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AP Board Class 10 Maths Chapter 13 Probability InText Questions Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 13 Probability InText Questions Book Answers |
Andhra Pradesh Board Class 10th Maths Chapter 13 Probability InText Questions Textbooks Solutions PDF
Andhra Pradesh State Board STD 10th Maths Chapter 13 Probability InText Questions Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 10th Maths Chapter 13 Probability InText Questions Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 10th Maths Chapter 13 Probability InText Questions solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 10th Maths Chapter 13 Probability InText Questions Textbooks. These Andhra Pradesh State Board Class 10th Maths Chapter 13 Probability InText Questions Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.Andhra Pradesh State Board Class 10th Maths Chapter 13 Probability InText Questions Books Solutions
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AP Board Class 10th Maths Chapter 13 Probability InText Questions Textbooks Solutions with Answer PDF Download
Find below the list of all AP Board Class 10th Maths Chapter 13 Probability InText Questions Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:10th Class Maths 13th Lesson Probability InText Questions and Answers
Do This
(Page No. 307)
Outcomes of which of the following experiments are equally likely ?
Question 1.
Getting a digit 1, 2, 3, 4, 5 or 6 when a die is rolled.
Answer:
Equally likely.
Question 2.
Picking a different colour ball from a bag of 5 red balls, 4 blue balls and 1 black ball.
Note: Picking two different colour balls …………..
i.e., picking a red or blue or black ball from a …………
Answer:
Not equally likely.
Question 3.
Winning in a game of carrom.
Answer:
Equally likely.
Question 4.
Units place of a two digit number selected may be 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9.
Answer:
Equally likely.
Question 5.
Picking a different colour ball from a bag of 10 red balls, 10 blue balls and 10 black balls.
Answer:
Equally likely.
Question 6.
a) Raining on a particular day of July.
Answer:
Not equally likely.
b) Are the outcomes of every experiment equally likely?
Answer:
Outcomes of all experiments need not necessarily be equally likely.
c) Give examples of 5 experiments that have equally likely outcomes and five more examples that do not have equally likely outcomes.
Answer:
Equally likely events:
- Getting an even or odd number when a die is rolled.
- Getting tail or head when a coin is tossed.
- Getting an even or odd number when a card is drawn at random from a pack of cards numbered from 1 to 10.
- Drawing a green or black ball from a bag containing 8 green balls and 8 black balls.
- Selecting a boy or girl from a class of 20 boys and 20 girls.
- Drawing a red or black card from a deck of cards.
Events which are not equally likely:
- Getting a prime or composite number when a die is thrown.
- Getting an even or odd number when a card is drawn at random from a pack of cards numbered from 1 to 5.
- Getting a number which is a multiple of 3 or not a multiple of 3 from numbers 1, 2, …… 10.
- Getting a number less than 5 or greater than 5.
- Drawing a white ball or green ball from a bag containing 5 green balls and 8 white balls.
Question 7.
Think of 5 situations with equally likely events and find the sample space. (Page No. 309)
Answer:
a) Tossing a coin: Getting a tail or head when a coin is tossed.
Sample space = {T, H}.
b) Getting an even or odd number when a die is rolled.
Sample space = (1, 2, 3, 4, 5, 6}.
c) Winning a game of shuttle.
Sample space = (win, loss}.
d) Picking a black or blue ball from a bag containing 3 blue balls and 3 blackballs = {blue, black}.
e) Drawing a blue coloured card or black coloured card from a deck of cards = {black, red}.
Question 8.
i) Is getting a head complementary to getting a tail? Give reasons. (Page No. 311)
Answer:
Number of outcomes favourable to head = 1
Probability of getting a head = 12 [P(E)]
Number of outcomes not favourable to head = 1
Probability of not getting a head = 12 [P(E⎯⎯⎯⎯)]
Now P(E) + P(E⎯⎯⎯⎯) = 12 + 12 = 1
∴ Getting a head is complementary to getting a tail.
ii) In case of a die is getting a 1 comple-mentary to events getting 2, 3, 4, 5, 6? Give reasons for your answer.
Answer:
Yes. Complementary events.
∵ Probability of getting 1 = 16 [P(E)]
Probability of getting 2, 3, 4, 5, 6 = P(E) = P(E⎯⎯⎯⎯) = 56
P(E) + P(E⎯⎯⎯⎯) = 16 + 56 = 66 = 1
iii) Write of five new pair of events that are complementary.
