AP Board Class 7 Maths Chapter 3 Simple Equations InText Questions Textbook Solutions PDF: Download Andhra Pradesh Board STD 7th Maths Chapter 3 Simple Equations InText Questions Book Answers |

## Andhra Pradesh Board Class 7th Maths Chapter 3 Simple Equations InText Questions Textbooks Solutions PDF

Andhra Pradesh State Board STD 7th Maths Chapter 3 Simple Equations InText Questions Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 7th Maths Chapter 3 Simple Equations InText Questions Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 7th Maths Chapter 3 Simple Equations InText Questions solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 7th Maths Chapter 3 Simple Equations InText Questions Textbooks. These Andhra Pradesh State Board Class 7th Maths Chapter 3 Simple Equations InText Questions Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.## Andhra Pradesh State Board Class 7th Maths Chapter 3 Simple Equations InText Questions Books Solutions

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## AP Board Class 7th Maths Chapter 3 Simple Equations InText Questions Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 7th Maths Chapter 3 Simple Equations InText Questions Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:Check your Progress (Page No: 43)

Question 1.

Write simple equations for the following verbal statements.

(i) The sum of five times of x and 3 is 28.

Answer:

Given number = x

Five times of a number = 5 ∙ x

By adding 3 the result = 5x + 3

∴ 5x + 3 = 28

(ii) Taking away 7 from p gives 21.

Answer:

Given number = p

By subtracting 7 from the number = p – 7

∴ p – 7 = 21

(iii) If you add one third to m, then you get 25.

Answer:

Given number = m

By adding 13 to m = m + 13

then, m + 13 = 25.

(iv) Sum of angles x, (x + 20) is a straight angle.

Answer:

Given angles are x, x + 20

Sum of angles = x + x + 20

Sum of angles is straight angle (180°).

⇒ x + x + 20 = 180°

∴ 2x + 20 = 180°

(v) Perimeter of a rectangle whose length is 2 cm more than its width is 16 cm.

Answer:

Let width of rectangle = x

Length of rectangle

= 2 more than width = x + 2

Perimeter = 2 (length + width)

= 2(x + 2 + x) = 2(2x + 2)

Given Perimeter = 16 cm

∴ 4x + 4 = 16

Question 2.

Write the following equations in state-ment form.

(i) x + 4 = 9

Answer:

4 is added to a number is 9.

(ii) 2y = 15

Answer:

Two times (twice) a number is 15.

(iii) 3m – 13 = 25

Answer:

13 is taking away from 3 times of m is 25.

(iv) 𝑛4 = 5

Answer:

One fourth of n is 5.

Let’s Do Activity (Page No: 45)

Describe the balances given below in two ways.

(a) Using words (b) Using mathematical symbols.

Answer:

Lets Explore (Page No: 46)

Develop equations from the pictures given below and solve pictorially.

(i)

Answer:

x + x + x = 5 + 5 + 1 + 1

3x = 12

(ii)

Answer:

y + y + 1 = 5 + 5 + 5

2y + 1 = 15

Let’s Think (Page No: 47)

An equation is multiplied or divided by two different numbers on either side What will happen to the equality?

Answer:

Consider an equation 7x = 14

If we multiply by two different numbers 5 and 8 on either side.

7x × 5 = 14 × 8 ⇒ 35x = 112

So, the equation 7x = 14 is not equal to 35x = 112

(ii) Consider an equation 3x = 15

If we divide by two different numbers 3 and 5 on either side,

3x ÷ 3 = 15 ÷ 5

3𝑥3 = 155 ⇒ x = 3

So, the equation 3x = 15 is not equal to x = 3 either side, the equality will be changes.

Puzzle Time (Page No: 48)

Question 1.

Solve the puzzle using simple equations.

(i)

Answer:

(ii)

Answer:

(iii)

Answer:

(iv)

Answer:

Check Your Progress (Page No: 51)

Find three equivalent equations having the same solutions x = – 1.

Answer:

Here x + 5 = 4, 8 – x = 9 and 4x + 5 = 1 are equivalent equations because they have the same solution x = – 1

Puzzle Time (Page No. 52)

Question 1.

Here is a puzzle to reveal the name of great mathematician. Solve the equations and fill the below box with the letter opposite to the solution of the equation and finally it reveals the name of mathematician.

Answer:

Check Your Progress (Page No. 53)

Find the value of variable x from the below diagrams.

