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AP Board Class 7 Maths Chapter 1 Integers Ex 1.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 1 Integers Ex 1.2 Book Answers

 AP Board Class 7 Maths Chapter 1 Integers Ex 1.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 1 Integers Ex 1.2 Book Answers

Andhra Pradesh State Board Class 7th Maths Chapter 1 Integers Ex 1.2 Books Solutions

 Board AP Board Materials Textbook Solutions/Guide Format DOC/PDF Class 7th Subject Maths Chapters Maths Chapter 1 Integers Ex 1.2 Provider Hsslive

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3. Look for your Andhra Pradesh Board STD 7th Maths Chapter 1 Integers Ex 1.2 Textbooks PDF.

Find below the list of all AP Board Class 7th Maths Chapter 1 Integers Ex 1.2 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Question 1.
Calculate the following,
(i) (- 96) ÷ 16
(- a) ÷ b = – 𝑎𝑏
9616 = – 6

(ii) 98 ÷ (- 49)
a ÷ (- b) = – 𝑎𝑏
9849 = – 2

(iii) (- 51) ÷ 17
(- a) ÷ b = – 𝑎𝑏
5117 = – 3

(iv) 38 ÷ (- 19)
a ÷ (- b) = – 𝑎𝑏
3819 = – 2

(v) (- 80) ÷ 20
(- a) ÷ b = – 𝑎𝑏
8020 = – 4

(vi) (- 150) ÷ (- 25)
(- a) ÷ (- b) = – 𝑎𝑏 = 𝑎𝑏
15025 = 15025 = – 6

(vii) (- 600) ÷ 60
(- a) ÷ b = – 𝑎𝑏
60060
= – 10

(viii) (-54) ÷ 9
(- a) ÷ b = – 𝑎𝑏
549
= – 6

(ix) 130 ÷ 65
a ÷ b = 𝑎𝑏
13065
= 2

(x) (- 315) ÷ ( -315)
(- a) ÷ (- b) = 𝑎𝑏 = 𝑎𝑏
315315
315315
= 1

Question 2.
The product of two integers is – 165. If one number is – 15, find the other integer.
Given one number a = – 15
Other number b = ?
Product of two numbers = (- 165)
a × b = – 165
(- 15) × b = – 165
b = (- 165) × (- 15)
Other number b = 11

Question 3.
Because of Covid-19 a company lockdown for 6 months and got loss of ₹1,32,000 in the year 2020. Find the average loss of each month.

Given loss of 6 months = ₹ 1,32,000
Average loss of each month = 1,32,000 ÷ 6
Average loss of each month = ₹ 22,000

Question 4.
The temperature at 12 noon was 10°C above zero. If it decreases at the rate of 2°C per hour until midnight, at what time would the temperature be 8°C below zero ? What would be the temperature at mid-night ?
The temperature at 12 noon = 10°C above zero.
The temperature is decreasing at 2°C per hour 8°C below zero = – 8°C
So, total temperature falls 2°C in every one hour.
Therefore, to decrease 18°C, time taken
= 18/2 = 9 hrs.
Present time is 12 noon, so, the time when the temperature at 12 midnight will be
= (- 8° C) + (- 2° C × 3 hrs.)
= (- 8° C) + (- 6° C)
= 160
So, at 12 midnight the temperature will be – 14°C

Question 5.
A green grocer earns a profit of ₹ 7 per kg of tomato and got loss of ₹ 4 per kg of brinjal by selling. On Monday he gets neither profit nor loss,.if he sold 68 kgs of tomato. How many kgs of brinjal did he sell ?

Given profit per kg of tomato = ₹ 7
Loss per kg of brinjal = ₹ 4
Weight of tomatoes sold = 68 kgs
Let number of kgs of tomato be x kg.
Number of kgs of brinjals be y kg.
7x – 4y = 0
7 × 68 – 4y = 0
– 4y = – 7 × 68
y = 7×684
∴ Weight of brinjals sold = + 7 × 17
= + 119 kgs.

Question 6.
In a test, each correct answer carry + 3 marks and incorrect answer – 1 mark, Sona attempted all the questions and scored + 20 marks though she got 10 correct answers.
(i) How many incorrect answers did she attempt ?
(ii) How many questions were given in the test ?
Given marks for every correct answer = + 3
Given marks for every incorrect answer = – 1
No. of correct answer questions = 10
Total marks gained on correct answer questions = 10 × (+3) = + 30

(i) No. of incorrect answer questions = x
Total marks gained on incorrect answer questions = y × (-1) = – y.
Marks scored by Sona
⇒ + 30 + (- y) = + 20
⇒ – y = + 20 – 30
⇒ – y = – 10
⇒ y = 10
∴ No. of incorrect answers Sona attempts =10

(ii) Number of questions given in the test = No. of correct answer questions + No. of incorrect answer questions.
= 10 + 10 = 20 questions.

Question 7.
Write 5 pairs of integers (a, b) such that a ÷ b = -4.
(Ex : (12, – 3) because 12 + (-3) = -4)

(i) (-16, +4) because (- 16) ÷ 4 = -4
(ii) (20, -5) because 20 ÷ (-5) = – 4
(iii) (—8, 2) because (-8) ÷ 2 =- 4
(iv) (24, -6) because 24 ÷ (-6) = – 4
(v) (-36, 9) because (-36) ÷ 9 = – 4

(OR)

 a b a ÷ b = – 4 (-16) 4 (-16) ÷ 4 = – 4 20 (-5) 20 ÷ (-5) = – 4 8 2 (- 8) ÷ 2 = – 4 24 (-6) 24 ÷ (- 6) = – 4 -36 9 (-36) ÷ 9 = – 4

Andhra Pradesh Board Class 7th Maths Chapter 1 Integers Ex 1.2 Textbooks for Exam Preparations

Andhra Pradesh Board Class 7th Maths Chapter 1 Integers Ex 1.2 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 7th Maths Chapter 1 Integers Ex 1.2 exam preparation. The AP Board STD 7th Maths Chapter 1 Integers Ex 1.2 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 7th Maths Chapter 1 Integers Ex 1.2 Books State Board syllabus with maximum efficiency.

FAQs Regarding Andhra Pradesh Board Class 7th Maths Chapter 1 Integers Ex 1.2 Textbook Solutions

Can we get a Andhra Pradesh State Board Book PDF for all Classes?

Yes you can get Andhra Pradesh Board Text Book PDF for all classes using the links provided in the above article.

Important Terms

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