AP Board Class 10 Maths Chapter 10 Mensuration Ex 10.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 10 Mensuration Ex 10.2 Book Answers ~ HSSlive: Plus One & Plus Two Notes & Solutions for Kerala State Board

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AP Board Class 10 Maths Chapter 10 Mensuration Ex 10.2 Textbook Solutions PDF: Download Andhra Pradesh Board STD 10th Maths Chapter 10 Mensuration Ex 10.2 Book Answers

AP Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 Textbooks Solutions and answers for students are now available in pdf format. Andhra Pradesh Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 Book answers and solutions are one of the most important study materials for any student. The Andhra Pradesh State Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 books are published by the Andhra Pradesh Board Publishers. These Andhra Pradesh Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 textbooks are prepared by a group of expert faculty members. Students can download these AP Board STD 10th Maths Chapter 10 Mensuration Ex 10.2 book solutions pdf online from this page.

Andhra Pradesh Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 Textbooks Solutions PDF

Andhra Pradesh State Board STD 10th Maths Chapter 10 Mensuration Ex 10.2 Books Solutions with Answers are prepared and published by the Andhra Pradesh Board Publishers. It is an autonomous organization to advise and assist qualitative improvements in school education. If you are in search of AP Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 Books Answers Solutions, then you are in the right place. Here is a complete hub of Andhra Pradesh State Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 solutions that are available here for free PDF downloads to help students for their adequate preparation. You can find all the subjects of Andhra Pradesh Board STD 10th Maths Chapter 10 Mensuration Ex 10.2 Textbooks. These Andhra Pradesh State Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 Textbooks Solutions English PDF will be helpful for effective education, and a maximum number of questions in exams are chosen from Andhra Pradesh Board.

Andhra Pradesh State Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 Books Solutions

Board	AP Board
Materials	Textbook Solutions/Guide
Format	DOC/PDF
Class	10th
Subject	Maths
Chapters	Maths Chapter 10 Mensuration Ex 10.2
Provider	Hsslive

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AP Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 Textbooks Solutions with Answer PDF Download

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10th Class Maths 10th Lesson Mensuration Ex 10.2 Textbook Questions and Answers

Question 1.
A toy is in the form of a cone mounted on a hemisphere. The diameter of the base and the height of the cone are 6 cm and 4 cm respectively. Determine the surface area of the toy. (Use π = 3.14)
Answer:

Diameter of the base of the cone d = 6 cm.
∴ Radius of the base of the cone
r = 𝑑2 = 62 = 3 cm
Height of the cone = h = 4 cm
Slant height of the cone l = 𝑟2+ℎ2‾‾‾‾‾‾‾√
= 32+42‾‾‾‾‾‾‾√
= 9+16‾‾‾‾‾‾√
= √25
= 5 cm
∴ C.S.A of the cone = πrl
= 227 × 3 × 5
= 3307 cm²
Radius of the hemisphere = 𝑑2 = 62 = 3 cm
C.S.A. of the hemisphere = 2πr²
= 2 × 227 × 3 × 3
= 3967
Hence the surface area of the toy = C.S.A. of cone + C.S.A. of hemisphere
= 3307 + 3967
= 7267 ≃ 103.71 cm².

Question 2.
A solid is in the form of a right circular cylinder with a hemisphere at one end and a cone at the other end. The radius of the common base is 8 cm and the heights of the cylindrical and conical portions are 10 cm and 6 cm respectively. Find the total surface area of the solid. [Use π = 3.14]
Answer:
Total surface area = C.S.A. of the cone + C.S.A. of cylinder + C.S.A of the hemisphere.

Cone:
Radius (r) = 8 cm
Height (h) = 6 cm
Slant height l = 𝑟2+ℎ2‾‾‾‾‾‾‾√
= 82+62‾‾‾‾‾‾‾√
= 64+36‾‾‾‾‾‾‾√
= √100
= 10 cm
C.S.A. = πrl
= 227 × 8 × 10
= 17607 cm²
Cylinder:
Radius (r) = 8 cm;
Height (h) = 10 cm
C.S.A. = 2πrh
= 2 × 227 × 8 × 10
= 35207 cm²
Hemisphere:
Radius (r) = 8 cm
C.S.A. = 2πr²
= 2 × 227 × 8 × 8
= 28167 cm²
∴ Total surface area of the given solid
= 17607 + 35207 + 28167
T.S.A. = 80967 = 1156.57 cm².

Question 3.
A medicine capsule is ih the shape of a cylinder with two hemispheres stuck to each of its ends. The length of the capsule is 14 mm. and the width is 5 mm. Find its surface area.
Answer:

Surface area of the capsule = C.S.A. of 2 hemispheres + C.S.A. of the cylinder
i) Now for Hemisphere:
Radius (r) = 𝑑2 = 52 = 2.5 mm
C.S.A of each hemisphere = 2πr²
C.S.A of two hemispheres
= 2 × 2πr² = 4πr²
= 2 × 227 × 52 × 52
= 5507
= 78.57 mm².

ii) Now for Cylinder:
Length of capsule = AB =14 mm
Then height (length) cylinder part = 14 – 2(2.5)
h = 14 – 5 = 9 mm
Radius of cylinder part (r) = 52
Now C.S.A of cylinder part = 2πrh
= 2 × 227 × 52 × 9
= 9007
= 141.428 mm²
Now total surface area of capsule
= 78.57 + 141.43 = 220 mm²

Question 4.
Two cubes each of volume 64 cm³ are joined end to end together. Find the surface area of the resulting cuboid.
Answer:
Given, volume of the cube.
V = a³ = 64 cm³
∴ a³ = 4 × 4 × 4 = 4³ , Hence a = 4 cm
When two cubes are added, the length of cuboid = 2a = 2 × 4 = 8 cm,
breadth = a = 4 cm.
height = a = 4 cm is formed.