(i)

Angle at ‘O’ is straight angle

Answer:

Straight angle = 180°

∠ AOB = 180°

∠ AOB + ∠ BOD = 180°

x + 30° + x = 180°

⇒ 2x + 30° = 180°

⇒ 2x + 30° – 30° – 180°- 30° (Subtract 30° on both sides)

⇒ 2x = 150°

⇒ 2𝑥2 = 150∘2 (Divide by 2 on both sides)

∴ x = 75°

(ii)

Perimeter = 36 cm

Answer:

Perimeter of rectangle = 36 cm

2(length + breadth) = 36

⇒ 2(x + 4 + x) = 36

⇒ 2(2x + 4) = 36

⇒ 2(2𝑥+4)2 = 362 (Divide by 2 on both sides)

⇒ 2x + 4 = 18

⇒ 2x + 4 – 4 = 18 – 4 (Subtract 4 on both sides)

⇒ 2x = 14 .

⇒ 2𝑥2 = 142 (Divide by 2 on both sides)

∴ x = 7

Puzzle Time (Page No: 59)

Collect the minimum and maximum temperature (in degrees) of any 5 cities of India of any month and convert the temperature into Fahrenheit and Kelvin Scale.

Examples

Question 1.

Convert the mathematical statements into simple equations.

(i) 5 added to a number is 9.

Answer:

Let the number = x

By adding 5 to the number = 5 + x

∴ 5 + x = 9

(ii) 4 times a number decreased by 3 is 5.

Answer:

Let the number = m

4 times the number = 4m

By decreasing 3 the result = 4m – 3

∴ 4m – 3 = 5

(iii) The sum of 3 times of n and 7 is 13.

Answer:

Let the number = n

3 times the number = 3n

By adding 7 the result = 3n + 7

∴ 3n + 7 = 13

(iv) Length of rectangle is 3 m more than its breadth and its perimeter is 24 m.

Answer:

Breadth of rectangle = x

Length of rectangle = x + 3

Perimeter = 2(x + 3 + x) = 4x + 6

Given Perimeter = 24 m

∴ 4x + 6 = 24

Question 2.

Convert simple equations into statements.

(i) y – 7 = 11

Answer:

Taking away 7 from ‘y’ is 11.

(ii) 8m = 24

Answer:

8 times of number ‘m’ is 24.

(iii) 2x + 13 = 25

Answer:

If you add 13 to 2 times of number ‘x’ is 25.

(iv) 𝑦4 – 7 = 1

Answer:

7 is subtracted from one fourth of y is 1.

Question 3.

Check whether the value given in the brackets is a solution to the given equation or not.

2k – 11 = 5 (k = 7)

Answer:

When k = 7

LHS: 2k – 11 = 2(7) – 11 = 14 – 11 = 3

RHS: 5

Here LHS ≠ RHS,

So k = 7 is not a solution.

Question 4.

Solve 6n – 1 = 29 trial and error method.

Answer:

For n = 5, LHS = RHS. So, n = 5 is the solution of given equation.

Question 5.

Solve x + 5 = 8 by using common balance idea.

Answer:

Question 6.

Solve 2x – 5 = 9 pictorially.

Answer:

Question 7.

Solve: 3k + 4 = 28

Answer:

3k + 4 = 28

⇒ 3k + 4 – 4 = 28 – 4 (Add both sides ‘- 4’)

⇒ 3k = 24

⇒ 3k3 = 243 (Divide both sides by ‘3’)

⇒ k = 8

Check: Substitute k = 8 in the given equation.

LHS = 3k + 4

= 3(8) + 4

= 24 + 4 = 28 = RHS

Hence verified.

Question 8.

Solve: – 4(x – 1) = 16

Answer:

– 4(x – 1) = 16

⇒ 4x + 4 = 16 (Distributive property)

⇒ – 4x + 4 – 4 = 16 – 4 (Subtract both sides ‘4’)

⇒ – 4x = 12

⇒ (- 4x) × (- 1) = 12 × (- 1)

(Multiply with ‘- 1 ‘on both sides)

⇒ 4x = – 12

⇒ 4𝑥4 = −124 (Divide both sides by ‘4’)

⇒ x = – 3

Check: Substitute x = – 3 in the given equation.

LHS = – 4(x – 1)

= – 4(- 3 – 1)

= – 4 (- 4)

= 16

= RHS

Hence verified.

Question 9.

Solve: 2(b + 3) + 13 = 27

Answer:

2(b + 3) + 13 = 27

⇒ 2b + 6 + 13 = 27 (distributive law)

⇒ 2b + 19 = 27

⇒ 2b = 27 – 19 (∵+ 19 transposed and becomes – 19)

⇒ 2b = 8

⇒ b = 82 (∵ × 2 transposed and becomes ÷ 2)

⇒ b = 4

Check:

Substitute b = 4

LHS = 2(b + 3) + 13

= 2(4 + 3) + 13

= 2(7) + 13

= 14 + 13

= 27 = RHS

Hence verified.

