# HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

## AP Board Class 10 Maths Chapter 11 Trigonometry Ex 11.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 11 Trigonometry Ex 11.2 Book Answers

 AP Board Class 10 Maths Chapter 11 Trigonometry Ex 11.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 11 Trigonometry Ex 11.2 Book Answers

## Andhra Pradesh State Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2 Books Solutions

 Board AP Board Materials Textbook Solutions/Guide Format DOC/PDF Class 10th Subject Maths Chapters Maths Chapter 11 Trigonometry Ex 11.2 Provider Hsslive

2. Click on the Andhra Pradesh Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2 Answers.
3. Look for your Andhra Pradesh Board STD 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbooks PDF.

## AP Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbooks Solutions with Answer PDF Download

Find below the list of all AP Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbook Solutions for PDF’s for you to download and prepare for the upcoming exams:

### 10th Class Maths 11th Lesson Trigonometry Ex 11.2 Textbook Questions and Answers

Question 1.
Evaluate the following.
i) sin 45° + cos 45°
sin 45° + cos 45°
= 12√ + 12√
= 1+12√
= 22√
= 2√×2√2√
= √2

ii)

iii)

iv) 2 tan2 45° + cos2 30° – sin2 60°
2 tan2 45° + cos2 30° – sin2 60°
= 2(1)2 + (3√2)2 – (3√2)2
= 21 + 34 – 34
= 8+3−34
= 84
= 2

v)

Question 2.
Choose the right option and justify your choice.
i) 2tan30∘1+tan245∘
a) sin 60°
b) cos 60°
c) tan 30°
d) sin 30°

ii) 1−tan245∘1+tan245∘
a) tan 90°
b) 1
c) sin 45°
d) 0
1−tan245∘1+tan245∘ = 1−(1)21+(1)2
= 01+1 = 02 = 0

iii) 2tan30∘1−tan230∘
a) cos 60°
b) sin 60°
c) tan 60°
d) sin 30°

Question 3.
Evaluate sin 60° cos 30° + sin 30° cos 60°. What is the value of sin (60° + 30°). What can you conclude?
Take sin 60°.cos 30° + sin 30°.cos 60°
= 3√2 . 3√2 + 12 . 12
= (3√)24 + 14
= 34 + 14
= 3+14
= 44 = 1 …… (1)
Now take sin (60° + 30°)
= sin 90° = 1 …….. (2)
From equations (1) and (2), I conclude that
sin (60°+30°) = sin 60° . cos 30° + sin 30° . cos 60°.
i.e., sin (A + B) = sin A . cos B + cos A . sin B

Question 4.
Is it right to say cos (60° + 30°) = cos 60° cos 30° – sin 60° sin 30° ?
L.H.S. = cos (60° + 30°)
cos 90° = 0
R.H.S. = cos 60° . cos 30° – sin 60° . sin 30°.
= 12 . 3√2 – 3√2 . 12
= 3√4 – 3√4 = 0
∴ L.H.S = R.H.S
Yes, it is right to say
cos (60°+30°) = cos 60° . cos 30° – sin 60° . sin 30°.
i.e., cos (A + B) = cos A . cos B – sin A . sin B

Question 5.
In right angle triangle △PQR, right angle is at Q and PQ = 6 cms, ∠RPQ = 60°. Determine the lengths of QR and PR.
Given that △PQR is a right angled triangle, right angle is at Q and PQ = 6 cm, ∠RPQ = 60°.

tan 60° =  Opposite side to ∠𝑃 Adjacent side to ∠𝑃
√3 = 𝑅𝑄6
which gives RQ = 6√3 cm ……. (1)
To find the length of the side RQ, we consider

∴ The length of QR is 6√3 and RP is 12 cm.

Question 6.
In △XYZ, right angle is at Y, YZ = x, and XY = 2x then determine ∠YXZ and ∠YZX.
Note: In the problem take
YX = x, and XZ = 2x.

Given that △XYZ is a right angled triangle and right angle at Y, and YX = x and XZ = 2x.
By Pythagoras theorem
XZ2 = XY2 + YZ2
(2x)2 = (x)2 + YZ2
4x2 = x2 + YZ2
YZ2 = 4x2 – x2 = 3x2
YZ = 3𝑥2‾‾‾‾√ = √3x
Now, from the △XYZ
tan X = 𝑋𝑍𝑋𝑌 = 3√𝑥𝑥
tan X = √3 = tan 60°
∴ Angle YXZ is 60°.
tan Z = 𝑋𝑌𝑌𝑍 = 𝑥3√𝑥
tan Z = 13√ = tan 30°
∴ Angle YZX is 30°.
Hence ∠YXZ and ∠YZX are 60° and 30°.

Question 7.
Is it right to say that
sin (A + B) = sin A + sin B? Justify your answer.
Let A = 30° and B = 60°
L.H.S = sin (A + B)
= sin (30° + 60°) = sin 90° = 1
R.H.S = sin 30° + sin 60°
= 12 + 3√2
= 3√+12
Hence L.H.S ≠ R.H.S
So, it is not right to say that sin (A + B) = sin A + sin B

## Andhra Pradesh Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbooks for Exam Preparations

Andhra Pradesh Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2 exam preparation. The AP Board STD 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 10th Maths Chapter 11 Trigonometry Ex 11.2 Books State Board syllabus with maximum efficiency.

## FAQs Regarding Andhra Pradesh Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbook Solutions

#### Can we get a Andhra Pradesh State Board Book PDF for all Classes?

Yes you can get Andhra Pradesh Board Text Book PDF for all classes using the links provided in the above article.

## Important Terms

Andhra Pradesh Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2, AP Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbooks, Andhra Pradesh State Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2, Andhra Pradesh State Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbook solutions, AP Board Class 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbooks Solutions, Andhra Pradesh Board STD 10th Maths Chapter 11 Trigonometry Ex 11.2, AP Board STD 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbooks, Andhra Pradesh State Board STD 10th Maths Chapter 11 Trigonometry Ex 11.2, Andhra Pradesh State Board STD 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbook solutions, AP Board STD 10th Maths Chapter 11 Trigonometry Ex 11.2 Textbooks Solutions,
Share: