# HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

## AP Board Class 8 Maths Chapter 12 Factorisation Ex 12.4 Textbook Solutions PDF: Download Andhra Pradesh Board STD 8th Maths Chapter 12 Factorisation Ex 12.4 Book Answers

 AP Board Class 8 Maths Chapter 12 Factorisation Ex 12.4 Textbook Solutions PDF: Download Andhra Pradesh Board STD 8th Maths Chapter 12 Factorisation Ex 12.4 Book Answers

## Andhra Pradesh State Board Class 8th Maths Chapter 12 Factorisation Ex 12.4 Books Solutions

 Board AP Board Materials Textbook Solutions/Guide Format DOC/PDF Class 8th Subject Maths Chapters Maths Chapter 12 Factorisation Ex 12.4 Provider Hsslive

2. Click on the Andhra Pradesh Board Class 8th Maths Chapter 12 Factorisation Ex 12.4 Answers.
3. Look for your Andhra Pradesh Board STD 8th Maths Chapter 12 Factorisation Ex 12.4 Textbooks PDF.

## AP Board Class 8th Maths Chapter 12 Factorisation Ex 12.4 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 8th Maths Chapter 12 Factorisation Ex 12.4 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Question 1.
Find the errors and correct the following mathematical sentences
(i) 3(x – 9) = 3x – 9
(ii) x(3x+2) = 3x2 + 2
(iii) 2x+3x = 5x2
(iv) 2x + x + 3x = sx
(v) 4p + 3p + 2p + p – 9p = 0
(vi) 3x + 2y = 6xy
(vii) (3x)2 + 4x +7 = 3x2 + 4x +7
(viii) (2x)2 + 5x = 4x + 5x = 9x
(ix) (2a + 3)2 = 2a2 + 6a +9
(x) Substitute x -3 in
(a) x2 + 7x + 12 (- 3)2 + 7(-3) + 12 = 9 + 4 + 12 = 25
(b) x2 – 5x + 6(-3)2 – 5(-3) + 69 – 15 + 6 = 0
(c) x2 +5x = (-3)2 + 5(3) + 6 = -9 – 15 = -24
(xi) (x – 4)2 = x2 – 16
(xii) (x + 7)2 = x2 +49
(xiii) (3a + 4b)(a – b)= 3a2 – 4a2
(xiv) (x + 4) (x + 2) = x2 + 8
(xv) (x – 4) (x – 2) = x2– 8
(xvi) 5x3 ÷ 5 x3 = 0
(xvii) 2x3 + 1 ÷ 2x3 = 1
(xviii) 3x + 2 ÷ 3x = 23𝑥
(xix) 3x + 5 ÷ 3 = 5
(xx) 4𝑥+33 = x + 1
Solution:
(i) 3(x – 9) = 3x – 9
3(x – 9) = 3x – 9
⇒ 3x – 3 x 9 = 3x – 9
⇒ 3x – 27 = 3x – 9
⇒ – 27 ≠ – 9
∴ The given sentence is wrong. Correct sentence is 3(x – 9) = 3x – 27.

(ii) x(3x+2) = 3x2 + 2
x(3x + 2) = 3x2 + 2
⇒ x × 3x + x × 2 = 3x2 + 2
⇒ 3x2 + 2x ≠ 3x2 + 2
∴ The given sentence is wrong.
Correct sentence is x(3x + 2) = 3x2 + 2x.

(iii) 2x+3x = 5x2
2x + 3x = 5x2
⇒ 5x = 5x2
⇒ x ≠ x2
∴ The given sentence is wrong. Correct sentence is 2x + 3x = 5x.

(iv) 2x + x + 3x = 5x
2x + x + 3x = 5x
⇒ 6x = 5x
⇒ 6 ≠ 5
∴ The given sentence is wrong. Correct sentence is 2x + 3x = 5x.