Question 10.

Solve : 5(x + 1) – 2(x – 7) = 13

Answer:

5(x + 1) – 2(x – 7) = 13

⇒ 5x + 5 – 2x + 14 = 13 (distributive law)

⇒ (5x – 2x) + (5 + 14) = 13 (regrouping like terms)

⇒ 3x +19 = 13

⇒ 3x = 13 – 19 (∵ +19 transposed arid becomes

⇒ 3x = – 6

⇒ x = −63 (∵ × 3 transposed and becomes ÷ 3)

⇒ x = – 2

Question 11.

Solve: 12 = 13 + 7 (y-6)

Answer:

12 = 13 + 7 (y – 6)

An equation remains the same,

when LHS, RHS are interchanged.

⇒ 13 + 7(y – 6) = 12 .

⇒ 3 + 7y – 42 = 12 (distributive law)

⇒ 7y – 29 = 12

⇒ 7y = 12 + 29 (∵ – 29 transposed and becomes + 29)

⇒ 7y = 41

⇒ y = 417 (∵ × 7 transposed and becomes ÷ 7)

Check:

Substitute y = 417

RHS = 13 + 7(y – 6)

= 13 + 7(417 – 6)

= 13 + 7(41−427)

= 13 + 7(−17)

= 13 – 1

= 12 = LHS

Hence verified.

Question 12.

Solve 𝑚2−2𝑚7−𝑚10=85

Answer:

Check:

Substitute m = 14

LHS = m2−2 m7−m10

= 7 – 4 – 75

= 3 – 75

= 15−75

= 85

= RHS

Hence verified.

Question 13.

Find the value of variable ‘x’ from the following.

(i) x + 20% of x = 60

Answer:

x + 20% of x = 60

⇒ x + 20𝑥100 = 60

⇒ x + 𝑥5 = 60

⇒ 6𝑥5 = 60

⇒ 6x = 60 × 5

⇒ x = (60×5)6

⇒ x = 50

(ii) If two numbers are in the ratio 2 : 3 and their difference is 5, then find largest number.

Answer:

Let largest number = 3x and smallest number = 2x

Difference = 3x – 2x = x

But as per the problem difference = 5

⇒ x = 5

∴ Largest number = 3x = 3 × 5 = 15

(iii) Find the value of x in the following picture.

Answer:

Sum of two angles is 90

2x + 25 + x – 10 = 90

⇒ 3x + 15 = 90

⇒ 3x = 90 – 15

⇒ 3x = 75

⇒ x = 753

⇒ x = 25

(iv) If the perimeter of the following tri-angle is 15 cm, then find the value of x.

Answer:

Perimeter of a triangle = 15 cm

Perimeter = x + x + 2 + 2x – 3 = 4x – 1

∴ 4x – 1 = 15

⇒ 4x = 15 + 1

⇒ 4x = 16

⇒ x = 4

Question 14.

Find two consecutive natural numbers whose sum is 125.

Answer:

Let the number = x

Consecutive number of x = x + 1

Given that, x + (x + 1) = 125

⇒ 2x + 1 = 125

⇒ 2x = 125 – 1

⇒ 2x = 124

⇒ x = 1242

x = 62 and x + 1 = 62 + 1 = 63

∴ Required numbers are 62 and 63.

Check:

Numbers: 62, 63

Sum = 62 + 63 = 125

Hence verified.

Question 15.

The sum of two numbers is 35. One of the numbers exceeds the other by 7. Find the numbers.

Answer:

Let the first number = x

Then the second number = x + 7 (exceeds first number by 7)

Sum of two numbers = 35

According to problem, x + x + 7 = 35

⇒ 2x + 7 = 35

⇒ 2x = 35 – 7

⇒ 2x = 28

⇒ x = 282

⇒ x = 14

x + 7 = 14 + 7 = 21

∴ The two numbers are 14 and 21

Check:

Numbers: 14, 21

Sum = 14 + 21

= 35

Hence verified.

Question 16.

A person has ₹ 1400 in denominations of ₹20, ₹10 and ₹5 notes. The number of notes in each denomination is equal, then find the number of notes of each denomination ?

Answer:

Let the number of notes in each denomination be x.

₹20 denomination amount = 20x

₹10 denomination amount = 10x

₹5 denomination amount = 5x

Total amount = ₹ 1400

⇒ 20x + 10x + 5x = 1400

⇒ 35x = 1400

⇒ x = 140035

⇒ x = 40

∴ Number of notes in each denomination is 40.

Check:

Number of notes = 40

Amount = (20 × 40 + 10 × 40 + 5 × 40)

= 800 + 400 + 200

= ₹ 1400

Hence Verified.

