AP Board Class 10 Maths Chapter 14 Statistics Ex 14.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 14 Statistics Ex 14.2 Book Answers ~ HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

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AP Board Class 10 Maths Chapter 14 Statistics Ex 14.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 14 Statistics Ex 14.2 Book Answers

AP Board Class 10th Maths Chapter 14 Statistics Ex 14.2 Textbooks Solutions and answers for students are now available in pdf format. Andhra Pradesh Board Class 10th Maths Chapter 14 Statistics Ex 14.2 Book answers and solutions are one of the most important study materials for any student. The Andhra Pradesh State Board Class 10th Maths Chapter 14 Statistics Ex 14.2 books are published by the Andhra Pradesh Board Publishers. These Andhra Pradesh Board Class 10th Maths Chapter 14 Statistics Ex 14.2 textbooks are prepared by a group of expert faculty members. Students can download these AP Board STD 10th Maths Chapter 14 Statistics Ex 14.2 book solutions pdf online from this page.

Andhra Pradesh Board Class 10th Maths Chapter 14 Statistics Ex 14.2 Textbooks Solutions PDF

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Andhra Pradesh State Board Class 10th Maths Chapter 14 Statistics Ex 14.2 Books Solutions

Board	AP Board
Materials	Textbook Solutions/Guide
Format	DOC/PDF
Class	10th
Subject	Maths
Chapters	Maths Chapter 14 Statistics Ex 14.2
Provider	Hsslive

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AP Board Class 10th Maths Chapter 14 Statistics Ex 14.2 Textbooks Solutions with Answer PDF Download

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10th Class Maths 14th Lesson Statistics Ex 14.2 Textbook Questions and Answers

Question 1.
The following table shows the ages of the patients admitted in a hospital during a year:

Find the mode and the mean of the data given above. Compare and interpret the two measures of central tendency.
Answer:
Maximum number of patients joined in the age group 35 – 45.
∴ Modal class is 35 – 45.
Lower limit of the modal class ‘l’ = 35
Class size h = 10
Frequency of modal class, f₁ = 23
Frequency of the class preceding the modal class f₀ = 21
Frequency of the class succeeding the modal class f₂ = 14

∴ Mode = 𝑙+(𝑓1−𝑓0)2𝑓1−𝑓0−𝑓2×ℎ
=35+(23−212×23−21−14)×10=35+(246−35)×10
= 35 + 211 × 10
= 35 + 1.81818……
= 36.8 years.
Mean x = ΣfixiΣfi
= 283080
= 35.37 years.
Interpretation: Mode age is 36.8 years, Mean age = 35.37 years.
Maximum number of patients admitted in the hospital are of the age 36.8 years, while on an average the age of patients admitted to the hospital is 35.37 years. Mode is less than the Mean.

Question 2.
The following data gives the information on the observed lifetimes (in hours) of 225 electrical components:

Determine the modal lifetimes of the components.
Answer:

Since the maximum frequency 61 is in the class 60 – 80, this is the required modal class.
Modal class frequency, f₁ = 61.
Frequency of the class preceding the modal class f₀ = 52
Frequency of the class succeeding the modal class f₂ = 38
Lower boundary of the modal class, l = 60
Height of the class, h = 20
∴ Mode (Z) = 𝑙+(𝑓1−𝑓0)2𝑓1−𝑓0−𝑓2×ℎ
=60+[61−522×61−(52+38)]×20
= 60 + 9122−90 × 20
= 60 + 932 × 20
= 60 + 5.625
= 65.625 hours.

Question 3.
The following data gives the distribution of total monthly household expenditure of 200 families of a village. Find the modal monthly expenditure of the families. Also, find the mean monthly expenditure:

Answer:

Since the maximum families 40 lies in the class 1500 – 2000, this is the required modal class.
Lower boundary of the modal class (l) = 1500
Frequency of the modal class (f₁) = 40
Frequency of the class preceding the modal class f₀ = 24
Frequency of the class succeeding the modal class f₂ = 33
Height of the class, h = 500
Hence, modal monthly income = Rs. 1847.83.
Assumed mean (a) = 3250
∑f_i = 200, ∑u_if_i = -235
Mean monthly income = x⎯⎯⎯=a+ΣfiuiΣfi×h
= 3250 – 235200 × 500
= 3250 – 587.5
= Rs. 2662.50

Question 4.
The following distribution gives the state-wise, teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures.

Answer:

Since the maximum number of states ‘10’ lies in the class interval 30-35, this is the modal class.
Lower boundary of the modal class, l = 30
Frequency of the modal class, f₁ = 10
Frequency of the class preceding the modal class=f₀ = 9
Frequency of the class succeeding the modal class=f₂ = 3
Height of the class, h = 5
∴ Mode (Z) = 𝑙+(f1−f0(f1−f0)+(f1−f2))×h
=30+10−9(10−9)+(10−3)×5
= 30 + 1×51+7
= 30 + 58
= 30 + 0.625
= 30.625
Mean x⎯⎯⎯=a+ΣfiuiΣfi×h
a = assumed mean = 32.5; h = height of the class=5
∴ x = 32.5 – 2335 × 5
= 32.5 – 3.28
= 29.22
Mean = 30.625
Mode = 29.22
Mode states have a students – teacher ratio 29.22 and on an average this ratio is 30.625.

Question 5.
The given distribution shows the number of runs scored by some top batsmen of the world in one-day international cricket matches.

Find the mode of the data.
Answer:

Maximum number of batsmen are in the class 4000 – 5000.
∴ Modal class is 4000 – 5000.
Lower boundary of the modal class ‘l’ = 4000
Frequency of the modal class, f₁ = 18
Frequency of the class preceding the modal class, f₀ = 4
Frequency of the class succeeding the modal class, f₂ = 9
Height of the class, h = 1000
Mode (Z) = 𝑙+(f1−f0(f1−f0)+(f1−f2))×h
Mode (Z) = 4000+18−4(18−4)+(18−9)×1000
= 4000 + 1414+9 × 1000
= 4000 + 1400023
= 4000 + 608.695
= 4608.69
≃ 4608.7 runs

Question 6.
A student noted the number of cars passing through a spot on a road for 100 periods, each of 3 minutes, and summarised this in the table given below.

Find the mode of the data.
Answer:

Since the maximum frequency is 20, the modal class is 40 – 50.
Lower boundary of the modal class ‘l’ = 40
Frequency of the modal class, f₁ = 20
Frequency of the class preceding the modal class, f₀ = 12
Frequency of the class succeeding the modal class, f₂ = 11
Height of the class, h = 10;
Mode (Z) = 𝑙+(f1−f0(f1−f0)+(f1−f2))×h
Mode (Z) = 40+(20−12)(20−12)+(20−11)×10
= 40 + 88+9 × 10
= 40 + 8017
= 40 + 4.70588
= 44.705
≃ 44.7 cars

AP Board Textbook Solutions PDF for Class 10th Maths

AP Board Class 10 Maths Chapter 1 Real Numbers Textbook Solutions PDF

AP Board Class 10 Maths Chapter 2 Sets Textbook Solutions PDF

AP Board Class 10 Maths Chapter 3 Polynomials Textbook Solutions PDF

AP Board Class 10 Maths Chapter 4 Pair of Linear Equations in Two Variables Textbook Solutions PDF

AP Board Class 10 Maths Chapter 5 Quadratic Equations Textbook Solutions PDF

AP Board Class 10 Maths Chapter 6 Progressions Textbook Solutions PDF

AP Board Class 10 Maths Chapter 7 Coordinate Geometry Textbook Solutions PDF

AP Board Class 10 Maths Chapter 8 Similar Triangles Textbook Solutions PDF

AP Board Class 10 Maths Chapter 9 Tangents and Secants to a Circle Textbook Solutions PDF

AP Board Class 10 Maths Chapter 10 Mensuration Textbook Solutions PDF

AP Board Class 10 Maths Chapter 11 Trigonometry Textbook Solutions PDF

AP Board Class 10 Maths Chapter 12 Applications of Trigonometry Textbook Solutions PDF

AP Board Class 10 Maths Chapter 13 Probability Textbook Solutions PDF

AP Board Class 10 Maths Chapter 14 Statistics Textbook Solutions PDF

Andhra Pradesh Board Class 10th Maths Chapter 14 Statistics Ex 14.2 Textbooks for Exam Preparations

Andhra Pradesh Board Class 10th Maths Chapter 14 Statistics Ex 14.2 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 10th Maths Chapter 14 Statistics Ex 14.2 exam preparation. The AP Board STD 10th Maths Chapter 14 Statistics Ex 14.2 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 10th Maths Chapter 14 Statistics Ex 14.2 Books State Board syllabus with maximum efficiency.

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Thursday, June 9, 2022