∴ T.S.A. of the cuboid
= 2 (lb + bh + lh)
= 2(8 × 4 + 4 × 4 + 8 × 4)
= 2(32 + 16 + 32)
= 2 × 80
= 160 cm²
∴ The surface area of resulting cuboid is 160 cm².

Question 5.
A storage tank consists of a circular cylinder with a hemisphere stuck on either end. If the external diameter of the cylinder be 1.4 m. and its length be 8 m. Find the cost of painting it on the outside at rate of Rs. 20 per m².
Answer:
Total surface area of the tank = 2 × C.S.A. of hemisphere + C.S.A. of cylinder.

Hemisphere:
Radius (r) = 𝑑2 = 1.42 = 0.7 m
C.S.A. of hemisphere = 2πr²
= 2 × 227 × 0.7 × 0.7
= 3.08 m².
2 × C.S.A. = 2 × 3.08 m² = 6.16 m²
Cylinder:
Radius (r) = 𝑑2 = 1.42 = 0.7 m
Height (h) = 8 m
C.S.A. of the cylinder = 2πrh
= 2 × 227 × 0.7 × 8
= 35.2 m²
∴ Total surface area of the storage tank = 35.2 + 6.16 = 41.36 m²
Cost of painting its surface area @ Rs. 20 per sq.m, is
= 41.36 × 20 = Rs. 827.2.

Question 6.
A hemisphere is cut out from one face of a cubical wooden block such that the diameter of the hemisphere is equal to the length of the cube. Determine the surface area of the remaining solid.
Answer:
Let the length of the edge of the cube = a units

T.S.A. of the given solid = 5 × Area of each surface + Area of hemisphere
Square surface:
Side = a units
Area = a² sq. units
5 × square surface = 5a² sq. units
Hemisphere:
Diameter = a units;
Radius = 𝑎2
C.S.A. = 2πr²
= 2π(𝑎2)2
= 2π𝑎24 = 𝜋a22 sq. units
Total surface area = 5a² + 𝜋a22 = a²(5+𝜋2) sq. units.

Question 7.
A wooden article was made by scooping out a hemisphere from each end of a solid cylinder, as shown in the figure. If the height of the cylinder is 10 cm and its base radius is of 3.5 cm, find the total surface area of the article.

Answer:
Surface area of the given solid = C.S.A. of the cylinder + 2 × C.S.A. of hemisphere.
If we take base = radius
Cylinder:
Radius (r) = 3.5 cm
Height (h) = 10 cm
C.S.A. = 2πrh
= 2 × 227 × 3.5 × 10
= 220 cm²
Hemisphere:
Radius (r) = 3.5 cm
C.S.A. = 2πr²
= 2 × 227 × 3.5 × 3.5
= 77 cm²
2 × C.S.A. = 2 × 77 = 154 cm²
∴ T.S.A. = 220 + 154 = 374 cm².

AP Board Textbook Solutions PDF for Class 10th Maths

AP Board Class 10 Maths Chapter 1 Real Numbers Textbook Solutions PDF

AP Board Class 10 Maths Chapter 2 Sets Textbook Solutions PDF

AP Board Class 10 Maths Chapter 3 Polynomials Textbook Solutions PDF

AP Board Class 10 Maths Chapter 4 Pair of Linear Equations in Two Variables Textbook Solutions PDF

AP Board Class 10 Maths Chapter 5 Quadratic Equations Textbook Solutions PDF

AP Board Class 10 Maths Chapter 6 Progressions Textbook Solutions PDF

AP Board Class 10 Maths Chapter 7 Coordinate Geometry Textbook Solutions PDF

AP Board Class 10 Maths Chapter 8 Similar Triangles Textbook Solutions PDF

AP Board Class 10 Maths Chapter 9 Tangents and Secants to a Circle Textbook Solutions PDF

AP Board Class 10 Maths Chapter 10 Mensuration Textbook Solutions PDF

AP Board Class 10 Maths Chapter 11 Trigonometry Textbook Solutions PDF

AP Board Class 10 Maths Chapter 12 Applications of Trigonometry Textbook Solutions PDF

AP Board Class 10 Maths Chapter 13 Probability Textbook Solutions PDF

AP Board Class 10 Maths Chapter 14 Statistics Textbook Solutions PDF

Andhra Pradesh Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 Textbooks for Exam Preparations

Andhra Pradesh Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 Textbook Solutions can be of great help in your Andhra Pradesh Board Class 10th Maths Chapter 10 Mensuration Ex 10.2 exam preparation. The AP Board STD 10th Maths Chapter 10 Mensuration Ex 10.2 Textbooks study material, used with the English medium textbooks, can help you complete the entire Class 10th Maths Chapter 10 Mensuration Ex 10.2 Books State Board syllabus with maximum efficiency.

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Thursday, June 9, 2022