Question 17.

The length of a rectangle is five meters more than twice of its breadth. If the perimeter is 148 meter, then find the length and breadth of the rectangle.

Answer:

Let the breadth of the rectangle = x,

length of a rectangle is five more than twice of its breadth.

Then, length of the rectangle = 2x + 5

Perimeter of the rectangle = 148m

2 (Length + Breadth) = 148

⇒ 2(2x + 5 + x) = 148

⇒ 2(3x + 5) = 148

⇒ 6x + 10 = 148

⇒ 6x = 148 – 10

⇒ 6x = 138

⇒ x = 1386

⇒ x = 23

∴ Breadth of rectangle = 23 m

Length of the rectangle = 2x + 5 = (2 × 23) + 5

= 46 + 5 = 51 m

Check:

Length = 51 m, Breadth = 23 m

Perimeter = 2(l + b)

= 2(51 + 23)

= 2(74)

= 148 m

Hence Verified.

Question 18.

On his birthday Yakshith’s grand father has given ₹ 2000. He used some amount for purchasing books for needy children and thrice of that amount for purchasing food items for orphanage children and the remaining ₹ 200 used for purchasing chocolates . for his friends. Find the amount spent for purchasing books and food items for orphanage children.

Answer:

Let the amount spent for purchasing books for needy children = ₹ x

Amount spent for purchasing food items for orphanage children = ₹ 3x

Amount spent for purchasing chocolates for friends = ₹ 200

Total amount spent = ₹ 2000

⇒ x + 3x + 200 = 2000

⇒ 4x + 200 = 2000

⇒ 4x = 2000 – 200

⇒ 4x = 1800

⇒ x = 18004

⇒ x = 450

∴ Amount spent for purchasing books for needy children = ₹ 450

Amount spent for purchasing food items for orphanage children = ₹ 3x

= 3 × 450 = ₹ 1350

Check:

Amount = ₹ 450 + ₹ 1350 + ₹ 200

= ₹ 2000

Hence Verified.

Question 19.

A school bus starts with full strength of 40 students. It drops some students at the first bus stop. At the second bus stop, twice the number of students get down from the bus. 8 students get down at the third bus stop and the number of students remaining in the bus is only 5. How many students got down at the first stop and second stop?

Answer:

Let us take the number of students get down at first stop = x

No.of students get down at the second bus stop = 2x

No. of students get down at the third bus stop = 8

Remaining students in the bus = 5

⇒ x + 2x +8 + 5 = 40

⇒ 3x + 13 = 40

⇒ 3x = 40 – 13

⇒ 3x = 27

⇒ x = 273

⇒ x = 9

∴ The number of students got down in the first bus stop = 9.

No. of students got down in second stop = 2x = 2 × 9 = 18.

Practice Questions (Page No: 62)

In the questions given below, equations have become wrong due to wrong order of signs (+, -, ×, ÷, =). Choose the correct order of signs from the alternatives given under each question so that the equation becomes right.

Question 1.

7 + 2 = 2 × 3

(a) = × +

(b) = + ×

(c) = + ÷

(d) + × =

Answer:

(a) = × +

Explaination

Given 7 + 2 = 2 × 3 ,

⇒ 7 = 2 × 2 + 3

⇒ 7 = 4 + 3

∴ 7 = 7

Question 2.

7 + 2 × 6 = 20

(a) = × +

(b) × – =

(c) × + =

(d) ÷ + =

Answer:

(c) × + =

Explaination:

Given 7 + 2 × 6 = 20

⇒ 7 × 2 + 6 = 20

⇒ 14 + 6 = 20

∴ 20 = 20

Question 3.

15 ÷ 5 = 2 × 1

(a) ÷ × =

(b) ÷ = ×

(c) × = +

(d) ÷ = +

Answer:

(d) ÷ = +

Explaination:

Given 15 ÷ 5 = 2 × 1

⇒ 15 ÷ 5 = 2 + 1

∴ 3 = 3

Question 4.

6 = 3 – 6 ÷ 12

(a) = × +

(b) ÷ = ×

(c) + = –

(d) ÷ × =

Sol.

(d) ÷ × =

Explaination:

Given 6 = 3 – 6 ÷ 12

⇒ 6 ÷ 3 × 6 =12

⇒ 2 × 6 = 12

∴ 12 = 12

Question 5.

3 + 1 ÷ 4 = 16

(a) – = ×

(b) × + =

(c) + × =

(d) = × +

Answer:

(c) + × =

Explaination:

Given 3 + 1 ÷ 4 = 16

⇒3 + 1 × 4 = 16

⇒ 4 × 4 = 16

∴ 16 = 16

Question 6.

