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AP Board Class 7 Maths Chapter 9 Algebraic Expressions Ex 9.3 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Book Answers

AP Board Class 7 Maths Chapter 9 Algebraic Expressions Ex 9.3 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Book Answers
AP Board Class 7 Maths Chapter 9 Algebraic Expressions Ex 9.3 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Book Answers


AP Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Textbooks Solutions and answers for students are now available in pdf format. Andhra Pradesh Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Book answers and solutions are one of the most important study materials for any student. The Andhra Pradesh State Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 books are published by the Andhra Pradesh Board Publishers. These Andhra Pradesh Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 textbooks are prepared by a group of expert faculty members. Students can download these AP Board STD 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 book solutions pdf online from this page.

Andhra Pradesh Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Textbooks Solutions PDF

Andhra Pradesh State Board STD 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Textbooks. These Andhra Pradesh State Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.

Andhra Pradesh State Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Books Solutions

Board AP Board
Materials Textbook Solutions/Guide
Format DOC/PDF
Class 7th
Subject Maths
Chapters Maths Chapter 9 Algebraic Expressions Ex 9.3
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AP Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Question 1.
Write standard form and additive inverse of the following expressions.
(i) – 6a
Answer:
Additive inverse of – 6a = – (- 6a) = 6a

(ii) 2 + 7c2
Answer:
Standard form of 2 + 7c2 = 7c2 + 2
Additive inverse of 7c2 + 2
= – (7c2 + 2)
= – 7c2 – 2

(iii) 6x2 + 4x – 5
Answer:
Given expression is in standard form.
Additive inverse of 6x2 + 4x – 5
= – (6x2 + 4x – 5)
= – 6x2 – 4x + 5

(iv) 3c + 7a – 9b
Answer:
Standard form of 3c + 7a – 9b = 7a – 9b + 3c
Additive inverse of 7a – 9b + 3c
= – (7a – 9b + 3c)
= – 7a + 9b – 3c

Question 2.
Write the following expressions in standard form:
(i) 6x + x2 – 5
Answer:
Standard form of 6x + x2 – 5
= x2 + 6x – 5

(ii) 3 – 4a2 – 5a
Answer:
Standard form of 3 – 4a2 – 5a
= – 4a2 – 5a + 3

(iii) – m + 6 + 3m2
Answer:
Standard form of – m + 6 + 3m2
= 3m2 – m + 6

(iv) c3 + 1 + c + 2c2
Answer:
Standard form of
c3 + 1 + c + 2c2 = c3 + 2c2 + c + 1

(v) 9 – p2
Answer:
Standard form of 9 – p2 = – p2 + 9

Question 3.
Add the following algebraic expressions using both horizontal and vertical methods. Did you get the same answer with both the methods? Verify.
(i) 2x2 – 6x +3; 4x2 + 9x + 5
Answer:

(ii) a2 + 6ab + 8; – 3a2 – ab – 2
Answer:

(iii) – p2 + 2p – 10; 4 – 5p – 2p2
Answer:

Question 4.
Subtract the second expression from the first expression:
(i) 2x + y , x – y
Answer:
Let A = 2x + y and B = x – y
A – B = A + (- B) Additive inverse of B is
-B = – (x – y) = – x + y
∴ A – B = A + (- B)
= 2x + y + (- x + y)
= 2x + y – x + y
= 2x – x + y + y
= (2 – 1)x + (1 + 1)y
∴ A – B = x + 2y

(ii) a + 2b + c, – a – b – 3c
Answer:
Let A = a + 2b + c and B = – a – b – 3c
A – B = A + (- B)
Additive inverse of B is
– B = – (- a – b – 3c)
= a + b + 3c
∴ A – B = A + (- B)
= a + 2b + c + (a + b + 3c)
= a + 2b + c + a + b + 3c
= (a + a) + (2b + lb) + (c + 3c)
∴ A – B = 2a + 3b + 4c

(iii) 2l2 – 3lm + 5m2, 3l2 – 4lm + 6m2
Answer:
Let A = 2l2 – 3lm + 5m2 and
B = 3l2 – 4lm + 6m2
A – B = A + (- B)
Additive inverse of B is
– B = – (3t2 – 4lm + 6m2)
= – 3l2 + 4lm – 6m2
∴ A – B = A + (- B)
= (2l2 – 3lm + 5m2) + (- 3l2 + 4lm – 6m2)
= 2l2 – 3lm + 5m2 – 3l2 + 4lm – 6m2
= 2l2 – 3l2 – 3lm + 4lm + 5m2 – 6m2
= (2 – 3)l2 + (- 3 + 4)lm + (5 – 6)m2
= (- 1) l2 + 1 lm + (- 1)m2
∴ A – B = – l2 + lm – m2