(v) 4p + 3p + 2p + p – 9p = 0
4p + 3p + 2p + p – 9p = 0
⇒ 10p – 9p = 0
⇒ p = 0
It is not possible
∴ The given sentence is wrong. Correct sentence is
4p + 3p + 2p + p – 9p – p = 0

(vi) 3x + 2y = 6xy
3x + 2y = 6xy
a + b ≠ ab
∴ The given sentence is wrong.
Correct sentence is 3x x 2y = 6xy.

(vii) (3x)2 + 4x +7 = 3x2 + 4x +7
(3x)2 + 4x +7 = 3x2 + 4x +7
⇒ (3x)2 = 3x2
⇒ 9x2 = 3x2
⇒ 9 = 3
It is not possible
∴ The given sentence is wrong. Correct sentence is
(3x)2+ 4x + 7 = 9x2 + 4x + 7.

(viii) (2x)2 + 5x = 4x + 5x = 9x
(2x)2 + 5x = 4x + 5x = 9x
⇒ 4x2 + 5x = 4x + 5x
⇒ 4x2 = 4x
⇒ x2 = x
⇒ x ≠ √x
∴ The given sentence is wrong. Correct sentence is (2x)2 + 5x = 4x2 + 5x.

(ix) (2a + 3)2 = 2a2 + 6a +9
(2a + 3)2 = 2a2 + 6a +9
⇒ (2a)2 + 2 × 2a × 3 + 32 = 2a2 + 6a + 9
⇒ 4a2 + 12a + 9 = 2a2+ 6a + 9
⇒ 4a2 – 2a2 = 6a – 12a
⇒ 2a2 = – 6a
⇒ 2a ≠ 6
∴ The given sentence is wrong.
Correct sentence is
(2a + 3)2 = 4a2 + 12a + 9.

(x) Substitute x -3 in
(a) x2 + 7x + 12 (- 3)2 + 7(-3) + 12 = 9 + 4 + 12 = 25
x2 + 7x + 12 = (- 3)2 + 7 (- 3) + 12
= 9 – 21 + 12
= 21 – 21
= 0 25 (False)

(b) x2 – 5x + 6(-3)2 – 5(-3) + 69 – 15 + 6 = 0
x2 – 5x + 6 = (-3)2 – 5 (- 3) + 6
= 9 + 15 + 6
= 30 ≠ 0 (False)

(c) x2 +5x = (-3)2 + 5(3) + 6 = -9 – 15 = -24
x2 + 5x = (- 3)2 + 5 (- 3)
= 9 – 15 = – 6 ≠ 24 (False)

(xi) (x – 4)2 = x2 – 16
(x – 4)2 = x2 – 16 = (x)2 – (4)2
(a – b)2 ≠ a2 – b2
∴ (x-4)2 ≠ (x)2 – (4)2
∴ The given sentence is wrong.
Correct sentence is (x – 4)2 = x2 – 8x + 16.

(xii) (x + 7)2 = x2 +49
(x + 7)2 = x2 + 49 = (x)2 + (7)2
(a + b)2 ≠ a2 + b2
∴ (x+7)2 ≠ (x)2 – (7)2
∴ The given sentence is wrong.
Correct sentence is (x + 7)2 = x2 + 14x + 49.

(xiii) (3a + 4b)(a – b)= 3a2 – 4a2
3a(a – b) + 4b(a – b) = 3a2 – 42
3a2 – 3ab + 4ab – 4b2 = – a2
3a2 + ab – 4b2 ≠ a2
∴ The given sentence is wrong. Correct sentence is
(3a + 4b) (a – b) = 3a2 + ab – 4b2

(xiv) (x + 4) (x + 2) = x2 + 8
(x + 4) (x + 2) = x2 + 8
⇒ x2 + 6x + 8 = x2 + 8
⇒ 6x ≠ 0
Here ’6x’ term is missing in R.H.S.
∴ The given sentence is wrong. Correct sentence is
(x + 4)(x + 2) = x2 + 6x + 8.

(xv) (x – 4) (x – 2) = x2– 8
(x – 4) (x – 2) = x2 – 8
⇒ x2 – 6x + 8 ≠ x2 – 8
∴ The given sentence is wrong. Correct sentence is
(x – 4) (x – 2) = x2 – 6x + 8

(xvi) 5x3 ÷ 5 x3 = 0
5x3 ÷ 5 x3 = 0
⇒ x3-3 = 0
⇒ x0 = 0
∴ 1 ≠ 0 (∵ but x° = 1)
∴ The given sentence is wrong. Correct sentence is 5x3 ÷ 5x3 = 1.
In the denominator the term T is missing. .•. The given sentence is wrong. Correct sentence is

(xvii) 2x3 + 1 ÷ 2x3 = 1
2x3 + 1 ÷ 2x3 = 1
⇒ 2𝑥3+12𝑥3 = 1
In the denominator the term T is missing.
∴ The given sentence is wrong. Correct sentence is
2x3 + 1 ÷ 2x3 = 1 + 12x3

(xviii) 3x + 2 ÷ 3x = 23𝑥
3x + 2 ÷ 3x = 23𝑥
⇒ 3𝑥+23𝑥=23𝑥
⇒ 1 + 23𝑥=23𝑥 ⇒ 1 ≠ 0
∴ The given sentence is wrong. Correct sentence is 3x + 2 ÷ 3x = 1 + 23𝑥

(xix) 3x + 5 ÷ 3 = 5
⇒ 3𝑥+53 = 5
⇒ 3𝑥3+53 = 5 ⇒ x + 53 ≠ 5
∴ It is a wrong sentence.
Correct sentence is 3x + 5 ÷ 3 = x + 53

(xx) 4𝑥+33 = x + 1
4𝑥+33 = x + 1
⇒ 4x3+33 = x + 1
⇒ 4x3 + 1 ≠ x + 1
∴ It is a wrong sentence.
Correct sentence is 4𝑥+33=4𝑥3+1

## Andhra Pradesh Board Class 8th Maths Chapter 12 Factorisation Ex 12.4 Textbooks for Exam Preparations

Andhra Pradesh Board Class 8th Maths Chapter 12 Factorisation Ex 12.4 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 8th Maths Chapter 12 Factorisation Ex 12.4 exam preparation. The AP Board STD 8th Maths Chapter 12 Factorisation Ex 12.4 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 8th Maths Chapter 12 Factorisation Ex 12.4 Books State Board syllabus with maximum efficiency.

## FAQs Regarding Andhra Pradesh Board Class 8th Maths Chapter 12 Factorisation Ex 12.4 Textbook Solutions

#### Can we get a Andhra Pradesh State Board Book PDF for all Classes?

Yes you can get Andhra Pradesh Board Text Book PDF for all classes using the links provided in the above article.

## Important Terms

Andhra Pradesh Board Class 8th Maths Chapter 12 Factorisation Ex 12.4, AP Board Class 8th Maths Chapter 12 Factorisation Ex 12.4 Textbooks, Andhra Pradesh State Board Class 8th Maths Chapter 12 Factorisation Ex 12.4, Andhra Pradesh State Board Class 8th Maths Chapter 12 Factorisation Ex 12.4 Textbook solutions, AP Board Class 8th Maths Chapter 12 Factorisation Ex 12.4 Textbooks Solutions, Andhra Pradesh Board STD 8th Maths Chapter 12 Factorisation Ex 12.4, AP Board STD 8th Maths Chapter 12 Factorisation Ex 12.4 Textbooks, Andhra Pradesh State Board STD 8th Maths Chapter 12 Factorisation Ex 12.4, Andhra Pradesh State Board STD 8th Maths Chapter 12 Factorisation Ex 12.4 Textbook solutions, AP Board STD 8th Maths Chapter 12 Factorisation Ex 12.4 Textbooks Solutions,
Share: