AP Board Class 10 Maths Chapter 10 Mensuration Ex 10.1 Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 10 Mensuration Ex 10.1 Book Answers ~ HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

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AP Board Class 10 Maths Chapter 10 Mensuration Ex 10.1 Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 10 Mensuration Ex 10.1 Book Answers

AP Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 Textbooks Solutions and answers for students are now available in pdf format. Andhra Pradesh Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 Book answers and solutions are one of the most important study materials for any student. The Andhra Pradesh State Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 books are published by the Andhra Pradesh Board Publishers. These Andhra Pradesh Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 textbooks are prepared by a group of expert faculty members. Students can download these AP Board STD 10th Maths Chapter 10 Mensuration Ex 10.1 book solutions pdf online from this page.

Andhra Pradesh Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 Textbooks Solutions PDF

Andhra Pradesh State Board STD 10th Maths Chapter 10 Mensuration Ex 10.1 Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 10th Maths Chapter 10 Mensuration Ex 10.1 Textbooks. These Andhra Pradesh State Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.

Andhra Pradesh State Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 Books Solutions

Board	AP Board
Materials	Textbook Solutions/Guide
Format	DOC/PDF
Class	10th
Subject	Maths
Chapters	Maths Chapter 10 Mensuration Ex 10.1
Provider	Hsslive

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AP Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 Textbooks Solutions with Answer PDF Download

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10th Class Maths 10th Lesson Mensuration Ex 10.1 Textbook Questions and Answers

Question 1.
A joker’s cap is in the form of right circular cone whose base radius is 7 cm and height is 24 cm. Find the area of the sheet required to make 10 such caps.
Answer:

Radius of the cap (r) = 7 cm
Height of the cap (h) = 24 cm
Slant height of the cap (l) = 𝑟2+ℎ2‾‾‾‾‾‾‾√
= 72+242‾‾‾‾‾‾‾‾√
= 49+576‾‾‾‾‾‾‾‾√
= √625
= 25
∴ l = 25 cm.
Lateral surface area of the cap = Cone = πrl
L.S.A. = 227 × 7 × 25 = 550 cm².
∴ Area of the sheet required for 10 caps = 10 x 550 = 5500 cm².

Question 2.
A sports company was ordered to prepare 100 paper cylinders without caps for shuttle cocks. The required dimensions of the cylinder are 35 cm length / height and its radius is 7 cm. Find the required area of thin paper sheet needed to make 100 cylinders.
Answer:

Radius of the cylinder, r = 7 cm
Height of the cylinder, h = 35 cm
T.S.A. of the cylinder with lids at both ends = 2πr(r+h)
= 2 × 227 × 7 × (7 + 35)
= 2 × 227 × 7 × 42 = 1848 cm².
Area of thin paper required for 100 cylinders = 100 × 1848
= 184800 cm²
= 184800100×100 m²
= 18.48 m².

Question 3.
Find the volume of right circular cone with radius 6 cm. and height 7 cm.
Answer:

Base radius of the cone (r) = 6 cm.
Height of the cone (h) = 7 cm
Volume of the cone = 13πr²h
= 13 × 227 × 6 × 6 × 7
= 264 c.c. (Cubic centimeters)
∴ Volume of the right circular cone = 264 c.c.

Question 4.
The lateral surface area of a cylinder is equal to the curved surface area of a cone. If their base be the same, find the ratio of the height of the cylinder to slant height of the cone.
Answer:
Base of cylinder and cone be the same.

CSA / LSA of cylinder = 2πrh
CSA of cone = πrl
The lateral surface area of a cylinder is equal to the curved surface area of cone.
∴ 2πrh = πrl
⇒ ℎ𝑙=𝜋𝑟2𝜋𝑟
⇒ ℎ𝑙 = 12
∴ h : l = 1 : 2

Question 5.
A self help group wants to manufacture joker’s caps (conical caps) of 3 cm radius and 4 cm height. If the available colour paper sheet is 1000 cm², then how many caps can be manufactured from that paper sheet?
Answer:

Radius of the cap (conical cap) (r) = 3 cm
Height of the cap (h) = 4 cm
Slant height l = 𝑟2+ℎ2‾‾‾‾‾‾‾√
(by Pythagoras theorem)
= 32+42‾‾‾‾‾‾‾√
= 9+16‾‾‾‾‾‾√
= √25
= 5 cm
C.S.A. of the cap = πrl
= 227 × 3 × 5
≃ 47.14 cm²
Number of caps that can be made out of 1000 cm² = 100047.14 ≃ 21.27
∴ Number of caps = 21.

