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AP Board Class 7 Maths Chapter 8 Exponents and Powers Ex 8.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Book Answers

AP Board Class 7 Maths Chapter 8 Exponents and Powers Ex 8.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Book Answers
AP Board Class 7 Maths Chapter 8 Exponents and Powers Ex 8.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Book Answers


AP Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Textbooks Solutions and answers for students are now available in pdf format. Andhra Pradesh Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Book answers and solutions are one of the most important study materials for any student. The Andhra Pradesh State Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 books are published by the Andhra Pradesh Board Publishers. These Andhra Pradesh Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 textbooks are prepared by a group of expert faculty members. Students can download these AP Board STD 7th Maths Chapter 8 Exponents and Powers Ex 8.2 book solutions pdf online from this page.

Andhra Pradesh Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Textbooks Solutions PDF

Andhra Pradesh State Board STD 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Textbooks. These Andhra Pradesh State Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.

Andhra Pradesh State Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Books Solutions

Board AP Board
Materials Textbook Solutions/Guide
Format DOC/PDF
Class 7th
Subject Maths
Chapters Maths Chapter 8 Exponents and Powers Ex 8.2
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AP Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Question 1.
Simplify the following by using Laws of Exponents.
(i) 37 × 38
Answer:
37 × 38
We know am × an = am+n
37 × 38 = 37 + 8 = 315
∴ 37 × 38 =315

(ii) 92 × 90 × 93
Answer:
92 × 90 × 93
We know ap × aq × ar = p + q + r
92 × 90 × 93 = 92 + 0 + 3 = 95
∴ 92 × 90 × 93 = 95

(iii) (28)3
Answer:
(28)3
We know (am)n = amn
(28)3 = 28×3 =224
∴ (28)3 = 224

(iv) (a5)4
Answer:
(a5)4
We Know (am)n = amn
(a5)4 = a5×4 = a20
(a5)4 = a20

(v) (25)4×(25)3×(25)8
Answer:

(vi) 75 ÷ 78
Answer:
75 ÷ 78
We know am = 1𝑎𝑛𝑚 (n>m)
75 ÷ 78 = 1785=173
∴ 75 ÷ 78 = 173

(vii) (6)9(6)5
Answer:
(6)9(6)5
We Know am ÷ an = am-n(m > n)
(6)9(6)5 = (-6)9-5 = (-6)4
∴ (6)9(6)5 = (-6)4

(viii) (64 × 62) ÷ 65
Answer:
(64 × 62) ÷ 65
We know atm X a = a”
= (64+2) ÷ 65
= 66 ÷ 65
We know am ÷ an = am-n (m> n)
= 66-5 = 61 = 6
∴ (64 × 62) ÷ 65 = 6

(ix) 5323
Answer:
5323
We know 𝑎𝑚𝑏𝑚=(𝑎𝑏)𝑚
∴ 5323=(52)3

(x) (-3)3 × (-3)10 × (-3)7
Answer:
(-3)3 × (-3)10 × (-3)7
we know ap . aq. ar = ap+q+r
(-3)3 × (-3)0 × (-3)7 = (-3)3+10+7
∴ (- 3)3 × (- 3)10 × (- 3)7 = (- 3)20

Question 2.
Simplify and express each of the following in Exponential form.
(i) (𝑎5𝑎3) × a8
Answer:
(𝑎5𝑎3) × a8
We Know 𝑎𝑚𝑎𝑛 = am-n(m > n)
= (a5-3) × a8
= a2 × a8

We know am × an = am+n
= a2+8 = a10
∴ (𝑎5𝑎3) × a8 = a10

(ii) 20 + 30 – 40
Answer:
20 + 30 – 40
We know a0 = 1

∴ 20 + 30 – 40 = 1

(iii) (23 × 2)2
Answer:
(23 × 2)2
We know am.an = am+n
(23 × 2)2 = (23+1)2 = (24)2

We know (am)n = am.n
= 24×2 = 28
∴(23 × 2)2 = 28

(iv) [(52)3 × 54] ÷ 57
Answer:
[(52)3 × 54] ÷ 57

We know (am) = am.n
= [52×3 × 54] ÷ 57
= [56 < 54] ÷ 57

We know am .an = am+n
= [56+4] ÷ 57
= 510 ÷ 57
We know am ÷ an = am-n (m > n)
= 510-7 = 53
∴ [(52)3 × 54] ÷ 57 = 53

Question 3.
Simplify (𝑥𝑎𝑥𝑏)×(𝑥𝑏𝑥𝑐)×(𝑥𝑐𝑥𝑎)
Answer:
(𝑥𝑎𝑥𝑏)×(𝑥𝑏𝑥𝑐)×(𝑥𝑐𝑥𝑎)

Question 4.
Find the value of the following.
(i) (-1)1000
Answer:
(-1)1000
(-1)1 = – 1
(-1)2 = – 1 × – 1 = + 1
(-1)3 = – 1 × -1 × -1 = – 1
(-1)4 = -1 × -1 × – 1 × – 1 = + 1
(-1)5 = -1 × -1 × -1 × -1 × -1 = -1
(-1)100 = -1 × -1 × -1 × ………… 100 times = + 1

So, (-1)odd number = -1 and
(-1)even number = + 1

Here 1000 is even number
So, (-1)1000 = + 1

(ii) (1)250
Answer:
1250 = 1 × 1 × 1 ……… 250 times = 1
∴ 1250 = 1

(iii) (1)121
Answer:
1121 = -1 × -1 × -1 ……..(121 times)
Here 121 is an odd number
So, (1)121 = – 1

(iv) (10000)0
Answer:
(10000)0
we know a0 = 1
So, (10000)0 = 1

Question 5.
If 75 × 73x = 720 then find the value of ’x’.
Answer:
Given, 75 × 73x = 720
W know am X an = am+n
75 + 3x = 720
If the bases are equal, then the powers should also be equal.
⇒ 5 + 3x = 20
⇒ 5 + 3x – 5 = 20 – 5
⇒ 3x = 15
⇒ 3𝑥3=153 = 5
∴ x = 5

Question 6.
If 10y = 10000 then 5y =?
Answer:
Given, 10y = 10000
10y = 10 × 10 × 10 × 10
10y = 104
If the bases are equal, then the powers should also be equal.
⇒ y = 4
Multiply by 5 on bothsides,
5 × y = 5 × 4
∴ 5y = 20

Question 7.
If 5x = 100 then find the following values.
(i) 5x+y
Answer:
Given 5x+y = 100
5x = 102
Multiply by 52
5x × 52 = 100 × 52
5x+2 = 100 × 25 (∵ am × an = am+n)
∴ 5x+2 = 2500

(ii) 5x-2
Answer:
Given 5x = 100
5x = 102
Divide by 52 on both sides
5x ÷ 52 = 100 ÷ 52

∴ 5x-2 = 4

Question 8.
By what number should 34 be multiplied so that the product is 243?
Answer:
Given number is 34
If we multiply 34 by ‘a’ the product is 243.
i.e. 34 × a = 243
= 3 × 3 × 3 × 3 × 3
34 × a = 35
Divide by 34 on both sides

If we multiply 34 by 3 we get 243.

Question 9.
Arushi computed (52)4 as 516 Has she done it correctly or not’? Justify your answer.
Answer:
Given, (52)4
We know) (am)n = am.n
= 52×4 = 58
∴ (52)4 = 58
But Arushi got 516 So, (52)4 ≠ 516
Therefore Arushi did wrong.

Question 10.
Is 35 × 45 equal to 1225? If not why? Justify your answer.
Answer:
Given, 35 × 45
We know am × bm = (a × b)m
So, 35 × 45 = 12 but not 125×5
= (3 × 4)5
= (12)5
35 × 45= 125
But given 35 × 45 = 1225.
So, this is wrong.
So, 35 × 45 ≠ 1225


AP Board Textbook Solutions PDF for Class 7th Maths


Andhra Pradesh Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Textbooks for Exam Preparations

Andhra Pradesh Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 exam preparation. The AP Board STD 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 7th Maths Chapter 8 Exponents and Powers Ex 8.2 Books State Board syllabus with maximum efficiency.

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