# HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

## AP Board Class 6 Maths Chapter 11 Perimeter and Area Ex 11.3 Textbook Solutions PDF: Download Andhra Pradesh Board STD 6th Maths Chapter 11 Perimeter and Area Ex 11.3 Book Answers AP Board Class 6 Maths Chapter 11 Perimeter and Area Ex 11.3 Textbook Solutions PDF: Download Andhra Pradesh Board STD 6th Maths Chapter 11 Perimeter and Area Ex 11.3 Book Answers

## Andhra Pradesh State Board Class 6th Maths Chapter 11 Perimeter and Area Ex 11.3 Books Solutions

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## AP Board Class 6th Maths Chapter 11 Perimeter and Area Ex 11.3 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 6th Maths Chapter 11 Perimeter and Area Ex 11.3 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Question 1.
Find the area of the rectangle of measurements 15 cm and 8 cm as length and breadth respectively.
Solution:
Given length of the rectangle l = 15 cm
breadth of the rectangle b = 8 cm
Area of the rectangle A = l x b
= 15 x 8 = 120 sq.cm

Question 2.
Find the area of a square whose perimeter is 64 m.
Solution:
Given perimeter of a square = 4 x side = 64 m
Divide with 4 on both sides,
Undefined control sequence \operatorname
side (s) = 16 m
Area of the square = s.s = 16xl6 = 256 sq.m

Question 3.
Perimeters of a rectangle and square are equal. If the length of the rectangle is 14 cm and the perimeter of the square is 44 cm, find the area of the rectangle.
Solution:
Given the length of the rectangle l = 14 cm
breadth of the rectangle b = ?
Perimeter of the square = 44 cm
Given perimeter of the rectangle = Perimeter of the square ‘
2(l + b) = 44
2(14 + b) = 44
Divide with 2 on both sides,
2(14+𝑏)2=442
14 + b = 22
Subtract 14 on both sides,
14 + b – 14 = 22 – 14
Breadth of the rectangle b = 8 cm
Area of the rectangle = l x b = 14 x 8 = 112 sq. cm

Question 4.
Find the perimeters and areas of the following and answer the questions.
A) A rectangle with length and breadth as 16 cm and 8 cm respectively.
B) A rectangle with length and breadth as 14 cm and 10 cm respectively.
C) A square with side 12 cm.
(i) Which of the above perimeters are equal ?
(ii) Are all these areas equal? If not, which one has the bigger area?
Solution:
A) Given length of the rectangle l =16 cm
– Breadth of the rectangle b = 8 cm
Perimeter of the rectangle P = 2(1 + b)
= 2(16 + 8) = 2×24 = 48 cm
Area of the rectangle A = l x b
= 16 x 8 = 128 sq. cm

B) Given length of the rectangle l = 14 cm
Breadth of the rectangle b = 10 cm
Perimeter of the rectangle P = 2(l + b)
= 2(14 + 10) = 2 x 24 = 48 cm
Area of the rectangle A = l x b
= 14 x 10 = 140 sq.cm

C) Given side of the square s = 12 cm
Perimeter of the square P = 4 x s = 4 x 12 = 48 cm
Area of the square A = s x s = 12 x 12 = 144 sq. cm
i) Perimeters of rectangle A and rectangle B and square are equal.
ii) No. Areas are not equal and area of the square is greater than the areas of rectangles.

## Andhra Pradesh Board Class 6th Maths Chapter 11 Perimeter and Area Ex 11.3 Textbooks for Exam Preparations

Andhra Pradesh Board Class 6th Maths Chapter 11 Perimeter and Area Ex 11.3 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 6th Maths Chapter 11 Perimeter and Area Ex 11.3 exam preparation. The AP Board STD 6th Maths Chapter 11 Perimeter and Area Ex 11.3 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 6th Maths Chapter 11 Perimeter and Area Ex 11.3 Books State Board syllabus with maximum efficiency.

## FAQs Regarding Andhra Pradesh Board Class 6th Maths Chapter 11 Perimeter and Area Ex 11.3 Textbook Solutions

#### Can we get a Andhra Pradesh State Board Book PDF for all Classes?

Yes you can get Andhra Pradesh Board Text Book PDF for all classes using the links provided in the above article.

## Important Terms

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