :

1. Draw a line l and mark a point B on it.
2. Place the pointer of the compasses at B and draw an arc of convenient radius which cuts the line l at a point C.
3. With the pointer at C as centre and with the same radius as above. Now draw an arc that passes through B.
4. Cut intersecting point of two arcs is A. Join BA. ∠ABC = 60° is formed.
Hence the required angle ∠ABC = 60° is constructed.

Question 2.
Construct an angle of 120° with using protractor and compasses.
Solution:
Steps of construction :

1. Draw a ray OA⎯⎯⎯⎯⎯⎯⎯⎯⎯ of any length.
2. Place the pointer of the compasses at O. With O as centre and any convenient radius draw an arc cutting OA at M.
3. With M as centre and without altering radius draw an arc which cuts the previous arc at P.
4. With P as centre and without changing radius draw an arc which cuts the first arc at Q.
5. Join OQ. Then ∠AOQ is the required angle.
Hence the required angle ∠AOQ = 120° is constructed.

Question 3.
Construct the following angles using ruler and compasses. Write the steps of construction in each case.
i) 75°
ii) 15°
iii) 105°
Solution:
i) 75°
Steps of construction:

1. Construct ∠RAM 900
2. Construct ∠PAM = 600 AM as common arm
3. Now, ∠PAR = ∠RAM – ∠PAM = 90° – 60° = 30°
4. Draw bisector to ∠PAR which is AQ−→−.
5. Now, ∠MAQ = ∠PAM + ∠PAQ = 60° + 302
= 60° + 15° = 75° (QED)

ii) 15°
Steps of construction:

1. Construct ∠BQR = 60°
2. Draw the bisector to ∠BQR which is QC−→−
3. Now,∠CQR = 602 = 30°
4. Draw the bisector QP−→ to∠CQR.
5. ∠PQR = 12 x 30° = 15° (Q.E.D)

iii) 105°
Steps of construction :

1. Construct ∠IDS = 90°
2. Construct ∠ADS = RDS2=302 = 15°

Andhra Pradesh Board Class 6th Maths Chapter 10 Practical Geometry Ex 10.4 Textbooks for Exam Preparations

Andhra Pradesh Board Class 6th Maths Chapter 10 Practical Geometry Ex 10.4 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 6th Maths Chapter 10 Practical Geometry Ex 10.4 exam preparation. The AP Board STD 6th Maths Chapter 10 Practical Geometry Ex 10.4 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 6th Maths Chapter 10 Practical Geometry Ex 10.4 Books State Board syllabus with maximum efficiency.

FAQs Regarding Andhra Pradesh Board Class 6th Maths Chapter 10 Practical Geometry Ex 10.4 Textbook Solutions

Can we get a Andhra Pradesh State Board Book PDF for all Classes?

Yes you can get Andhra Pradesh Board Text Book PDF for all classes using the links provided in the above article.

Important Terms

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