8 ÷ 4 = 2 + 1

(a) ÷ = +

(b) ÷ = ×

(c) ÷ × =

(d) = ÷ ×

Answer:

(b) ÷ = ×

Explaination:

Given 8 ÷ 4 = 2 + 1

⇒ 8 ÷ 4 = 2 × 1

∴ 2 = 2

Question 7.

2 × 2 + 2 = 2

(a) × ÷ =

(b) × = ÷

(c) + × =

(d) × + =

Answer:

(a) × ÷ =

Explaination:

Given 2 × 2 + 2 = 2

⇒ 2 × 2 ÷ 2 = 2

⇒ 2 × 1 = 2

∴ 2 = 2

Question 8.

5 – 6 + 8 = 3

(a) + – =

(b) + = –

(c) – = ×

(d) ÷ × =

Answer:

(a) + – =

Explaination:

Given 5 – 6 + 8 = 3

⇒ 5 + 6 – 8 = 3

⇒ 11 – 8 = 3

∴ 3 = 3

Question 9.

8 ÷ 2 = 2 × 8

(a) + – =

(b) + ×

(c) ÷ = ×

(d) × = ÷

Answer:

(b) + ×

Explaination:

Given 8 ÷ 2 = 2 × 8

⇒ 8 ÷ 2 × 2 = 8

⇒ 4 × 2 – 8

∴8 = 8

Question 10.

3 = 3 – 7 + 0

(a) – + =

(b) + × =

(c) – × =

(d) = × –

Answer:

(c) – × =

Explaination:

