Hsslive.co.in: Kerala Higher Secondary News, Plus Two Notes, Plus One Notes, Plus two study material, Higher Secondary Question Paper.

Thursday, June 9, 2022

AP Board Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Book Answers

AP Board Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Book Answers
AP Board Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Book Answers


AP Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbooks Solutions and answers for students are now available in pdf format. Andhra Pradesh Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Book answers and solutions are one of the most important study materials for any student. The Andhra Pradesh State Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 books are published by the Andhra Pradesh Board Publishers. These Andhra Pradesh Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 textbooks are prepared by a group of expert faculty members. Students can download these AP Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 book solutions pdf online from this page.

Andhra Pradesh Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbooks Solutions PDF

Andhra Pradesh State Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbooks. These Andhra Pradesh State Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.

Andhra Pradesh State Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Books Solutions

Board AP Board
Materials Textbook Solutions/Guide
Format DOC/PDF
Class 10th
Subject Maths
Chapters Maths Chapter 7 Coordinate Geometry Ex 7.1
Provider Hsslive


How to download Andhra Pradesh Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbook Solutions Answers PDF Online?

  1. Visit our website - Hsslive
  2. Click on the Andhra Pradesh Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Answers.
  3. Look for your Andhra Pradesh Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbooks PDF.
  4. Now download or read the Andhra Pradesh Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbook Solutions for PDF Free.


AP Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

10th Class Maths 7th Lesson Coordinate Geometry Ex 7.1 Textbook Questions and Answers

Question 1.
Find the distance between the following pair of points,
(i) (2, 3) and (4, 1)
Answer:
Distance = \(\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}\)
= \(\sqrt{(4-2)^{2}+(1-3)^{2}}\)
= \(\sqrt{4+4}\)
= √8 = 2√2 units

ii) (- 5, 7) and (-1, 3)
Answer:
Distance = \(\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}\)
= \(\sqrt{(-1+5)^{2}+(3-7)^{2}}\)
= \(\sqrt{4^{2}+(-4)^{2}}\)
= \(\sqrt{16+16}\)
= √32 = 4√2 units

iii) (- 2, -3) and (3, 2)
Answer:

iv) (a, b) and (- a, – b)
Answer:

Question 2.
Find the distance between the points (0, 0) and (36, 15).
Answer:
Given: Origin O (0, 0) and a point P (36, 15).
Distance between any point and origin = \(\sqrt{x^{2}+y^{2}}\)
∴ Distance = \(\sqrt{36^{2}+15^{2}}\)
= \(\sqrt{1296+225}\)
= \(\sqrt{1521}\)
= 39 units

∴ 1521 = 32 × 132
\(\sqrt{1521}\) = 3 × 13 = 39

Question 3.
Verify that the points (1, 5), (2, 3) and (-2, -1) are collinear or not.
Answer:
Given: A (1, 5), B (2, 3) and C (- 2, – 1)

Here the sum of no two segments is equal to third segment.
Hence the points are not collinear.
!! Slope of AB, m1 = \(\frac{3-5}{2-1}\) = -2
Slope of BC, m2 = \(\frac{-1-3}{-2-2}\) = 1
m1 ≠ m2
Hence A, B, C are not collinear.

Question 4.
Check whether (5, -2), (6, 4) and (7,-2) are the vertices of an isosceles triangle.
Answer:
Let A = (5, – 2); B = (6, 4) and C = (7, – 2).

Now we have, AB = BC.
∴ △ABC is an isosceles triangle,
i.e., given points are the vertices of an isosceles triangle.

Question 5.
In a classroom, 4 friends are seated at the points A, B, C and D as shown in figure. Jarina and Phani walk into the class and after observing for a few minutes Jarina asks Phani “Don’t you think ABCD is a square?” Phani disagrees. Using distance formula, find which of them is correct. Why?

Answer:
Given: Four friends are seated at A, B, C and D where A (3, 4), B (6, 7), C (9, 4) and D (6, 1).
Now distance

BD = \(\sqrt{(6-6)^{2}+(1-7)^{2}}\) = √36 = 6
Hence in □ ABCD four sides are equal
i.e., AB = BC = CD = DA
= 3√2 units
and two diagonals are equal.
i.e., AC = BD = 6 units.
∴ □ ABCD forms a square.
i.e., Jarina is correct.

Question 6.
Show that the following points form an equilateral triangle A(a, 0), B(- a, 0), C(0, a√3).
Answer:
Given: A (a, 0), B (- a, 0), C (0, a√3).

Now, AB = BC = CA.
∴ △ABC is an equilateral triangle.

Question 7.
Prove that the points (-7, -3), (5, 10), (15, 8) and (3, -5) taken in order are the corners of a parallelogram.
Answer:
To show that the given points form a parallelogram.
We have to show that the mid points of each diagonal are same. Since diagonals of a parallelogram bisect each other.
Now let A(-7, -3), B(5, 10), C(15, 8) and D(3, -5)
Then midpoint of diagonal

∴ (1) = (2)
Hence the given are vertices of a parallelogram.

