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AP Board Class 9 Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Textbook Solutions PDF: Download Andhra Pradesh Board STD 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Book Answers

AP Board Class 9 Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Textbook Solutions PDF: Download Andhra Pradesh Board STD 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Book Answers
AP Board Class 9 Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Textbook Solutions PDF: Download Andhra Pradesh Board STD 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Book Answers


AP Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Textbooks Solutions and answers for students are now available in pdf format. Andhra Pradesh Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Book answers and solutions are one of the most important study materials for any student. The Andhra Pradesh State Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 books are published by the Andhra Pradesh Board Publishers. These Andhra Pradesh Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 textbooks are prepared by a group of expert faculty members. Students can download these AP Board STD 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 book solutions pdf online from this page.

Andhra Pradesh Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Textbooks Solutions PDF

Andhra Pradesh State Board STD 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Textbooks. These Andhra Pradesh State Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.

Andhra Pradesh State Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Books Solutions

Board AP Board
Materials Textbook Solutions/Guide
Format DOC/PDF
Class 9th
Subject Maths
Chapters Maths Chapter 10 Surface Areas and Volumes Ex 10.1
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AP Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

AP State Syllabus 9th Class Maths Solutions 10th Lesson Surface Areas and Volumes Exercise 10.1

Question 1.
Find the lateral surface area and total surface area of the following right prisms.
i) 
L.S.A. = 4l2
= 4 × 42
= 64cm2
T.S.A = 6l2
= 6 × 42 = 96cm2

ii) L.S.A. =2h(l + b)
= 2 × 5 (8 + 6)
= 10 × 14 = 140 cm2
T.S.A. = 2 (lb + bh + lh)
= 2(8 × 6 + 6 × 5 + 8 × 5)
= 2 (48 + 30 + 40)
= 236 cm2

Question 2.
The total surface area of a cube is 1350 sq.m. Find its volume.
Solution:
Given T.S.A. of a cube 6l2 = 1350
l2 = 13506
l2 = 225
∴ l = 225‾‾‾‾√ = 15m
∴ Volume of the cube = l3
= 15 × 15 × 15
= 3375 m3

Question 3.
Find the area of four walls of a room (Assume that there are no doors or windows) if its length 12 m; breadth 10 m and height 7.5 m.
Solution:
Length of the room = 12 m
Breadth of the room = 10 m
Height of the room = 7.5 m
Area of four walls of the room
A = 2h (l + b)
A = 2 × 7.5 (12 + 10)
= 15 × 22
= 330 m2

Question 4.
The volume of a cuboid is 1200 cm3. The length is 15 cm and breadth is 10 cm. Find its height.
Solution:
Length of a cuboid, ‘l’ = 15 cm
Breadth of the cuboid, b = 10 cm
Volume of the cuboid, V = lbh = 1200.cm3
Let the height = h
∴ 15 × 10 × h = 1200
∴ h = 120015×10
= 8 cm

Question 5.
How does the total surface area of a box change if
i) Each dimension is doubled ?
Solution:
Let the original dimensions be Length – l units
Breadth – b units
Height – h units
Then T.S.A = 2 (lb + bh + lh)
If the dimensions are doubled then
Length = 2l
Breadth = 2b
Height = 2h
T.S.A. = 2 (2l. 2b + 2b . 2h + 2l . 2h)
= 2 (4lb + 4bh + 4lh)
= 4 × [2 (lb + bh + lh]
= 4 × original T.S.A.
i.e., T.S.A. increases by 4 times.

ii) Each dimension is tripled ?
Solution:
Let the original and changed dimensions are l, b, h and 31, 3b, 3h
Original T.S.A. = 2 (lb + bh + lh)
Changed T.S.A
= 2 (3l . 3b + 3b . 3h + 3l. 3h)
Changed T S.A. = 2 (9lb + 9bh + 9lh)
= 9 × [2 (lb + bh + lh)]
= 9 [original T.S.A.]
Thus original T.S.A. increased by 9 times if each dimension is tripled.

Question 6.
The base of a prism is triangular in shape with sides 3 cm, 4 cm and 5 cm. Find the volume of the prism if its height is 10 cm.
Solution:
Volume of triangular prism = Area of the base × height
Sides of the triangle are 3 cm, 4 cm and 5 cm.
Area = s (s – a) (s – b) (s – c)

∴ Volume of the prism = 6 × 10 = 60 cm3
(OR)
3 cm, 4 cm and 5 cm are the sides of right triangle.
∴ Area of the triangle
= 12 bh = 12 × 3 × 4 = 6 cm2
Volume of prism = base area × height
= 6 × 10 = 60cm3

Question 7.
A regular square pyramid is 3 m height and the perimeter of its base is16 m Find the volume of the pyramid.
Solution:
Perimeter of the base = 16 m
Height of the pyramid 3 m
Volume of the pyramid
= 13 × volume of prism
= 13 × (base area x height)
= 13 × 4 × 4 × 3= 16m [4 × side=16 ∴ side = 4 m Area = s= 4 × 4]

Question 8.
An Olympic swimming pool is in the shape of a cuboid of dimensions 50 m long and 25 m wide. If it is 3 m deep throughout, how many litres of water does it hold ?
Solution:
Dimensions of the swimming pool are
Length = 50 m
Breadth = 25 m
Deep = 3 m
∴ Volume of the swimming pool
V = lbh
V = 50 × 25 × 3 = 3750 m3
∴ It can hold 37,50,000 litres of water.
[∵ 1 m3 = 1000 lit.]


AP Board Textbook Solutions PDF for Class 9th Telugu


Andhra Pradesh Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Textbooks for Exam Preparations

Andhra Pradesh Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 exam preparation. The AP Board STD 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 9th Maths Chapter 10 Surface Areas and Volumes Ex 10.1 Books State Board syllabus with maximum efficiency.

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