Given 3 = 3 – 7 + 0

⇒ 3 – 3 × 7 = 0

⇒ 0 × 7 = 0

∴ 0 = 0

## AP Board Textbook Solutions PDF for Class 7th Maths

- AP Board Class 7
- AP Board Class 7 Maths
- AP Board Class 7 Maths Chapter 1 Integers Review Exercise
- AP Board Class 7 Maths Chapter 1 Integers Ex 1.1
- AP Board Class 7 Maths Chapter 1 Integers Ex 1.2
- AP Board Class 7 Maths Chapter 1 Integers Ex 1.3
- AP Board Class 7 Maths Chapter 1 Integers Ex 1.4
- AP Board Class 7 Maths Chapter 1 Integers Unit Exercise
- AP Board Class 7 Maths Chapter 1 Integers InText Questions
- AP Board Class 7 Maths Chapter 2 Fractions, Decimals and Rational Numbers Review Exercise
- AP Board Class 7 Maths Chapter 2 Fractions, Decimals and Rational Numbers Ex 2.1
- AP Board Class 7 Maths Chapter 2 Fractions, Decimals and Rational Numbers Ex 2.2
- AP Board Class 7 Maths Chapter 2 Fractions, Decimals and Rational Numbers Ex 2.3
- AP Board Class 7 Maths Chapter 2 Fractions, Decimals and Rational Numbers Ex 2.4
- AP Board Class 7 Maths Chapter 2 Fractions, Decimals and Rational Numbers Ex 2.5
- AP Board Class 7 Maths Chapter 2 Fractions, Decimals and Rational Numbers Unit Exercise
- AP Board Class 7 Maths Chapter 2 Fractions, Decimals and Rational Numbers InText Questions
- AP Board Class 7 Maths Chapter 3 Simple Equations Ex 3.1
- AP Board Class 7 Maths Chapter 3 Simple Equations Ex 3.2
- AP Board Class 7 Maths Chapter 3 Simple Equations Ex 3.3
- AP Board Class 7 Maths Chapter 3 Simple Equations Ex 3.4
- AP Board Class 7 Maths Chapter 3 Simple Equations Unit Exercise
- AP Board Class 7 Maths Chapter 3 Simple Equations InText Questions
- AP Board Class 7 Maths Chapter 4 Lines and Angles Review Exercise
- AP Board Class 7 Maths Chapter 4 Lines and Angles Ex 4.1
- AP Board Class 7 Maths Chapter 4 Lines and Angles Ex 4.2
- AP Board Class 7 Maths Chapter 4 Lines and Angles Ex 4.3
- AP Board Class 7 Maths Chapter 4 Lines and Angles Ex 4.4
- AP Board Class 7 Maths Chapter 4 Lines and Angles Unit Exercise
- AP Board Class 7 Maths Chapter 4 Lines and Angles InText Questions
- AP Board Class 7 Maths Chapter 5 Triangles Review Exercise
- AP Board Class 7 Maths Chapter 5 Triangles Ex 5.1
- AP Board Class 7 Maths Chapter 5 Triangles Ex 5.2
- AP Board Class 7 Maths Chapter 5 Triangles Ex 5.3
- AP Board Class 7 Maths Chapter 5 Triangles Ex 5.4
- AP Board Class 7 Maths Chapter 5 Triangles Ex 5.5
- AP Board Class 7 Maths Chapter 5 Triangles Ex 5.6
- AP Board Class 7 Maths Chapter 5 Triangles Unit Exercise
- AP Board Class 7 Maths Chapter 5 Triangles InText Questions
- AP Board Class 7 Maths Chapter 6 Data Handling Ex 6.1
- AP Board Class 7 Maths Chapter 6 Data Handling Ex 6.2
- AP Board Class 7 Maths Chapter 6 Data Handling Ex 6.3
- AP Board Class 7 Maths Chapter 6 Data Handling Ex 6.4
- AP Board Class 7 Maths Chapter 6 Data Handling Unit Exercise
- AP Board Class 7 Maths Chapter 6 Data Handling InText Questions
- AP Board Class 7 Maths Chapter 7 Ratio and Proportion Review Exercise
- AP Board Class 7 Maths Chapter 7 Ratio and Proportion Ex 7.1
- AP Board Class 7 Maths Chapter 7 Ratio and Proportion Ex 7.2
- AP Board Class 7 Maths Chapter 7 Ratio and Proportion Ex 7.3
- AP Board Class 7 Maths Chapter 7 Ratio and Proportion Ex 7.4
- AP Board Class 7 Maths Chapter 7 Ratio and Proportion Ex 7.5
- AP Board Class 7 Maths Chapter 7 Ratio and Proportion Ex 7.6
- AP Board Class 7 Maths Chapter 7 Ratio and Proportion Ex 7.7
- AP Board Class 7 Maths Chapter 7 Ratio and Proportion Unit Exercise
- AP Board Class 7 Maths Chapter 7 Ratio and Proportion InText Questions
- AP Board Class 7 Maths Chapter 8 Exponents and Powers Ex 8.1
- AP Board Class 7 Maths Chapter 8 Exponents and Powers Ex 8.2
- AP Board Class 7 Maths Chapter 8 Exponents and Powers Ex 8.3