(iv) 7 – x – 3x2, 2x2 – 5x – 3
Answer:
Let A = 7 – x – 3x2 and B = 2x2 – 5x – 3
Write the given expressions in standard form.
∴ A = – 3x2 – x + 7 and B = 2x2 – 5x – 3
A – B = A + (- B)
Additive inverse of B is
– B = – (2x2 – 5x – 3)
= – 2x2 + 5x + 3
∴ A – B = A + (- B)
= (- 3x2 – x + 7) + (- 2x2 + 5x + 3)
= – 3x2 – x + 7 – 2x2 + 5x + 3
= (- 3x2 – 2x2) + (- x + 5x) + (7 + 3)
= (- 3 – 2)x2 + (- 1 + 5)x + 10
∴ A – B = – 5x2 + 4x + 10

(v) 6m3 + 4m2 + 7m – 3, 2m3 + 4
Answer:
Let A = 6m3 + 4m2 + 7m – 3 and
B = 2 m2 + 4
A – B = A + (- B)
Additive inverse of B is
– B = – (2m3 + 4)
= – 2m3 – 4
∴ A – B = A + (- B)
= (6m3 + 4m2 + 7m – 3) + (- 2m3 – 4)
= 6m3 + 4m2 + 7m – 3 – 2m3 – 4
= (6m3 – 2m3) + 4m2 + 7m + (- 3 – 4)
= (6 – 2)m3 + 4m2 + 7m + (- 7)
∴ A – B = 4m3 + 4m2 + 7m – 7

Question 5.
Find the perimeter of the beside rect¬angle whose length is 6x + y and breadth is 3x – 2y.

Answer:
Given length of rectangle l = 6x + y
breadth b = 3x – 2y
Perimeter of Rectangle = 2 (l + b)
= 2[(6x + y) + (3x – 2y)]
= 2[6x + y + 3x – 2y]
= 2[(6 + 3)x + (1 – 2)y]
= 2[9x + (- 1) y]
= 2[9x – 1y]
= 2 × (9x) – 2 × (1y)
∴ Perimeter of rectangle = (18x – 2y) units.

Question 6.
Find the perimeter of triangle whose sides are a + 3b, a – b and 2a – b.

Answer:
Let the sides of triangle are
x = a + 3b, y = a – b and z = 2a – b
Perimeter of triangle = x + y + z
= (a + 3b) + (a – b) + (2a – b)
= a + 3b + a – b + 2a – b
= (a + a + 2a) + (3b – b – b)
= (1 + 1 + 2)a + (3 – 1 – 1)b
Perimeter of triangle.
= (4a + b) units.

Question 7.
Subtract the sum of x2 – 5xy + 2y2 and y2 – 2xy – 3x2 from the sum of 6x2 – 8xy – y2 and 2xy – 2y2 – x2.
Answer:
Given expressions are
x2 – 5xy + 2y2 and y2 – 2xy – 3x2 and 6x2 – 8xy – y2 and 2xy – 2y2 – x2
Write the given expressions in the standard form
x2 – 5xy + 2y2 and – 3x2 – 2xy + y2 and 6x2 – 8xy – y2 and – x2 + 2xy – 2y2
Let the Sum
A = (x2 – 5xy + 2y2) + (- 3x2 – 2xy + y2)
= x2 – 5xy + 2y2 – 3x2 – 2xy + y2
= x2 – 3x2 – 5xy – 2xy + 2y2 + y2
= (1 – 3)x2 + (- 5 – 2)xy + (2 + 1)y2
A = – 2x2 – 7xy + 3y2

Let the Sum
B = (6x2 – 8xy – y2) + (- x2 + 2xy – 2y2)
= 6x2 – 8xy – y2 – x2 + 2xy – 2y2
= (6 – 1 )x2 + (- 8 + 2)xy + (- 1 – 2)y2
B = 5x2 – 6xy – 3y2
B – A = B + (- A)
Additive inverse of A is
– A = – (A)
= – (- 2x2 – 7xy + 3y2)
∴ – A = 2x2 + 7xy – 3y2
B – A = B + (- A)
= (5x2 – 6xy – 3y2) + (2x2 + 7xy – 3y2)
= (5 + 2)x2 + (- 6 + 7)xy + (- 3 – 3)y2
∴ B – A = 7x2 + xy – 6y2