Question 6.
A cylinder and cone have bases of equal radii and are of equal heights. Show that their volumes are in the ratio of 3 : 1.
Answer:
Given dimensions are:
Cone:
Radius = r
Height = h
Volume (V) = 13πr²h

Cylinder:
Radius = r
Height = h
Volume (V) = πr²h

Ratio of volumes of cylinder and cone = πr²h : 13πr²h
= 1 : 13
= 3 : 1
Hence, their volumes are in the ratio = 3 : 1.

Question 7.
A solid iron rod has cylindrical shape. Its height is 11 cm. and base diameter is 7 cm. Then find the total volume of 50 rods?
Answer:

Diameter of the cylinder (d) = 7 cm
Radius of the base (r) = 72 = 3.5 cm
Height of the cylinder (h) = 11 cm
Volume of the cylinder V = πr²h
= 227 × 3.5 × 3.5 × 11 = 423.5 cm³
∴ Total volume of 50 rods = 50 × 423.5 cm³ = 21175 cm³.

Question 8.
A heap of rice is in the form of a cone of diameter 12 m. and height 8 m. Find its volume? How much canvas cloth is required to cover the heap? (Use π = 3.14)
Answer:

Diameter of the heap (conical) (d) = 12 cm
∴ Radius = 𝑑2 = 122 = 6 cm
Height of the cone (h) = 8 m
Volume of the cone, V = 13πr²h
= 13 × 227 × 6 × 6 × 8
= 301.71 m³.

Question 9.
The curved surface area of a cone is 4070 cm² and its diameter is 70 cm. What is its slant height?
Answer:
C.S.A. of a cone = πrl = 4070 cm²
Diameter of the cone (d) = 70 cm
Radius of the cone = r = 𝑑2 = 702 = 35 cm
Let its slant height be ‘l’.
By problem,
πrl = 4070 cm²
227 × 35 × l = 4070
110 l = 4070
l = 4070110 = 37 cm
∴ Its slant height = 37 cm.

AP Board Textbook Solutions PDF for Class 10th Maths

AP Board Class 10 Maths Chapter 1 Real Numbers Textbook Solutions PDF

AP Board Class 10 Maths Chapter 2 Sets Textbook Solutions PDF

AP Board Class 10 Maths Chapter 3 Polynomials Textbook Solutions PDF

AP Board Class 10 Maths Chapter 4 Pair of Linear Equations in Two Variables Textbook Solutions PDF

AP Board Class 10 Maths Chapter 5 Quadratic Equations Textbook Solutions PDF

AP Board Class 10 Maths Chapter 6 Progressions Textbook Solutions PDF

AP Board Class 10 Maths Chapter 7 Coordinate Geometry Textbook Solutions PDF

AP Board Class 10 Maths Chapter 8 Similar Triangles Textbook Solutions PDF

AP Board Class 10 Maths Chapter 9 Tangents and Secants to a Circle Textbook Solutions PDF

AP Board Class 10 Maths Chapter 10 Mensuration Textbook Solutions PDF

AP Board Class 10 Maths Chapter 11 Trigonometry Textbook Solutions PDF

AP Board Class 10 Maths Chapter 12 Applications of Trigonometry Textbook Solutions PDF

AP Board Class 10 Maths Chapter 13 Probability Textbook Solutions PDF

AP Board Class 10 Maths Chapter 14 Statistics Textbook Solutions PDF

Andhra Pradesh Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 Textbooks for Exam Preparations

Andhra Pradesh Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 10th Maths Chapter 10 Mensuration Ex 10.1 exam preparation. The AP Board STD 10th Maths Chapter 10 Mensuration Ex 10.1 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 10th Maths Chapter 10 Mensuration Ex 10.1 Books State Board syllabus with maximum efficiency.

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Thursday, June 9, 2022