Answer:
- When a dice is thrown, getting an even number is complementary to getting an odd number.
- Drawing a red card from a deck of cards is complementary to getting a black card.
- Getting an even number is complementary to getting an odd number from numbers 1, 2, ….. 8.
- Getting a Sunday is complementary to getting any day other than Sunday in a week.
- Winning a running race is complementary to loosing it.
Try This
Question 1.
A child has a dice whose six faces show the letters A, B, C, D, E and F. The dice is thrown once. What is the probability of getting (i) A? (ii) D? (Page No. 312)
Answer:
Total number of outcomes (A, B, C, D, E and F) = 6.
i) Number of favourable outcomes to A = 1
Probability of getting A =
P(A) = No.of favourable outcomesto A No.of all possible outcomes = 16
ii) No. of outcomes favourable to D = 1
Probability of getting D
= No.of outcomes favourble to D All possible outcomes = 16
Question 2.
Which of the following cannot be the probability of an event? (Page No. 312)
(a) 2.3
(b) -1.5
(c) 15%
(d) 0.7
Answer:
a) 2.3 – Not possible
b) -1.5 – Not possible
c) 15% – May be the probability
d) 0.7 – May be the probability
Question 3.
You have a single deck of well shuffled cards. Then, what is the probability that the card drawn will be a queen? (Page No. 313)
Answer:
Number of all possible outcomes = 4 × 13 = 1 × 52 = 52
Number of outcomes favourable to Queen = 4 [♥ Q, ♦ Q, ♠ Q, ♣ Q]
∴ Probability P(E) = No. of favourable outcomes Total no. of outcomes
= 452 = 113
Question 4.
What is the probability that it is a face card? (Page No. 314)
Answer:
Face cards are J, Q, K.
∴ Number of outcomes favourable to face card = 4 × 3 = 12
No. of all possible outcomes = 52
P(E) = No. of favourable outcomes Total no. of outcomes
= 1252 = 313
Question 5.
What is the probability that it is a spade? (Page No. 314)
Answer:
Number of spade cards = 13
Total number of cards = 52
Probability
= Number of outcomes favourable to spades Number of all outcomes
= 1352 = 14
Question 6.
What is the probability that is the face card of spades? (Page No. 314)
Answer:
Number of outcomes favourable to face cards of spades = (K, Q, J) = 3
Number of all outcomes = 52
P(E) = 352
Question 7.
What is the probability it is not a face card? (Page No. 314)
Answer:
Probability of a face card = 1252 from (1)
∴ Probability that the card is not a face card
(or)
Number of favourable outcomes = 4 × 10 = 40
Number of all outcomes = 52
∴ Probability
= No. of favourable outcomes Total no. of outcomes
= 4052 = 1013
Think & Discuss
(Page No. 312)
Question 1.
Why is tossing a coin considered to be a fair way of deciding which team should get the ball at the beginning of any game?
Answer:
Probability of getting a head is 12 and of a tail is 12 are equal.
Hence tossing a coin is a fair way.
Question 2.
Can 72 be the probability of an event? Explain.
Answer:
72 can’t be the probability of any event.
Since probability of any event should lie between 0 and 1.
Question 3.
Which of the following arguments are correct and which are not correct? Give reasons.
i) If two coins are tossed simultaneously, there are three possible outcomes – two heads, two tails or one of each. Therefore, for each of these outcomes, the probability is 13.
Answer:
False.
Reason:
All possible outcomes are 4
HH, HT, TH, TT
Thus, probability of two heads = 14
Probability of two tails = 14
Probability of one each = 24 = 12.
ii) If a dice is thrown, there are two possible outcomes – an odd number or an even number. Therefore, the probability of getting an odd number is 12.
Answer:
True.
Reason:
All possible outcomes = (1, 2, 3, 4, 5, 6) = 6
Outcomes favourable to an odd number (1, 3, 5) = 3
Outcomes favourable to an even number = (2, 4, 6) = 3
∴ Probability (odd number)
= No. of favourable outcomes Total no. of outcomes
= 36 = 12.
AP Board Textbook Solutions PDF for Class 10th Maths
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