Question 8.
What should be added to 1 + 2p – 3P2 to get p2 – p – 1 ?
Answer:
Given expressions are
1 + 2p – 3p2 and p2 – p – 1
Write the given expressions in the standard form.
– 3p2 + 2p + 1 and p2 – p – 1
Let A should be added to B to get C.
i.e. A + B = C
∴ A = C – B
Let B = – 3p2 + 2p + 1 and
C = p2 – p – 1
A = C + (- B )
Additive inverse B is
– B = – (- 3p2 + 2p + 1) .
– B = 3p2 – 2p – 1 .
A = (p2 – p – 1) + (3p2 – 2p – 1)
= p2 – p – 1 + 3p2 – 2p – 1
= (1 + 3)p2 + (- 1 – 2)p + (- 1 – 1)
∴ A = 4p2 – 3p – 2
∴ 4p2 – 3p – 2 is added to 1 + 2p – 3p2 to get p2 – p – 1.

Question 9.
What should be taken away from 3a2 – 4b2 + 5ab + 20 to get – a2 – b2 + 6ab + 3 ?
Answer:
Given expressions are
3a2 – 4b2 + 5ab + 20 and – a2 – b2 + 6ab +3
Let A be taken away from B to get C. that is A = B – C = B + (- C)
Let B = 3a2 – 4b2 + 5ab + 20 and C = – a2 – b2 + 6ab + 3 Additive inverse of C is
(- C) = – (- a2 – b2 + 6ab + 3)
= a2 + b2 – 6ab – 3
A = B + (- C)
= (3a2 – 4b2 + 5ab + 20) + (a2 + b2 – 6ab – 3)
= 3a2 – 4b2 + 5ab + 20 + a2 + b2 – 6ab – 3
= 3a2 + a2 – 4b2 + b2 + 5ab – 6ab + 20 – 3
= (3 + 1)a2 + (- 4 + 1)b2 + (5 – 6) ab + (20 – 3)
A = 4a2 – 3b2 – 1 ab + 17
So, 4a2 – 3b2 – 1 ab + 17 is taken away from 3a2 – 4b2 + 5ab + 20 to get – a2 – b2 + 6ab + 3.

Question 10.
If A = 4x2 + y2 – 6xy;
B = 3y2 + 12x2 + 8xy;
C = 6x2 + 8y2 + 6xy then,
find(i) A + B + C (ii) (A – B) – C
Answer:
Given A = 4x2 + y2 – 6xy
B = 3y2 + 12x2 + 8xy
C = 6x2 + 8y2 + 6xy
Write the given expressions in standard form.
A = 4x2 – 6xy + y2
B = 12x2 + 8xy + 3y2
C = 6x2 + 6xy + 8y2

(i) A + B + C = (4x2 – 6xy + y2) + (12x2 + 8xy + 3y2) + (6x2 + 6xy + 8y2)
= 4x2 – 6xy + y2 + 12x2 + 8xy + 3y2 + 6x2 + 6xy + 8y2
= (4x2 + 12x2 + 6x2) + (- 6xy + 8xy + 6xy) + (y2 + 3y2 + 8y2)
= (4 + 12 + 6) x2 + (- 6 + 8 + 6) xy + (1 + 3 + 8)y2
∴ A + B + C = 22x2 + 8xy + 12y2

(ii) (A – B) – C
A + (- B) + (- C)
Additive inverse of B is
– B = – (12x2 + 8xy + 3y2)
∴ – B = – 12x2 – 8xy – 3y2
Additive inverse of C is
– C = -(6x2 + 6xy + 8y2)
∴ – C = – 6x2 – 6xy – 8y2
A + (- B) + (- C)
= (4x2 – 6xy + y2) + (- 12x2 – 8xy – 3y2) + (- 6x2 – 6xy – 8y2)
= 4x2 – 6xy + y2 – 12x2 – 8xy – 3y2 – 6x2 – 6xy – 8y2
= (4x2 – 12x2 – 6x2) + (- 6xy – 8xy – 6xy) + (y2 – 3y2 – 8y2)
= (4 – 12 – 6)x2 + (- 6 – 8 – 6)xy + (1 – 3 – 8)y2
∴ (A – B) – C = – 14x2 – 20xy – 10y2


AP Board Textbook Solutions PDF for Class 7th Maths


Andhra Pradesh Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Textbooks for Exam Preparations

Andhra Pradesh Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 exam preparation. The AP Board STD 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 7th Maths Chapter 9 Algebraic Expressions Ex 9.3 Books State Board syllabus with maximum efficiency.

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