- AP Board Class 7 Maths Chapter 8 Exponents and Powers Unit Exercise
- AP Board Class 7 Maths Chapter 8 Exponents and Powers InText Questions
- AP Board Class 7 Maths Chapter 9 Algebraic Expressions Review Exercise
- AP Board Class 7 Maths Chapter 9 Algebraic Expressions Ex 9.1
- AP Board Class 7 Maths Chapter 9 Algebraic Expressions Ex 9.2
- AP Board Class 7 Maths Chapter 9 Algebraic Expressions Ex 9.3
- AP Board Class 7 Maths Chapter 9 Algebraic Expressions Ex 9.4
- AP Board Class 7 Maths Chapter 9 Algebraic Expressions Unit Exercise
- AP Board Class 7 Maths Chapter 9 Algebraic Expressions InText Questions
- AP Board Class 7 Maths Chapter 10 Construction of Triangles Review Exercise
- AP Board Class 7 Maths Chapter 10 Construction of Triangles Ex 10.1
- AP Board Class 7 Maths Chapter 10 Construction of Triangles Ex 10.2
- AP Board Class 7 Maths Chapter 10 Construction of Triangles Ex 10.3
- AP Board Class 7 Maths Chapter 10 Construction of Triangles Unit Exercise
- AP Board Class 7 Maths Chapter 10 Construction of Triangles InText Questions
- AP Board Class 7 Maths Chapter 11 Area of Plane Figures Review Exercise
- AP Board Class 7 Maths Chapter 11 Area of Plane Figures Ex 11.1
- AP Board Class 7 Maths Chapter 11 Area of Plane Figures Ex 11.2
- AP Board Class 7 Maths Chapter 11 Area of Plane Figures Ex 11.3
- AP Board Class 7 Maths Chapter 11 Area of Plane Figures Ex 11.4
- AP Board Class 7 Maths Chapter 11 Area of Plane Figures Unit Exercise
- AP Board Class 7 Maths Chapter 11 Area of Plane Figures InText Questions
- AP Board Class 7 Maths Chapter 12 Symmetry Review Exercise
- AP Board Class 7 Maths Chapter 12 Symmetry Ex 12.1
- AP Board Class 7 Maths Chapter 12 Symmetry Ex 12.2
- AP Board Class 7 Maths Chapter 12 Symmetry Ex 12.3
- AP Board Class 7 Maths Chapter 12 Symmetry Ex 12.4
- AP Board Class 7 Maths Chapter 12 Symmetry Unit Exercise
- AP Board Class 7 Maths Chapter 12 Symmetry InText Questions
- AP Board Class 7 Maths Chapter 1 పూర్ణ సంఖ్యలు Review Exercise
- AP Board Class 7 Maths Chapter 1 పూర్ణ సంఖ్యలు Ex 1.1
- AP Board Class 7 Maths Chapter 1 పూర్ణ సంఖ్యలు Ex 1.2
- AP Board Class 7 Maths Chapter 1 పూర్ణ సంఖ్యలు Ex 1.3
- AP Board Class 7 Maths Chapter 1 పూర్ణ సంఖ్యలు Ex 1.4
- AP Board Class 7 Maths Chapter 1 పూర్ణ సంఖ్యలు Unit Exercise
- AP Board Class 7 Maths Chapter 1 పూర్ణ సంఖ్యలు InText Questions
- AP Board Class 7 Maths Chapter 2 భిన్నాలు మరియు దశాంశాలు Review Exercise
- AP Board Class 7 Maths Chapter 2 భిన్నాలు మరియు దశాంశాలు Ex 2.1
- AP Board Class 7 Maths Chapter 2 భిన్నాలు మరియు దశాంశాలు Ex 2.2
- AP Board Class 7 Maths Chapter 2 భిన్నాలు మరియు దశాంశాలు Ex 2.3
- AP Board Class 7 Maths Chapter 2 భిన్నాలు మరియు దశాంశాలు Ex 2.4
- AP Board Class 7 Maths Chapter 2 భిన్నాలు మరియు దశాంశాలు Ex 2.5
- AP Board Class 7 Maths Chapter 2 భిన్నాలు మరియు దశాంశాలు Unit Exercise
- AP Board Class 7 Maths Chapter 2 భిన్నాలు మరియు దశాంశాలు InText Questions
- AP Board Class 7 Maths Chapter 3 సామాన్య సమీకరణాలు Ex 3.1
- AP Board Class 7 Maths Chapter 3 సామాన్య సమీకరణాలు Ex 3.2
- AP Board Class 7 Maths Chapter 3 సామాన్య సమీకరణాలు Ex 3.3
- AP Board Class 7 Maths Chapter 3 సామాన్య సమీకరణాలు Ex 3.4
- AP Board Class 7 Maths Chapter 3 సామాన్య సమీకరణాలు Unit Exercise
- AP Board Class 7 Maths Chapter 3 సామాన్య సమీకరణాలు InText Questions
- AP Board Class 7 Maths Chapter 4 రేఖలు మరియు కోణాలు Review Exercise
- AP Board Class 7 Maths Chapter 4 రేఖలు మరియు కోణాలు Ex 4.1
- AP Board Class 7 Maths Chapter 4 రేఖలు మరియు కోణాలు Ex 4.2
- AP Board Class 7 Maths Chapter 4 రేఖలు మరియు కోణాలు Ex 4.3
- AP Board Class 7 Maths Chapter 4 రేఖలు మరియు కోణాలు Ex 4.4
- AP Board Class 7 Maths Chapter 4 రేఖలు మరియు కోణాలు Unit Exercise
