AP Board Class 10 Maths Chapter 5 Quadratic Equations Ex 5.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 5 Quadratic Equations Ex 5.2 Book Answers |

## Andhra Pradesh Board Class 10th Maths Chapter 5 Quadratic Equations Ex 5.2 Textbooks Solutions PDF

Andhra Pradesh State Board STD 10th Maths Chapter 5 Quadratic Equations Ex 5.2 Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 10th Maths Chapter 5 Quadratic Equations Ex 5.2 Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 10th Maths Chapter 5 Quadratic Equations Ex 5.2 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 10th Maths Chapter 5 Quadratic Equations Ex 5.2 Textbooks. These Andhra Pradesh State Board Class 10th Maths Chapter 5 Quadratic Equations Ex 5.2 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.## Andhra Pradesh State Board Class 10th Maths Chapter 5 Quadratic Equations Ex 5.2 Books Solutions

Board | AP Board |

Materials | Textbook Solutions/Guide |

Format | DOC/PDF |

Class | 10th |

Subject | Maths |

Chapters | Maths Chapter 5 Quadratic Equations Ex 5.2 |

Provider | Hsslive |

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## AP Board Class 10th Maths Chapter 5 Quadratic Equations Ex 5.2 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 10th Maths Chapter 5 Quadratic Equations Ex 5.2 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:### 10th Class Maths 5th Lesson Quadratic Equations Ex 5.2 Textbook Questions and Answers

Question 1.

Find the roots of the following quadratic equations by factorisation,

i) x^{2} – 3x – 10 = 0

Answer:

Given: x^{2} – 3x – 10 = 0

x^{2} – 5x + 2x- 10 = 0

⇒ x(x – 5) + 2 (x – 5) = 0

⇒ (x – 5) (x + 2) = 0

⇒ x – 5 = 0 or x + 2 = 0

⇒ x = 5 or x = -2

⇒ x = 5 or -2

are the roots of the given Q.E.

ii) 2x^{2} + x – 6 = 0

Answer:

Given: 2x^{2} + x – 6 = 0

⇒ 2x^{2} + 4x – 3x – 6 = 0

⇒ 2x(x + 2) – 3(x + 2) = 0

⇒ (x + 2) (2x – 3) = 0

⇒ (x + 2) or 2x – 3 = 0

⇒ x = -2 or 2x = 3

⇒ x = -2 or 32

are the roots of the given Q.E.

iii) √2x^{2} + 7x + 5√2 =0

Answer:

Given: √2x^{2} + 7x + 5√2 =0

⇒ √2x^{2} + 5x + 2x + 5√2 = 0

⇒ x(√2x + 5)+ √2(√2x + 5) = 0

⇒ (√2x + 5) (x + √2) = 0

⇒ √2x + 5 = 0 or x + √2 = 0

⇒ √2x = -5 or x = -√2

⇒ x = −52√ = or -√2

are the roots of √2 the given Q.E.

iv) 2x^{2} – x + 18 = 0

Answer:

Given: 2x^{2} – x + 18 = 0

⇒ 16𝑥2−8𝑥+18 = 0

⇒ 16x^{2} – 8x + 1 =0

⇒ 16x^{2} – 4x – 4x + 1 = 0

⇒ 4x(4x – 1) – l(4x – 1) = 0

⇒ (4x – 1) (4x – 1) – 0

⇒ 4x – 1 = 0

⇒ 4x = l

⇒ x = 14, 14

are the roots of given Q.E.

v) 100x^{2} – 20x + 1 = 0

Answer:

Given : 100x^{2} – 20x + 1 =0

⇒ 100x^{2} – 10x – 10x + 1 = 0

⇒ 10x(10x – 1) – l(10x – 1) = 0

⇒ (10x – 1) (10x – l) = 0

⇒ 10x – 1 = 0

⇒ 10x = 1

⇒ x = 110, 110

are the roots of the given Q.E.

vi) x(x + 4) = 12

Answer:

Given: x(x + 4) = 12

⇒ x^{2} + 4x = 12

⇒ x^{2} + 4x – 12 = 0

⇒ x^{2} + 6x – 2x – 12 = 0

⇒ x(x + 6) – 2(x + 6) = 0

⇒ (x + 6) (x – 2) = 0

⇒ x + 6 = 0 or x – 2 = 0

⇒ x = -6 or x = 2

⇒ x = -6 or 2

are the roots of the given Q.E.

vii) 3x^{2} – 5x + 2 = 0

Answer:

Given: 3x^{2} – 5x + 2 = 0

⇒ 3x^{2} – 3x – 2x + 2 = 0

⇒ 3x(x – 1) – 2(x – 1) = 0

⇒ (x – 1) (3x – 2) = 0

⇒ x – 1 = 0 or 3x – 2 = 0

⇒ x = 1 or 23,

⇒ x = 1 or 23 are the roots of the given Q.E.

viii) x – 3𝑥 = 2

Answer:

Given: x – 3𝑥 = 2

⇒ 𝑥2−3𝑥 = 2

⇒ x^{2} – 3 = 2x

⇒ x^{2} – 2x – 3 = 0

⇒ x^{2} – 3x + x – 3 = 0

⇒ x(x – 3) + l(x – 3) = 0

⇒ (x – 3) (x + 1) = 0

⇒ (x – 3) = 0 or (x + 1) = 0

⇒ x = 3 or x = -1

⇒ x = 3 or -1 are the roots of the given Q.E.

ix) 3(x – 4)^{2} – 5(x – 4) = 12

Answer:

Take (x – 4) = a, then the given Q.E. reduces to 3a^{2} – 5a = 12

⇒ 3a^{2} – 5a – 12 = 0

⇒ 3a^{2} – 9a + 4a – 12 = 0

⇒ 3a(a – 3) + 4(a – 3) = 0

⇒ (a – 3) (3a + 4) = 0

⇒ a – 3 = 0 or 3a + 4 = 0

⇒ a = 3 or a = −43

but a = x – 4

x – 4 = 3 (or) x – 4 = −43

⇒ x = 7 or x = 4 – −43 = 83

∴ x = 7 or 83

are the roots of the given Q.E.

Question 2.

Find two numbers whose sum is 27 and product is 182.

Answer:

Let a number be x.

Then the other number = 27 – x

Product of the numbers = x(27 – x) = 27x – x^{2}

By problem 27x – x^{2} = 182

⇒ x^{2} – 27x + 182 = 0

⇒ x^{2} – 14x – 13x + 182 = 0

⇒ x(x- 14) – 13(x – 14) = 0

⇒ (x – 13) (x – 14) = 0

⇒ x – 13 = 0 or x – 14 = 0

⇒ x = 13 or 14.

∴ The numbers are 13; 27 – 13 = 14 or 14 and 27 – 14 = 13.

Question 3.

Find two consecutive positive integers, sum of whose squares is 613.

Answer:

Let a positive integer be x.

Then the second integer = x + 1

Sum of the squares of the above integers = x^{2} + (x + 1)^{2}

= x^{2} + x^{2} + 2x + 1

= 2x^{2} + 2x + 1

By problem 2x^{2} + 2x + 1 = 613

⇒ 2x^{2} + 2x – 612 = 0

⇒ x^{2} + x – 306 = 0

⇒ x^{2} + 18x – 17x – 306 = 0

⇒ x(x + 18) – 17(x + 18) = 0

⇒ (x – 17) (x + 18) = 0

⇒ x – 17 = 0 (or) x + 18 = 0

⇒ x = 17 (or) -18,

we do not consider -18

Then the numbers are (17, 17 + 1)

i.e., 17, 18 are the required two consecutive positive integers.

Question 4.

The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.

Answer:

Let the base of the right triangle = x cm

Then its altitude = x – 7 cm

By Pythagoras Theorem

(base)^{2} + (height)^{2} = (hypotenuse)^{2}

⇒ x^{2} + (x – 7)^{2} = 13^{2}

⇒ x^{2} + x^{2} – 14x + 49 = 169 .

⇒ 2x^{2} – 14x + 49 – 169 = 0

⇒ 2x^{2} – 14x – 120 = 0

⇒ x^{2} – 7x – 60 = 0

⇒ x^{2} – 12x + 5x – 60 = 0

⇒ x(x – 12) + 5(x – 12) = 0

⇒ (x – 12) (x + 5) = 0

⇒ x – 12 = 0 (or) x + 5 = 0

⇒ x = 12 (or) x = -5 But x can’t be negative.

∴ x = 12

x – 7 = 12 – 7 = 5

The two sides are 12 cm and 5 cm.

Question 5.

A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was Rs. 90, find the number of articles produced and the cost of each article.

Answer:

Let the number of articles produced be x.

Then the cost of each article = 2x + 3

Total cost of the articles produced = x [2x + 3] = 2x^{2} + 3x

By problem 2x^{2} + 3x = 90

⇒ 2x^{2} + 3x – 90 = 0

⇒ 2x^{2} + 15x – 12x – 90 = 0

⇒ x (2x + 15) – 6 (2x + 15) = 0

⇒ (2x + 15) (x – 6) = 0

⇒ 2x + 15 = 0 (or) x – 6 = 0

⇒ x = −152 or x = 6

But x can’t be negative.

∴ x = 6

2x + 3 = 2 × 6 + 3 = 15

∴ Number of articles produced = 6 Cost of each article = Rs. 15.

Question 6.

Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40 square meters.

Answer:

Let the length of the rectangle = x

Given perimeter = 2(1 + b) = 28

⇒ (1 + b) = 282 = 14

Breadth of the rectangle = 14 – x

Area = length . breadth = x (14 – x)

= 14x – x^{2}

By problem, 14x – x^{2} = 40.

⇒ x^{2} – 14x + 40 = 0

⇒ x^{2} – 10x – 4x + 40 = 0

⇒ x(x – 10) – 4(x – 10) = 0

⇒ (x – 10) (x – 4) = 0

⇒ x – 10 = 0 (or) x – 4 = 0

⇒ x = 10 (or) 4

∴ Length = 10 m or 4 m

Then breadth = 14 – 10 = 4 m (or) 14 – 4 = 10 m

Question 7.

The base of a triangle is 4 cm longer than its altitude. If the area of the triangle is 48 sq.cm, then find its base and altitude.

Answer:

Let the altitude of the triangle h = x cm

Then its base ‘b’ = x + 4.

Area = 12 × base × height

= 12(x + 4)(x)

= 𝑥2+4𝑥2

By problem 𝑥2+4𝑥2 = 48

⇒ x^{2} + 4x = 2 × 48

⇒ x^{2} + 4x – 96 = 0

⇒ x^{2} + 12x – 8x – 96 = 0

⇒ x(x + 12) – 8(x + 12) = 0

⇒ (x + 12)(x – 8) = 0

⇒ x + 12 = 0 (or) x – 8 = 0

⇒ x = -12 (or) x = 8

But x can’t be negative.

∴ x = 8 and x + 4 = 8 + 4 = 12

Hence altitude = 8 cm and base = 12 cm.

Question 8.

Two trains leave a railway station at the same time. The first train travels towards west and the second train towards north. The first train travels 5 km/hr faster than the second train. If after two hours they are 50 km. apart, find the average speed of each train.

Answer:

Let the speed of the slower train = x kmph

Then speed of the faster train = x + 5 kmph.

Distance = Speed × Time

Distance travelled by the first train = 2(x + 5) = 2x + 10

Distance travelled by the second train = 2.x = 2x

By Pythagoras Theorem

(hypotenuse)^{2} = (side)^{2} + (side)^{2}

⇒ (2x)^{2} + (2x + 10)2^{2} = 50^{2}

⇒ 4x^{2} + (4x^{2} + 40x + 100) = 2500

⇒ 4x^{2} + 4x^{2} + 40x + 100 = 2500

⇒ 8x^{2} + 40x – 2400 = 0

⇒ x^{2} + 5x – 300 = 0

⇒ x^{2} + 20x – 15x – 300 = 0

⇒ x (x + 20) – 15 (x + 20) = 0

⇒ (x + 20) (x – 15) = 0

∴ x – 15 = 0 (or) x + 20 = 0

⇒ x = 15 (or) – 20

But x can’t be negative.

∴ Speed of the slower train x = 15 kmph.

Speed of the faster train x + 5 = 15 + 5 = 20 kmph.

Question 9.

In a class of 60 students, each boy contributed rupees equal to the number of girls and each girl contributed rupees equal to the number of boys. If the total money then collected was Rs. 1600, how many boys are there in the class?

Answer:

Let the number of boys in the class=x

Then number of girls in the class=60 – x [∵ total students = 60]

Money contributed by the boys = x(60 – x) = 60x – x^{2} [∵ given]

Money contributed by the girls = (60 – x)x = 60x – x^{2}

∴ Money contributed by the class=120x – 2x^{2}

By problem 120x -2x^{2} = 1600

⇒ 2x^{2}– 120x + 1600 = 0

⇒ x^{2} – 60x + 800 = 0

⇒ x^{2} – 40x – 20x + 800 = 0

⇒ x(x – 40) – 20 (x – 40) = 0

⇒ (x – 40) (x – 20) = 0

⇒ x = 40 (or) 20

∴ Boys = 40 or 20 Girls = 20 or 40.

Question 10.

A motor boat heads upstream a distance of 24 km on a river whose current is running at 3 km per hour. The trip up and back takes 6 hours. Assuming that the motor boat maintained a constant speed, what was its speed ?

Answer:

Let the speed of the boat in still water be x kmph.

Speed of the current = 3 kmph

Then speed of the boat in upstream = (x – 3) kmph

Speed of the boat in downstream = (x + 3) kmph

By problem total time taken = 6h.

