AP Board Class 7 Maths Chapter 4 Lines and Angles Ex 4.4 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 4 Lines and Angles Ex 4.4 Book Answers ~ HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

AP Board Class 7 Maths Chapter 4 Lines and Angles Ex 4.4 Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 4 Lines and Angles Ex 4.4 Book Answers

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Andhra Pradesh Board Class 7th Maths Chapter 4 Lines and Angles Ex 4.4 Textbooks Solutions PDF

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Andhra Pradesh State Board Class 7th Maths Chapter 4 Lines and Angles Ex 4.4 Books Solutions

Board	AP Board
Materials	Textbook Solutions/Guide
Format	DOC/PDF
Class	7th
Subject	Maths
Chapters	Maths Chapter 4 Lines and Angles Ex 4.4
Provider	Hsslive

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AP Board Class 7th Maths Chapter 4 Lines and Angles Ex 4.4 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 7th Maths Chapter 4 Lines and Angles Ex 4.4 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

Question 1.
In the given figure, two lines p ∥ q arid r is transversal, If ∠3 = 135°, then find the remaining angles.

Answer:
Given ∠3 = 135
∠1 = ∠3 = 135° (vertically opposite angles)
∠1 = ∠5 = 135° (corresponding angles)

∠3 = ∠8 = 135° (corresponding angles)
∠3 = ∠5 = 135° (Alternate interior angles)

∠1 + ∠7 = 180° (co-exterior angles are supplementary)
135° + ∠7 = 180°
∠7 = 180°- 135° = 45°
∠6 = ∠7 = 45° (vertically opposite angles)
∠6 = ∠2 = 45° (corresponding angles)
∠4 = ∠7 = 45° (corresponding angles)
∴ ∠1 = 135°, ∠2 = 45°, ∠3 = 135°, ∠4 = 45°, ∠5 = 135°, ∠6 = 45°, ∠7 = 45°, ∠8 = 135°

Question 2.
In the given figure, 𝐀𝐁←→ || 𝐂𝐃←→ and 𝐃𝐄←→ is a transversal. Find x.

Answer:
Given 𝐀𝐁←→ || 𝐂𝐃←→ and 𝐃𝐄←→ is a transversal line.
∠ABE = ∠CDB (corresponding angles)
∠ABF + ∠FBE = ∠CDB (we know ∠ABE = ∠ABF + ∠FBE)
From the figure ∠ABF = 35°,
∠FBE = x° and ∠CDB =100°
35° + x = 100°
⇒ 35° + x – 35° = 100° – 35°
∴ x = 65°

Question 3.
In the given figure, m || n and p is transversal. Find x and y.

Answer:
Given m || n and p is transversal.
So, ∠x = 120° (vertically opposite angles)
45 + y = x (corresponding angles)
⇒ 45 + y = 120° (we know ∠x = 120°)
⇒ 45 + y – 45 = 120-45°
⇒ y = 75°
x = 120° and y = 75°

Question 4.
In the given figure, 𝐀𝐁−→−‖𝐂𝐃−→−‖𝐅𝐄−→. Find x, y and ∠AEC.

Answer:
Given 𝐀𝐁−→−‖𝐂𝐃−→−‖𝐅𝐄−→
∠x = 20° (Alternate interior angles)
∠y = 33° (Alternate interior angles)
∠AEC = ∠AEF + ∠FEC
∠AEC = ∠x + ∠y
∠AEC = 20° + 33° = 53°
∴ x = 20°, y = 33° and ∠AEC = 53°

Question 5.
In the given figure, a transversal t intersects two lines p and q. Check whether p ∥q or not.

Answer:
If co-interior angles are supplementary, then the lines are parallel.
100° + 80° = 180° (co-interior angles supplementary)
So, p and q are parallel to each other.

Question 6.
In the given figure if l ∥m, then find x, y and z.

Answer:
Given l ∥m and AC is transversal.
z = 40° (Alternate interior angles)
l ∥m and AB is transversal. , and x + (y + z) = 180° (co-interior angles are supplementary)
x + y + z = 180°
(x + y) + 40° = 180° (co-interior angles are supplementary) (∵ z = 40°)
x + y + 40° = 180°
x + y + 40°-40° = 180° – 40°
∴ x + y = 140°
But x = y (given)
2x = 140°
∴ x = 140∘2 = 70° = y
So, x = 70°, y = 70° and z = 40°

Question 7.
In the given figure p, q, r and s are parallel lines and t is a transversal. Find x, y and z.

Answer:
p ∥ q
So, 80° + x = 180° (co-interior angles)
80° + x-80° = 180°-80°
x = 100°

q ∥ r
x + y = 180° (co-interior angles)
100° + y = 180° (we know x – 100°)
100° + y – 100° = 180°- 100°
y = 80°

r∥s
y = z (Alternate exterior angles)
y = z = 80° (we know y = 80°)
x = 100°, y = 80° and z = 80°

Question 8.
In the given figure 𝐀𝐁−→−‖𝐂𝐃−→− and E is a point in between them. Find x + y + z. (Hint : Draw a parallel line to 𝐀𝐁−→− through E)

Answer:
Given 𝐀𝐁−→−‖𝐂𝐃−→−

Draw EF−→‖AB−→−
∠BAE = x,
∠AEF = p
∠FEC = q,
∠ECD = z
∠AEC = ∠AEF + ∠FEC
y = p + q

AB ∥ EF and AE is a transversal.
∠BAE + ∠AEF = 180° (co-interior angles are supplementary)
x + p = 180° ……………….(1)
CD ∥ EF and EC is a transversal.
∠FEC + ∠ECD = 180° (co-interior angles are supplementary’)
q + z = 180° …………….(2)

By adding (1) and (2)

x + y. + z = 360° (we know y = p + q)

Question 9.
Identify the pair of parallel lines in the given figure and write them.

Answer:
∠A = ∠E = 60° So, AL ∥ EH
∠B = ∠D = 90° So, BK ∥ DL
∠C = ∠F = 50° So, CJ ∥FG

AP Board Textbook Solutions PDF for Class 7th Maths

Andhra Pradesh Board Class 7th Maths Chapter 4 Lines and Angles Ex 4.4 Textbooks for Exam Preparations

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