- AP Board Class 7 Maths Chapter 4 రేఖలు మరియు కోణాలు InText Questions
- AP Board Class 7 Maths Chapter 5 త్రిభుజాలు Review Exercise
- AP Board Class 7 Maths Chapter 5 త్రిభుజాలు Ex 5.1
- AP Board Class 7 Maths Chapter 5 త్రిభుజాలు Ex 5.2
- AP Board Class 7 Maths Chapter 5 త్రిభుజాలు Ex 5.3
- AP Board Class 7 Maths Chapter 5 త్రిభుజాలు Ex 5.4
- AP Board Class 7 Maths Chapter 5 త్రిభుజాలు Ex 5.5
- AP Board Class 7 Maths Chapter 5 త్రిభుజాలు Ex 5.6
- AP Board Class 7 Maths Chapter 5 త్రిభుజాలు Unit Exercise
- AP Board Class 7 Maths Chapter 5 త్రిభుజాలు InText Questions
- AP Board Class 7 Maths Chapter 6 దత్తాంశ నిర్వహణ Ex 6.1
- AP Board Class 7 Maths Chapter 6 దత్తాంశ నిర్వహణ Ex 6.2
- AP Board Class 7 Maths Chapter 6 దత్తాంశ నిర్వహణ Ex 6.3
- AP Board Class 7 Maths Chapter 6 దత్తాంశ నిర్వహణ Ex 6.4
- AP Board Class 7 Maths Chapter 6 దత్తాంశ నిర్వహణ Unit Exercise
- AP Board Class 7 Maths Chapter 6 దత్తాంశ నిర్వహణ InText Questions
- AP Board Class 7 Maths Chapter 7 నిష్పత్తి మరియు అనుపాతం Review Exercise
- AP Board Class 7 Maths Chapter 7 నిష్పత్తి మరియు అనుపాతం Ex 7.1
- AP Board Class 7 Maths Chapter 7 నిష్పత్తి మరియు అనుపాతం Ex 7.2
- AP Board Class 7 Maths Chapter 7 నిష్పత్తి మరియు అనుపాతం Ex 7.3
- AP Board Class 7 Maths Chapter 7 నిష్పత్తి మరియు అనుపాతం Ex 7.4
- AP Board Class 7 Maths Chapter 7 నిష్పత్తి మరియు అనుపాతం Ex 7.5
- AP Board Class 7 Maths Chapter 7 నిష్పత్తి మరియు అనుపాతం Ex 7.6
- AP Board Class 7 Maths Chapter 7 నిష్పత్తి మరియు అనుపాతం Ex 7.7
- AP Board Class 7 Maths Chapter 7 నిష్పత్తి మరియు అనుపాతం Unit Exercise
- AP Board Class 7 Maths Chapter 7 నిష్పత్తి మరియు అనుపాతం InText Questions
- AP Board Class 7 Maths Chapter 8 ఘాతాంకాలు మరియు ఘాతాలు Ex 8.1
- AP Board Class 7 Maths Chapter 8 ఘాతాంకాలు మరియు ఘాతాలు Ex 8.2
- AP Board Class 7 Maths Chapter 8 ఘాతాంకాలు మరియు ఘాతాలు Ex 8.3
- AP Board Class 7 Maths Chapter 8 ఘాతాంకాలు మరియు ఘాతాలు Unit Exercise
- AP Board Class 7 Maths Chapter 8 ఘాతాంకాలు మరియు ఘాతాలు InText Questions
- AP Board Class 7 Maths Chapter 9 బీజీయ సమాసాలు Review Exercise
- AP Board Class 7 Maths Chapter 9 బీజీయ సమాసాలు Ex 9.1
- AP Board Class 7 Maths Chapter 9 బీజీయ సమాసాలు Ex 9.2
- AP Board Class 7 Maths Chapter 9 బీజీయ సమాసాలు Ex 9.3
- AP Board Class 7 Maths Chapter 9 బీజీయ సమాసాలు Ex 9.4
- AP Board Class 7 Maths Chapter 9 బీజీయ సమాసాలు Unit Exercise
- AP Board Class 7 Maths Chapter 9 బీజీయ సమాసాలు InText Questions
- AP Board Class 7 Maths Chapter 10 త్రిభుజాల నిర్మాణం Review Exercise
- AP Board Class 7 Maths Chapter 10 త్రిభుజాల నిర్మాణం Ex 10.1
- AP Board Class 7 Maths Chapter 10 త్రిభుజాల నిర్మాణం Ex 10.2
- AP Board Class 7 Maths Chapter 10 త్రిభుజాల నిర్మాణం Ex 10.3
- AP Board Class 7 Maths Chapter 10 త్రిభుజాల నిర్మాణం Unit Exercise
- AP Board Class 7 Maths Chapter 10 త్రిభుజాల నిర్మాణం InText Questions
- AP Board Class 7 Maths Chapter 11 సమతల పటాల వైశాల్యాలు Review Exercise
- AP Board Class 7 Maths Chapter 11 సమతల పటాల వైశాల్యాలు Ex 11.1
- AP Board Class 7 Maths Chapter 11 సమతల పటాల వైశాల్యాలు Ex 11.2
- AP Board Class 7 Maths Chapter 11 సమతల పటాల వైశాల్యాలు Ex 11.3
- AP Board Class 7 Maths Chapter 11 సమతల పటాల వైశాల్యాలు Ex 11.4
- AP Board Class 7 Maths Chapter 11 సమతల పటాల వైశాల్యాలు Unit Exercise
- AP Board Class 7 Maths Chapter 11 సమతల పటాల వైశాల్యాలు InText Questions
- AP Board Class 7 Maths Chapter 12 సౌష్ఠవము Review Exercise
- AP Board Class 7 Maths Chapter 12 సౌష్ఠవము Ex 12.1
- AP Board Class 7 Maths Chapter 12 సౌష్ఠవము Ex 12.2
- AP Board Class 7 Maths Chapter 12 సౌష్ఠవము Ex 12.3
- AP Board Class 7 Maths Chapter 12 సౌష్ఠవము Ex 12.4
- AP Board Class 7 Maths Chapter 12 సౌష్ఠవము Unit Exercise
- AP Board Class 7 Maths Chapter 12 సౌష్ఠవము InText Questions

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