⇒ 24(2x) = 6(x^{2} – 9)

⇒ 8x = x^{2} – 9

⇒ x^{2} – 8x – 9 = 0

⇒ x^{2} – 9x + x-9 = 0

⇒ x (x – 9) + 1 (x – 9) = 6

⇒ (x – 9) (x + 1) = 0

⇒ x – 9 = 0 or x + 1 = 0

x can’t be negative,

∴ x = 9

i.e., speed of the boat in still water = 9 kmph.

## AP Board Textbook Solutions PDF for Class 10th Maths

- AP Board Class 10 Maths Chapter 1 Real Numbers Ex 1.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 1 Real Numbers Ex 1.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 1 Real Numbers Ex 1.3 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 1 Real Numbers Ex 1.4 Textbook Solutions PDF
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- AP Board Class 10 Maths Chapter 2 Sets Ex 2.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 2 Sets Ex 2.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 2 Sets Ex 2.3 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 2 Sets Ex 2.4 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 2 Sets InText Questions Textbook Solutions PDF

- AP Board Class 10 Maths Chapter 3 Polynomials Ex 3.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 3 Polynomials Ex 3.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 3 Polynomials Ex 3.3 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 3 Polynomials Ex 3.4 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 3 Polynomials Optional Exercise Textbook Solutions PDF
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- AP Board Class 10 Maths Chapter 4 Pair of Linear Equations in Two Variables Ex 4.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 4 Pair of Linear Equations in Two Variables Ex 4.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 4 Pair of Linear Equations in Two Variables Ex 4.3 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 4 Pair of Linear Equations in Two Variables Optional Exercise Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 4 Pair of Linear Equations in Two Variables InText Questions Textbook Solutions PDF

- AP Board Class 10 Maths Chapter 5 Quadratic Equations Ex 5.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 5 Quadratic Equations Ex 5.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 5 Quadratic Equations Ex 5.3 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 5 Quadratic Equations Ex 5.4 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 5 Quadratic Equations Optional Exercise Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 5 Quadratic Equations InText Questions Textbook Solutions PDF

- AP Board Class 10 Maths Chapter 6 Progressions Ex 6.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 6 Progressions Ex 6.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 6 Progressions Ex 6.3 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 6 Progressions Ex 6.4 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 6 Progressions Ex 6.5 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 6 Progressions Optional Exercise Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 6 Progressions InText Questions Textbook Solutions PDF

- AP Board Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.3 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 7 Coordinate Geometry Ex 7.4 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 7 Coordinate Geometry Optional Exercise Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 7 Coordinate Geometry InText Questions Textbook Solutions PDF

- AP Board Class 10 Maths Chapter 8 Similar Triangles Ex 8.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 8 Similar Triangles Ex 8.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 8 Similar Triangles Ex 8.3 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 8 Similar Triangles Ex 8.4 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 8 Similar Triangles Optional Exercise Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 8 Similar Triangles InText Questions Textbook Solutions PDF

- AP Board Class 10 Maths Chapter 9 Tangents and Secants to a Circle Ex 9.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 9 Tangents and Secants to a Circle Ex 9.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 9 Tangents and Secants to a Circle Ex 9.3 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 9 Tangents and Secants to a Circle Optional Exercise Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 9 Tangents and Secants to a Circle InText Questions Textbook Solutions PDF

- AP Board Class 10 Maths Chapter 10 Mensuration Ex 10.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 10 Mensuration Ex 10.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 10 Mensuration Ex 10.3 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 10 Mensuration Ex 10.4 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 10 Mensuration Optional Exercise Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 10 Mensuration InText Questions Textbook Solutions PDF

- AP Board Class 10 Maths Chapter 11 Trigonometry Ex 11.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 11 Trigonometry Ex 11.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 11 Trigonometry Ex 11.3 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 11 Trigonometry Ex 11.4 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 11 Trigonometry Optional Exercise Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 11 Trigonometry InText Questions Textbook Solutions PDF

- AP Board Class 10 Maths Chapter 12 Applications of Trigonometry Ex 12.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 12 Applications of Trigonometry Ex 12.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 12 Applications of Trigonometry Optional Exercise Textbook Solutions PDF
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- AP Board Class 10 Maths Chapter 13 Probability Ex 13.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 13 Probability Ex 13.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 13 Probability Optional Exercise Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 13 Probability InText Questions Textbook Solutions PDF

- AP Board Class 10 Maths Chapter 14 Statistics Ex 14.1 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 14 Statistics Ex 14.2 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 14 Statistics Ex 14.3 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 14 Statistics Ex 14.4 Textbook Solutions PDF
- AP Board Class 10 Maths Chapter 14 Statistics InText Questions Textbook Solutions PDF

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