Question 8.
Show that the points (-4, -7), (-1, 2), (8, 5) and (5, -4) taken in order are the vertices of a rhombus. And find its area.
(Hint: Area of rhombus = \(\frac{1}{2}\) × product of its diagonals)
Answer:
Given in ▱ ABCD , A(-4, – 7), B (- 1, 2), C (8, 5) and D (5,-4)


∴ In ▱ ABCD, AB = BC = CD = AD [from sides are equal]
Hence ▱ ABCD is a rhombus.
Area of a rhombus = \(\frac{1}{2}\) d1d2
= \(\frac{1}{2}\) × 12√2 × 6√2
= 72 sq. units.

Question 9.
Name the type of quadrilateral formed, if any, by the following points, and give reasons for your answer.
i) (-1,-2), (1,0), (-1,2), (-3,0)
Answer:
Let A (- 1, -2), B (1, 0), C (- 1, 2), D (- 3, 0) be the given points. Distance formula

In ▱ ABCD, AB = BC = CD = AD – four sides are equal.
AC = BD – diagonals are equal.
Hence, the given points form a square,

ii) (-3, 5), (1, 10), (3, 1), (-1,-4).
Answer:
Let A(-3, 5), B(l,10), C(3, 1), D(-l, -4) then

In ▱ ABCD, \(\overline{\mathrm{AB}}\) = \(\overline{\mathrm{CD}}\) and \(\overline{\mathrm{BC}}\) = \(\overline{\mathrm{AD}}\) (i.e., both pairs of opposite sides are equal) and \(\overline{\mathrm{AC}}\) ≠ \(\overline{\mathrm{BD}}\).
Hence ▱ ABCD is a parallelogram,
i.e., The given points form a parallelogram.

iii) (4, 5), (7, 6), (4, 3), (1, 2).
Answer:
Let A (4, 5), B (7, 6), C (4, 3) and D (1, 2) be the given points.
Distance formula

In ▱ ABCD, AB = CD and BC = AD (i.e., both pairs of opposite sides are equal) and AC ≠ BD.
Hence ▱ ABCD is a parallelogram, i.e., The given points form a parallelogram.

Question 10.
Find the point on the X-axis which is equidistant from (2, -5) and (-2,9).
Answer:
Given points, A (2, – 5), B (- 2, 9).
Let P (x, 0) be the point on X – axis which is equidistant from A and B. i.e., PA = PB.
Distance formula = \(\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}\)

But PA = PB.
⇒ \(\sqrt{x^{2}-4 x+29}=\sqrt{x^{2}+4 x+85}\)
Squaring on both sides, we get
x2 – 4x + 29 = x2 + 4x + 85
⇒ – 4x – 4x = 85 – 29
⇒ – 8x = 56
⇒ x = \(\frac{56}{-8}\) = -7
∴ (x, 0) = (- 7, 0) is the point which is equidistant from the given points.

Question 11.
If the distance between two points (x, 7) and (1, 15) is 10, find the value of x.
Answer:
Formula for distance between two points = \(\sqrt{\left(x_{1}-x_{2}\right)^{2}+\left(y_{1}-y_{2}\right)^{2}}\)
Now distance between (x, 7) and (1,15) is 10.
∴ \(\sqrt{(x-1)^{2}+(7-15)^{2}}\) = 10
∴ (x – l)2 + (-8)2 = 102
⇒ (x – l)2 = 100 – 64 = 36
∴ x – 1 = √36 = ± 6
∴ x – 1 = 6 or x – 1 = -6
⇒ x = 6 + 1 = 7 or x = -6 + 1 = -5
∴ x = 7 or x = – 5

Question 12.
Find the values of y for which the distance between the points P(2, -3) and Q(10, y) is 10 units.
Answer:
Given: P (2, – 3), Q (10, y) and
\(\overline{\mathrm{PQ}}\) = 10.
Distance formula = \(\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}\)

⇒ y2 + 6y + 73 = 100
⇒ y2 + 6y – 27 = 0
⇒ y2 + 9y – 3y – 27 = 0
⇒ y (y + 9) – 3 (y + 9) = 0
⇒ (y + 9) (y – 3) = 0
⇒ y + 9 = 0 or y – 3 = 0
⇒ y = -9 or y = 3
⇒ y = – 9 or 3.

Question 13.
Find the radius of the circle whose centre is (3, 2) and passes through (-5,6).
Answer:

Given: A circle with centre A (3, 2) passing through B (- 5, 6).
Radius = AB
[∵ Distance of a point from the centre of the circle]
Distance formula = \(\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}\)

Question 14.
Can you draw a triangle with vertices (1, 5), (5, 8) and (13, 14)? Give reason.
Answer:
Let A (1, 5), B (5, 8) and C (13, 14) be the given points.
Distance formula

Here, AC = AB + BC.
∴ △ABC can’t be formed with the given vertices.
[∵ Sum of the any two sides of a triangle must be greater than the third side].

Question 15.
Find a relation between x and y such that the point (x, y) is equidistant from the points (-2, 8) and (-3, -5).
Answer:
Let A (- 2, 8), B (- 3, – 5) and P (x, y). If P is equidistant from A, B, then PA = PB.
Distance formula =


Squaring on both sides we get, x2 + y2 + 4x – 16y + 68
= x2 + y2 + 6x +10y + 34
⇒ 4x – 16y – 6x – 10y = 34-68
⇒ – 2x – 26y = -34
⇒ x + 13y = 17 is the required condition.


AP Board Textbook Solutions PDF for Class 10th Maths


Andhra Pradesh Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbooks for Exam Preparations

Andhra Pradesh Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 exam preparation. The AP Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Books State Board syllabus with maximum efficiency.

FAQs Regarding Andhra Pradesh Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbook Solutions


How to get AP Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbook Answers??

Students can download the Andhra Pradesh Board Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.1 Answers PDF from the links provided above.

Can we get a Andhra Pradesh State Board Book PDF for all Classes?

Yes you can get Andhra Pradesh Board Text Book PDF for all classes using the links provided in the above article.

Important Terms

Andhra Pradesh Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1, AP Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbooks, Andhra Pradesh State Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1, Andhra Pradesh State Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbook solutions, AP Board Class 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbooks Solutions, Andhra Pradesh Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1, AP Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbooks, Andhra Pradesh State Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1, Andhra Pradesh State Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbook solutions, AP Board STD 10th Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbooks Solutions,
Share:

0 Comments:

Post a Comment

Plus Two (+2) Previous Year Question Papers

Plus Two (+2) Previous Year Chapter Wise Question Papers, Plus Two (+2) Physics Previous Year Chapter Wise Question Papers , Plus Two (+2) Chemistry Previous Year Chapter Wise Question Papers, Plus Two (+2) Maths Previous Year Chapter Wise Question Papers, Plus Two (+2) Zoology Previous Year Chapter Wise Question Papers, Plus Two (+2) Botany Previous Year Chapter Wise Question Papers, Plus Two (+2) Computer Science Previous Year Chapter Wise Question Papers, Plus Two (+2) Computer Application Previous Year Chapter Wise Question Papers, Plus Two (+2) Commerce Previous Year Chapter Wise Question Papers , Plus Two (+2) Humanities Previous Year Chapter Wise Question Papers , Plus Two (+2) Economics Previous Year Chapter Wise Question Papers , Plus Two (+2) History Previous Year Chapter Wise Question Papers , Plus Two (+2) Islamic History Previous Year Chapter Wise Question Papers, Plus Two (+2) Psychology Previous Year Chapter Wise Question Papers , Plus Two (+2) Sociology Previous Year Chapter Wise Question Papers , Plus Two (+2) Political Science Previous Year Chapter Wise Question Papers, Plus Two (+2) Geography Previous Year Chapter Wise Question Papers, Plus Two (+2) Accountancy Previous Year Chapter Wise Question Papers, Plus Two (+2) Business Studies Previous Year Chapter Wise Question Papers, Plus Two (+2) English Previous Year Chapter Wise Question Papers , Plus Two (+2) Hindi Previous Year Chapter Wise Question Papers, Plus Two (+2) Arabic Previous Year Chapter Wise Question Papers, Plus Two (+2) Kaithang Previous Year Chapter Wise Question Papers , Plus Two (+2) Malayalam Previous Year Chapter Wise Question Papers

Plus One (+1) Previous Year Question Papers

Plus One (+1) Previous Year Chapter Wise Question Papers, Plus One (+1) Physics Previous Year Chapter Wise Question Papers , Plus One (+1) Chemistry Previous Year Chapter Wise Question Papers, Plus One (+1) Maths Previous Year Chapter Wise Question Papers, Plus One (+1) Zoology Previous Year Chapter Wise Question Papers , Plus One (+1) Botany Previous Year Chapter Wise Question Papers, Plus One (+1) Computer Science Previous Year Chapter Wise Question Papers, Plus One (+1) Computer Application Previous Year Chapter Wise Question Papers, Plus One (+1) Commerce Previous Year Chapter Wise Question Papers , Plus One (+1) Humanities Previous Year Chapter Wise Question Papers , Plus One (+1) Economics Previous Year Chapter Wise Question Papers , Plus One (+1) History Previous Year Chapter Wise Question Papers , Plus One (+1) Islamic History Previous Year Chapter Wise Question Papers, Plus One (+1) Psychology Previous Year Chapter Wise Question Papers , Plus One (+1) Sociology Previous Year Chapter Wise Question Papers , Plus One (+1) Political Science Previous Year Chapter Wise Question Papers, Plus One (+1) Geography Previous Year Chapter Wise Question Papers , Plus One (+1) Accountancy Previous Year Chapter Wise Question Papers, Plus One (+1) Business Studies Previous Year Chapter Wise Question Papers, Plus One (+1) English Previous Year Chapter Wise Question Papers , Plus One (+1) Hindi Previous Year Chapter Wise Question Papers, Plus One (+1) Arabic Previous Year Chapter Wise Question Papers, Plus One (+1) Kaithang Previous Year Chapter Wise Question Papers , Plus One (+1) Malayalam Previous Year Chapter Wise Question Papers
Copyright © HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board About | Contact | Privacy Policy